Problem 56
Question
Explain why triphenylamine is a much weaker base than benzenamine and why its electronic absorption spectrum is shifted to longer wavelengths compared with the spectrum of benzenamine. Would you expect \(\mathrm{N}\) -phenylcarbazole to be a stronger, or weaker, base than triphenylamine? Explain.
Step-by-Step Solution
Verified Answer
Triphenylamine is weaker due to delocalized lone pair; longer conjugation causes red shift. N-phenylcarbazole might be stronger than triphenylamine.
1Step 1: Understanding Basicity
In organic chemistry, an amine's basicity is primarily determined by the availability of the lone pair on the nitrogen atom. The more available the lone pair, the stronger the base.
2Step 2: Effect of Phenyl Groups on Basicity
Triphenylamine has three phenyl groups attached to its nitrogen atom. These phenyl groups are electron-withdrawing due to their resonance capability, which delocalizes the nitrogen's lone pair electrons. This decreases the nitrogen's ability to donate its electrons, making triphenylamine a weaker base than benzenamine, which has only one phenyl ring.
3Step 3: Electronic Absorption Spectrum Shift
The electronic absorption spectrum is influenced by conjugation length, as longer conjugation leads to lower energy transitions and therefore longer wavelengths (red shift). Triphenylamine has extended conjugation with its three aromatic rings, resulting in a shift to longer wavelengths compared to benzenamine, which has less conjugation.
4Step 4: Comparing Basicity of N-Phenylcarbazole and Triphenylamine
N-phenylcarbazole has a carbazole moiety and only one additional phenyl group. While the carbazole system can stabilize the lone pair through resonance, the greater extent of conjugation and additional phenyl group in triphenylamine means its lone pair is more delocalized, potentially making N-phenylcarbazole a slightly stronger base than triphenylamine.
Key Concepts
Basicity of AminesElectronic Absorption SpectrumResonance in Aromatic Compounds
Basicity of Amines
In organic chemistry, the basicity of amines is a fundamental concept pivotal to the behavior of these compounds. Amines are nitrogen-containing molecules characterized by their lone electron pair. This lone pair makes them capable of accepting protons, forming a Lewis base. The strength of this base is primarily determined by the availability of this lone pair. When the electron pair is readily available for bonding, the amine shows stronger basicity.
\[ \text{Basicity} \propto \text{Availability of Lone Pair} \]
However, the presence of substituents can significantly impact this availability. An aryl (phenyl) ring is known to possess electron-withdrawing characteristics due to its resonance. When attached to the nitrogen, it can delocalize the electron pair, reducing its availability and consequently the basicity.
The stark contrast is seen with triphenylamine, which sports three phenyl groups. These groups create an extensive network where resonance spreads over all three rings, making the lone pair on nitrogen less available for bonding, thus weakening its basicity in comparison to benzenamine, which possesses only one phenyl ring.
\[ \text{Basicity} \propto \text{Availability of Lone Pair} \]
However, the presence of substituents can significantly impact this availability. An aryl (phenyl) ring is known to possess electron-withdrawing characteristics due to its resonance. When attached to the nitrogen, it can delocalize the electron pair, reducing its availability and consequently the basicity.
The stark contrast is seen with triphenylamine, which sports three phenyl groups. These groups create an extensive network where resonance spreads over all three rings, making the lone pair on nitrogen less available for bonding, thus weakening its basicity in comparison to benzenamine, which possesses only one phenyl ring.
Electronic Absorption Spectrum
The electronic absorption spectrum is an indispensable tool in organic chemistry, providing insights into the structural aspects of compounds. It measures the wavelengths of light absorbed by a compound, typically translated into a spectrum graph. This spectrum is highly influenced by the extent of conjugation in a molecule. Conjugation refers to the overlap of p-orbitals across adjacent unsaturated bonds, allowing for delocalization of electrons. A greater extent of conjugation results in the lowering of the energy gap between the HOMO (highest occupied molecular orbital) and LUMO (lowest unoccupied molecular orbital).
\[ \text{Energy Gap} \downarrow \Rightarrow \text{Wavelength (}\lambda\text{)} \uparrow \]
In practical terms, as observed with triphenylamine, this lowering trend shifts the electronic absorption spectrum to longer wavelengths (known as a red shift). This is because triphenylamine, with its triaryl setup, presents a larger conjugated system compared to benzenamine, thus requiring less energy for electronic transitions, hence absorbing longer (redder) wavelengths of light.
\[ \text{Energy Gap} \downarrow \Rightarrow \text{Wavelength (}\lambda\text{)} \uparrow \]
In practical terms, as observed with triphenylamine, this lowering trend shifts the electronic absorption spectrum to longer wavelengths (known as a red shift). This is because triphenylamine, with its triaryl setup, presents a larger conjugated system compared to benzenamine, thus requiring less energy for electronic transitions, hence absorbing longer (redder) wavelengths of light.
Resonance in Aromatic Compounds
Resonance is a key concept in understanding the stability and reactivity of aromatic compounds. It involves the delocalization of electrons across various structures, allowing for a more stable electronic configuration. This is particularly pronounced in compounds featuring aromatic rings, such as phenyl groups.
When a nitrogen atom is part of this aromatic system, as in triphenylamine, the electron pair on nitrogen can engage in resonance with the adjacent phenyl rings. Such delocalization stabilizes the entire molecule but simultaneously decreases the availability of the nitrogen's lone pair for proton acceptance, thus affecting its basicity.
\[ \text{Longevity of Resonance} \Rightarrow \text{Stability} \uparrow \Rightarrow \text{Basicity} \downarrow \]
In the case of triphenylamine, three aromatic rings create a robust resonance effect, contrasting with the less extensive resonance seen in molecules with fewer aromatic groups like benzenamine. This expansive conjugation not only reduces the basicity but also influences other properties, such as the observed electronic absorption spectra.
When a nitrogen atom is part of this aromatic system, as in triphenylamine, the electron pair on nitrogen can engage in resonance with the adjacent phenyl rings. Such delocalization stabilizes the entire molecule but simultaneously decreases the availability of the nitrogen's lone pair for proton acceptance, thus affecting its basicity.
\[ \text{Longevity of Resonance} \Rightarrow \text{Stability} \uparrow \Rightarrow \text{Basicity} \downarrow \]
In the case of triphenylamine, three aromatic rings create a robust resonance effect, contrasting with the less extensive resonance seen in molecules with fewer aromatic groups like benzenamine. This expansive conjugation not only reduces the basicity but also influences other properties, such as the observed electronic absorption spectra.
Other exercises in this chapter
Problem 52
Write structural formulas for substances (one for each part) that fit the following descriptions: a. an aromatic amine that is a stronger base than benzenamine
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Diazotization of 4-chlorobenzenamine with sodium nitrite and hydrobromic acid yields a diazonium salt solution that couples with N,N-dimethylbenzenamine to give
View solution Problem 51
What reagents and conditions would you use to prepare 2 -methylpropanamine by the following reactions: a. Hofmann rearrangement b. Schmidt rearrangement c. Curt
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