Problem 57
Question
Exer. 51-60: Show that the equation is not an identity. (Hint: Find one number for which the equation is false.) $$ \cos (-t)=-\cos t $$
Step-by-Step Solution
Verified Answer
The equation \( \cos(-t) = -\cos(t) \) is not an identity as shown by \( t = 0 \), where it results in \( 1 \neq -1 \).
1Step 1: Understand the Trigonometric Identity
Recall the trigonometric identity for cosine: \( \cos(-t) = \cos(t) \). This tells us that cosine is an even function, which means that the cosine of a negative angle is the same as the cosine of the positive angle.
2Step 2: Evaluate the Given Expression
The given expression is \( \cos(-t) = -\cos(t) \). Based on the identity from Step 1, we know that this equation does not hold for all values of \( t \) because \( \cos(-t) \) should be equal to \( \cos(t) \), not \(-\cos(t) \).
3Step 3: Select a Test Value for t
We need to choose a value of \( t \) for which we can show that \( \cos(-t) eq -\cos(t) \). A simple choice is \( t = 0 \) because it often simplifies trigonometric functions.
4Step 4: Substitute the Test Value into the Equation
Substituting \( t = 0 \) into the left side of the equation, we have \( \cos(-0) = \cos(0) \). Since \( \cos(0) = 1 \), the left side evaluates to 1. On the right side, we have \(-\cos(0) = -1 \). Therefore, \( 1 eq -1 \), showing that the equation \( \cos(-t) = -\cos(t) \) is false for \( t = 0 \).
5Step 5: Conclude the Verification
Since \( t = 0 \) leads to a false statement in the equation \( \cos(-t) = -\cos(t) \), the equation is not an identity, as it does not hold true for all values of \( t \).
Key Concepts
Even FunctionsCosine FunctionVerification of Equations
Even Functions
An even function is a type of mathematical function that maintains symmetry around the y-axis. This means if you were to fold the graph of the function along the y-axis, it would match on both sides. Even functions follow a specific rule where the function evaluated at negative x is equal to the function evaluated at positive x, represented by the formula:
- For any even function: \[ f(-x) = f(x) \]
Cosine Function
The cosine function, one of the fundamental functions in trigonometry, is primarily known for its property of dealing with angles in standard position in the coordinate system. It is derived from the ratio of the adjacent side to the hypotenuse in a right-angled triangle.
One of the distinguishing qualities of the cosine function is that it is an even function. This characteristic is encapsulated in the identity:
One of the distinguishing qualities of the cosine function is that it is an even function. This characteristic is encapsulated in the identity:
- \( \cos(-t) = \cos(t) \)
Verification of Equations
Verification of equations assists in determining whether a given equation is always valid (i.e., an identity) or not. To verify, one selects specific values to substitute into the equation, evaluating if the equation holds true in those instances. When checking trigonometric equations, like the one in the exercise \( \cos(-t) = -\cos(t) \), this process becomes particularly important.
By substituting a simple value, like \( t = 0 \), it's possible to show if the equation remains consistent or false with its expected trigonometric identity. For instance, substituting \( t = 0 \) yields \( \cos(-0) = \cos(0) \), simplifying to 1 on the left side, while the right evaluates to \(-1\), indicating the equation is false. This method reveals that the equation in question is not an identity because it doesn't hold for all values of \( t \). Verification is a key step in assessing trigonometric and algebraic equations, ensuring accuracy and understanding of mathematical properties and functions.
By substituting a simple value, like \( t = 0 \), it's possible to show if the equation remains consistent or false with its expected trigonometric identity. For instance, substituting \( t = 0 \) yields \( \cos(-0) = \cos(0) \), simplifying to 1 on the left side, while the right evaluates to \(-1\), indicating the equation is false. This method reveals that the equation in question is not an identity because it doesn't hold for all values of \( t \). Verification is a key step in assessing trigonometric and algebraic equations, ensuring accuracy and understanding of mathematical properties and functions.
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