Problem 59
Question
Write expression in terms of sine and cosine, and simplify it. (The final expression does not have to be in terms of sine and cosine.) $$\csc \theta \sec \theta \tan \theta$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \sec^2 \theta \).
1Step 1: Express all trigonometric functions in terms of sine and cosine
Begin by expressing each of the trigonometric functions \( \csc \theta \), \( \sec \theta \), and \( \tan \theta \) in terms of \( \sin \theta \) and \( \cos \theta \). \[ \csc \theta = \frac{1}{\sin \theta}, \quad \sec \theta = \frac{1}{\cos \theta}, \quad \text{and} \quad \tan \theta = \frac{\sin \theta}{\cos \theta}. \] This yields the expression \[ \frac{1}{\sin \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\sin \theta}{\cos \theta}. \]
2Step 2: Simplify the expression
Now simplify the expression by multiplying all terms: \[ \frac{1}{\sin \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\sin \theta}{\cos \theta} = \frac{\sin \theta}{\sin \theta \cos^2 \theta}. \] The \( \sin \theta \) in the numerator and denominator cancel out, leaving \[ \frac{1}{\cos^2 \theta}. \]
3Step 3: Utilize identity to further simplify
Recognize that \( \frac{1}{\cos^2 \theta} \) is equivalent to the trigonometric identity \( \sec^2 \theta \). Thus, the simplified expression is \( \sec^2 \theta \).
Key Concepts
Sine and Cosine FunctionsTrigonometric IdentitiesStep-by-Step Solution
Sine and Cosine Functions
Trigonometric functions are fundamental in mathematics, particularly in the study of triangles and waves. At the core of these functions lie the sine and cosine functions. The sine function, denoted as \( \sin \theta \), is a ratio comparing the opposite side to the hypotenuse in a right-angled triangle. Conversely, the cosine function, known as \( \cos \theta \), compares the adjacent side to the hypotenuse. These relationships are pivotal because they allow us to express other trigonometric functions. For instance:
- The cosecant function (\( \csc \theta \)) is the reciprocal of sine: \( \csc \theta = \frac{1}{\sin \theta} \).
- The secant function (\( \sec \theta \)) is the reciprocal of cosine: \( \sec \theta = \frac{1}{\cos \theta} \).
- The tangent function (\( \tan \theta \)) is the ratio of sine to cosine: \( \tan \theta = \frac{\sin \theta}{\cos \theta} \).
Trigonometric Identities
Trigonometric identities are equations involving trigonometric functions that hold true for all values of the variable involved, assuming the expression is defined. These identities play a significant role in simplifying and solving trigonometric expressions or equations.One crucial identity is the Pythagorean Identity:\[\sin^2 \theta + \cos^2 \theta = 1\]From which we derive other identities:
- \( \sec^2 \theta = 1 + \tan^2 \theta \)
- \( \csc^2 \theta = 1 + \cot^2 \theta \)
Step-by-Step Solution
Understanding the process of simplification is crucial. Let's revisit the step-by-step method used in solving the given exercise to ensure clarity.**Step 1: Conversion to Sine and Cosine**
Transform the original expression \( \csc \theta \sec \theta \tan \theta \) into terms of sine and cosine using the definitions:
Multiply the terms:\[ \frac{1}{\sin \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\sin \theta}{\cos \theta} = \frac{\sin \theta}{\sin \theta \cos^2 \theta} \]Cancel \( \sin \theta \) from the numerator and denominator:\[ \frac{1}{\cos^2 \theta} \]**Step 3: Using Trigonometric Identity**
Recognize the result as a trigonometric identity, \( \sec^2 \theta \). Thus, simplifying \( \csc \theta \sec \theta \tan \theta \) requires changing functions, multiplying, and applying the identity for efficient results. This methodical approach showcases the importance of understanding each function and identity in trigonometry.
Transform the original expression \( \csc \theta \sec \theta \tan \theta \) into terms of sine and cosine using the definitions:
- \( \csc \theta = \frac{1}{\sin \theta} \)
- \( \sec \theta = \frac{1}{\cos \theta} \)
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
Multiply the terms:\[ \frac{1}{\sin \theta} \cdot \frac{1}{\cos \theta} \cdot \frac{\sin \theta}{\cos \theta} = \frac{\sin \theta}{\sin \theta \cos^2 \theta} \]Cancel \( \sin \theta \) from the numerator and denominator:\[ \frac{1}{\cos^2 \theta} \]**Step 3: Using Trigonometric Identity**
Recognize the result as a trigonometric identity, \( \sec^2 \theta \). Thus, simplifying \( \csc \theta \sec \theta \tan \theta \) requires changing functions, multiplying, and applying the identity for efficient results. This methodical approach showcases the importance of understanding each function and identity in trigonometry.
Other exercises in this chapter
Problem 59
Verify that each equation is an identity. $$\frac{\sin (x-y)}{\sin (x+y)}=\frac{\tan x-\tan y}{\tan x+\tan y}$$
View solution Problem 59
Verify that each equation is an identity. $$\frac{2 \cos 2 \alpha}{\sin 2 \alpha}=\cot \alpha-\tan \alpha$$
View solution Problem 60
Verify that each equation is an identity. $$\frac{\cos (A-B)}{\sin (A+B)}=\frac{1+\cot A \cot B}{\cot A+\cot B}$$
View solution Problem 60
Draw by hand the graph of each inverse function. $$y=\csc ^{-1} x$$
View solution