Problem 58
Question
Give an example of irrational numbers a and b such that the indicated expression is (a) rational and (b) irrational. $$a / b$$
Step-by-Step Solution
Verified Answer
Use \(a = \sqrt{2}, b = \sqrt{2}\) for a rational result; and \(a = \sqrt{2}, b = 1\) for an irrational result.
1Step 1: Understanding Rationality and Irrationality
Recall that a rational number is one that can be expressed as the quotient of two integers (i.e., a fraction \( \frac{m}{n} \) with \( n eq 0 \)), while an irrational number cannot be expressed in this form. Examples of irrational numbers include \( \sqrt{2} \), \( \pi \), and others.
2Step 2: Create an Expression with a Rational Result
Choose \( a = \sqrt{2} \) and \( b = \sqrt{2} \). Then, \( \frac{a}{b} = \frac{\sqrt{2}}{\sqrt{2}} = 1 \), which is a rational number.
3Step 3: Create an Expression with an Irrational Result
Choose \( a = \sqrt{2} \) and \( b = 1 \). Then, \( \frac{a}{b} = \frac{\sqrt{2}}{1} = \sqrt{2} \), which is an irrational number.
Key Concepts
Quotient of IntegersIrrational NumbersRational Numbers
Quotient of Integers
Understanding the concept of the quotient of integers is key when dealing with rational numbers. A quotient is the result of dividing one number by another. When discussing quotients of integers, we are referring to two whole numbers being divided to produce a result. This is essential in distinguishing rational numbers.
A rational number is defined as a number that can be expressed as a fraction \( \frac{m}{n} \), where \( m \) and \( n \) are integers and \( n eq 0 \). In simpler terms, a rational number is any number that can be written as a simple fraction. For instance:
A rational number is defined as a number that can be expressed as a fraction \( \frac{m}{n} \), where \( m \) and \( n \) are integers and \( n eq 0 \). In simpler terms, a rational number is any number that can be written as a simple fraction. For instance:
- \( \frac{1}{2} \) is a rational number because both 1 and 2 are integers and 2 is not zero.
- \( \frac{-5}{3} \) is also a rational number.
Irrational Numbers
Irrational numbers are quite fascinating because they cannot be expressed as a simple fraction of integers. This means there are no two integers you can divide to get an irrational number.
Irrational numbers include well-known numbers like:
To think of irrational numbers in another way, consider the diagonal length of a square with side length 1, which is \( \sqrt{2} \). No fraction with whole numbers will exactly equal this figure. That makes \( \sqrt{2} \) an irrational number.
Irrational numbers include well-known numbers like:
- \( \sqrt{2} \)
- \( \pi \)
- \( e \)
To think of irrational numbers in another way, consider the diagonal length of a square with side length 1, which is \( \sqrt{2} \). No fraction with whole numbers will exactly equal this figure. That makes \( \sqrt{2} \) an irrational number.
Rational Numbers
Rational numbers, as previously mentioned, are numbers that can be written as a fraction \( \frac{m}{n} \) where both \( m \) and \( n \) are integers and \( n eq 0 \). This definition allows for a variety of numbers that fulfill these criteria:
- Whole numbers, like 7, as they can be expressed as \( \frac{7}{1} \).
- Negative numbers, such as \( \frac{-8}{3} \).
- Decimals that end, like 0.75, which can be written as \( \frac{3}{4} \).
- Decimals that repeat, such as 0.666..., which is equal to \( \frac{2}{3} \).
Other exercises in this chapter
Problem 58
(a) Verify that the point (3,7) is on the circle $$x^{2}+y^{2}-2 x-6 y-10=0$$ (b) Find the equation of the line tangent to this circle at the point \((3,7) .\)
View solution Problem 58
Solve each equation for \(x\) in terms of the other letters. $$(x-p)^{2}+(x-q)^{2}=p^{2}+q^{2}$$
View solution Problem 59
The set of real numbers satisfying the given inequality is one or more intervals on the number line. Show the interval(s) on a number line. $$|x-5| \geq 2$$
View solution Problem 59
Solve each equation for \(x\) in terms of the other letters. \(a^{2}(a-x)=b^{2}(b+x)-2 a b x,\) where \(a \neq b\)
View solution