Problem 59
Question
Let \(f(x)=\left\\{\begin{array}{ll}|x|, & 0<|x| \leq 2 \\ 1, & x=0\end{array}\right.\). Then, at \(x=0, f\) has (A) a local maximum (B) no local maximum (C) a local minimum (D) no extremum
Step-by-Step Solution
Verified Answer
(A) a local maximum
1Step 1: Understand the Function
The function is defined piecewise which means it behaves differently at different intervals. It uses the absolute value of \(x\) for \(0 < |x| \leq 2\) and a constant value of 1 at \(x = 0\). This tells us how \(f(x)\) is structured around \(x = 0\).
2Step 2: Analyze Around x=0
For values very close to \(x = 0\), but not equal to zero, \(f(x) = |x|\). By evaluating the function as \(x\) approaches 0 from both the positive and negative directions, we get \(f(x) = |x| \to 0\). At \(x=0\), the function takes the value \(f(x)=1\).
3Step 3: Determine Local Extrema
A local maximum or minimum at \(x=0\) would involve \(f(x)\) being larger or smaller than \(f(x)\) for values closely surrounding \(x=0\). Specifically, for a local maximum at \(x=0\), we would need \(f(0) \geq f(x)\) for values near 0, but since \(f(x)\to 0\) as \(x\to 0\), \(f(0)=1\) is indeed larger than \(f(x)\) near \(x=0\). Thus \(x=0\) is a local maximum point.
Key Concepts
Local MaximumAbsolute Value FunctionFunction Analysis
Local Maximum
In mathematical terms, a local maximum occurs at a point if the function value at that point is greater than or equal to values at points in a nearby interval. When analyzing piecewise functions, identifying a local maximum is crucial because it determines where a function reaches a peak within a localized region.
For the given piecewise function, check values around a specific point, such as at the origin in this function. At \(x = 0\), the function \(f(x)\) takes the value 1. If we compare this to values just surrounding \(x = 0\), the function \(f(x) = |x|\) moves towards zero as \(x\) approaches zero from both sides. Hence, \(f(0) = 1\) indeed forms a peak relative to these surrounding values.
Therefore, the function does have a local maximum at \(x = 0\). To summarize, if a function climbs to a higher point at a specific spot than nearby points, that spot is termed as a local maximum in mathematical parlance.
For the given piecewise function, check values around a specific point, such as at the origin in this function. At \(x = 0\), the function \(f(x)\) takes the value 1. If we compare this to values just surrounding \(x = 0\), the function \(f(x) = |x|\) moves towards zero as \(x\) approaches zero from both sides. Hence, \(f(0) = 1\) indeed forms a peak relative to these surrounding values.
Therefore, the function does have a local maximum at \(x = 0\). To summarize, if a function climbs to a higher point at a specific spot than nearby points, that spot is termed as a local maximum in mathematical parlance.
Absolute Value Function
The absolute value of a number represents its distance from zero on the number line without considering its direction. In algebra, the absolute value function is denoted by \(|x|\). This function transforms any negative value to a positive and keeps positive values intact.
For instance, the absolute value of -3 is 3, written as \(|-3| = 3\). Thus, absolute value functions create V-shaped graphs when plotted, with a sharp point located at the origin. In our problem, this shape directly impacts how solutions form and behave around specific points.
For instance, the absolute value of -3 is 3, written as \(|-3| = 3\). Thus, absolute value functions create V-shaped graphs when plotted, with a sharp point located at the origin. In our problem, this shape directly impacts how solutions form and behave around specific points.
- The expression \(f(x) = |x|\) for \(0 < |x| \leq 2\) implies the function reflects over the y-axis, retaining positive values.
- Such functions are continuous and have non-negative outputs, essential when evaluating limits and behaviors, especially around crucial points like \(x = 0\).
Function Analysis
Function analysis involves examining how different parts of a function behave, especially across distinct intervals. With piecewise functions, each segment represents a unique formula defining the function behavior over particular ranges.
For this function analysis, you need to observe intervals individually. The behavior of the function at \(0 < |x| \leq 2\) utilizes \(|x|\), indicating linear but symmetric growth on either side of \(x\).
Through function analysis, gain insight into how each part contributes to the overall structure, helping identify specific points of interest like local maxima or minima.
For this function analysis, you need to observe intervals individually. The behavior of the function at \(0 < |x| \leq 2\) utilizes \(|x|\), indicating linear but symmetric growth on either side of \(x\).
- First, understand that for \(0 < |x| \leq 2\), the function follows a symmetric path as \(x\) approaches zero from positive or negative directions.
- Secondly, analyze the behavior at the pivotal \(x = 0\), where the function deviates to a constant value of 1, altering its behavior and signifying a local extremum.
Through function analysis, gain insight into how each part contributes to the overall structure, helping identify specific points of interest like local maxima or minima.
Other exercises in this chapter
Problem 56
Let \(f:[2,7] \rightarrow[0, \infty)\) be a continuous and differentiable function. Then, \((f(7)-f(2)) \frac{\left(f(7)^{2}+(f(2))^{2}+f(2) f(7)\right.}{3}\) i
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If the equation \(a_{n} x^{n}+a_{n-1} x^{n-1}+\ldots+a_{1} x=0\) has a positive root \(x=\alpha\), then the equation \(n a_{n} x^{n-1}+(n-1) a_{n-1} x^{n-2}+\ld
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Let \(f\) be a function which is continuous and differentiable for all real \(x\). If \(f(2)=-4\) and \(f^{\prime}(x) \geq 6\) for all \(x \in[2,4]\), then (A)
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