Problem 59
Question
The equation of the system of coaxal circles that are tangent at \((\sqrt{2}, 4)\) to the locus of the point of intersection of mutually \(\perp\) tangents to the circle \(x^{2}+y^{2}=9\), is (A) \(\left(x^{2}+y^{2}-18\right)+\lambda(\sqrt{2} x+4 y-18)=0\) (B) \(\left(x^{2}+y^{2}-18\right)+\lambda(4 x+\sqrt{2 y}-18)=0\) (C) \(\left(x^{2}+y^{2}-16\right)+\lambda(\sqrt{2 x}+4 y-16)=0\) (D) none of these
Step-by-Step Solution
Verified Answer
(A) \((x^2 + y^2 - 18) + \lambda(\sqrt{2} x + 4 y - 18) = 0\)."
1Step 1: Understand the given circle
The given circle equation is \(x^2 + y^2 = 9\), which represents a circle with center \((0,0)\) and radius \(3\).
2Step 2: Determine the locus of intersection of perpendicular tangents
The locus of the intersection of mutually perpendicular tangents to a circle is a circle with the same center and twice the radius. Thus, the locus is \(x^2 + y^2 = 18\).
3Step 3: Equation of coaxal circles
Coaxial circles with a fixed circle \(x^2 + y^2 = 18\) have the equation \((x^2 + y^2 - 18) + \lambda(L) = 0\), where \(L\) is a line.
4Step 4: Line condition for tangency at a point
For the circles to be tangent at \((\sqrt{2}, 4)\), substituting this point into \(L\) gives the line equation: \(\sqrt{2}x + 4y = 18\).
5Step 5: Construct the final equation
Using the form from Step 3 and the line \(L = \sqrt{2}x + 4y - 18\), the equation becomes \((x^2 + y^2 - 18) + \lambda(\sqrt{2} x + 4 y - 18) = 0\).
Key Concepts
Locus of IntersectionEquation of CircleTangent to a CircleMutually Perpendicular Tangents
Locus of Intersection
The concept of a locus refers to a set of points that satisfy a certain condition. In the context of circles, the locus of the intersection of mutually perpendicular tangents is particularly interesting. Given a circle with equation \(x^2 + y^2 = 9\), its center is at the origin \((0, 0)\) and it has a radius of 3. When exploring the locus of points formed by the intersection of tangents that meet at right angles, it helps to remember that these points create a new circle. This circle shares the same center as the original circle but its radius is doubled. Thus, the locus of intersection for tangents perpendicular to a circle with radius 3 is a larger circle with radius 6. Therefore, the equation becomes \(x^2 + y^2 = 18\).
This transformation reveals how tangents can define a new geometric space, capturing not only the presence of the original circle but also extending beyond it.
This transformation reveals how tangents can define a new geometric space, capturing not only the presence of the original circle but also extending beyond it.
Equation of Circle
The equation of a circle is a fundamental concept in geometry and is essential for understanding circles' properties and relationships. Typically, a circle centered at \((h, k)\) with radius \(r\) is represented by \((x - h)^2 + (y - k)^2 = r^2\). In simpler terms, every point \((x, y)\) on the circle is at a distance \(r\) from the center.
In our exercise, we have the circle \(x^2 + y^2 = 18\), indicating a center at \((0,0)\) with a radius of 6. Coaxial circles, like those described in the problem, share a common axis—in this case, they share the same center. Their general equation takes the form \((x^2 + y^2 - 18) + \lambda L = 0\), where \(L\) is a linear element.
In our exercise, we have the circle \(x^2 + y^2 = 18\), indicating a center at \((0,0)\) with a radius of 6. Coaxial circles, like those described in the problem, share a common axis—in this case, they share the same center. Their general equation takes the form \((x^2 + y^2 - 18) + \lambda L = 0\), where \(L\) is a linear element.
Tangent to a Circle
A tangent to a circle is a line that just "touches" the circle at exactly one point, providing a way to explore and define further geometric properties. In our context, when the problem specifies tangency at \((\sqrt{2}, 4)\), it dictates specific conditions for possible lines.
- These lines do not penetrate the circle, ensuring only one point of contact.
- They create a perpendicular radius at the point of contact, visible in special scenarios such as mutually perpendicular tangents.
Mutually Perpendicular Tangents
In mathematics, when we talk about mutually perpendicular tangents, we're referring to two tangents that meet the circle at right angles, intersecting at an external point. This concept has a broader implication as it helps define a new circle encompassing said path of external points.
From our problem, the provided circle \(x^2 + y^2 = 9\) with center \((0,0)\) sees this intersection locus defined as another circle with larger radius - a shift intrinsic to all mutually perpendicular tangents. Visualizing this can be insightful:
From our problem, the provided circle \(x^2 + y^2 = 9\) with center \((0,0)\) sees this intersection locus defined as another circle with larger radius - a shift intrinsic to all mutually perpendicular tangents. Visualizing this can be insightful:
- Perpendicular tangents define a diameter of sorts, with intersections forming a locus twice the radius of the original circle.
- This geometric approach facilitates defining new circle equations - linking mutual perpendicularity to coaxial circle systems.
Other exercises in this chapter
Problem 55
If a circle passes through the points of intersection of the coordinate axes with the lines \(\lambda x-y+1=0\) and \(x-2 y+3=0\), then the value of \(\lambda\)
View solution Problem 56
A circle touches the line \(y=x\) at \(a\) point \(P\) such that \(O P=4 \sqrt{2}\), where \(O\) is the origin. The circle contains the point \((-10,2)\) in its
View solution Problem 60
The point on the straight line \(y=2 x+11\) which is nearest to the circle \(16\left(x^{2}+y^{2}\right)+32 x-8 y-50=0\) is (A) \(\left(\frac{9}{2}, 2\right)\) (
View solution Problem 61
Extremities of a diagonal of a rectangle are \((0,0)\) and \((4,3)\). The equations of the tangents to the circumcircle of the rectangle which are parallel to t
View solution