Problem 53
Question
Diazotization of 4-chlorobenzenamine with sodium nitrite and hydrobromic acid yields a diazonium salt solution that couples with N,N-dimethylbenzenamine to give substantial amounts of 4 -dimethylamino-4'-bromoazobenzene. Explain.
Step-by-Step Solution
Verified Answer
Diazotization converts 4-chlorobenzenamine to a diazonium salt, which then couples with N,N-dimethylbenzenamine to form 4-dimethylamino-4'-bromoazobenzene through an azo linkage.
1Step 1: Understanding Diazotization
Diazotization is a chemical reaction where an amine group (
-NH2) is converted into a diazonium salt using sodium nitrite (NaNO2) and a strong acid, in this case, hydrobromic acid (HBr). The 4-chlorobenzenamine undergoes diazotization to form 4-chlorobenzenediazonium bromide, which involves the formation of the diazonium (
-N2+) group.
2Step 2: Formation of Diazonium Salt
Through the diazotization reaction, 4-chlorobenzenamine reacts with sodium nitrite in hydrobromic acid to yield 4-chlorobenzenediazonium bromide. This diazonium salt is highly reactive and serves as an intermediate for further reactions.
3Step 3: Coupling Reaction
In an azo coupling reaction, the diazonium salt reacts with N,N-dimethylbenzenamine. The highly reactive diazonium group from 4-chlorobenzenediazonium bromide attacks the electron-rich aromatic ring of N,N-dimethylbenzenamine, resulting in the formation of an azo bond (
-N=N-).
4Step 4: Synthesis of 4-dimethylamino-4'-bromoazobenzene
The coupling reaction produces 4-dimethylamino-4'-bromoazobenzene. In this final compound, the azo group connects the dimethylamino group of N,N-dimethylbenzenamine to the bromine atom carried by the former diazonium salt.
Key Concepts
Diazonium Salt FormationAzo Coupling Reaction4-dimethylamino-4'-bromoazobenzene Synthesis
Diazonium Salt Formation
The diazonium salt formation is a fascinating process that involves transforming an amine group into a highly reactive diazonium group. In our specific reaction, 4-chlorobenzenamine is the starting material. The process begins with diazotization, where a sodium nitrite (\( \text{NaNO}_2 \)) reagent and hydrobromic acid (\( \text{HBr} \)) are used. This reaction occurs in two primary steps:
- The sodium nitrite reacts with the acid, generating nitrous acid (\( \text{HNO}_2 \)).
- The nitrous acid then interacts with the amine group of 4-chlorobenzenamine to form the diazonium ion (\( \text{-N}_2^+ \)).
Azo Coupling Reaction
The azo coupling reaction is a critical step in synthesizing azo compounds, known for their vivid colors and applications in dyes. In this process, the diazonium salt, which we've formed from 4-chlorobenzenamine, participates in a coupling reaction with an aromatic compound, specifically N,N-dimethylbenzenamine.The reaction initiates when the diazonium group of the salt (\( \text{-N}_2^+ \)) undergoes electrophilic attack on the aromatic ring of N,N-dimethylbenzenamine. This aromatic amine is an ideal choice for coupling because it contains an electron-rich environment that is susceptible to attack by the positively charged diazonium group.Key Points of the Azo Coupling Reaction:
- The diazonium group attaches to the electron-rich amine, forming an azo linkage (\( \text{-N=N-} \)).
- The reaction maintains the aromaticity of the ring, ensuring structural stability.
- The result is the creation of a valuable class of compounds known as azo compounds, deeply explored for their applicability in dye manufacturing.
4-dimethylamino-4'-bromoazobenzene Synthesis
The synthesis of 4-dimethylamino-4'-bromoazobenzene is the culmination of the diazotization and azo coupling reactions. This synthesis brings together the strengths of both reactions to create a complex azo compound with distinct characteristics.In the final product, the 4-chlorobenzenediazonium bromide interacts with the N,N-dimethylbenzenamine. Here, the azo coupling process forms the compound by establishing an azo bond between the aromatic groups of the two reactants.Final Characteristics of the Synthesis:
- The azo group (\( \text{-N=N-} \)) connects the dimethylamine moiety of N,N-dimethylbenzenamine with the former diazonium salt fragment.
- The bromine atom introduced from the usage of hydrobromic acid remains a part of the final structure, giving us 4-dimethylamino-4'-bromoazobenzene.
- This compound exemplifies the successful joining of highly reactive intermediates to create stable, color-rich azo compounds, described for their use in various industrial dyeing applications.
Other exercises in this chapter
Problem 51
What reagents and conditions would you use to prepare 2 -methylpropanamine by the following reactions: a. Hofmann rearrangement b. Schmidt rearrangement c. Curt
View solution Problem 52
Write structural formulas for substances (one for each part) that fit the following descriptions: a. an aromatic amine that is a stronger base than benzenamine
View solution Problem 56
Explain why triphenylamine is a much weaker base than benzenamine and why its electronic absorption spectrum is shifted to longer wavelengths compared with the
View solution Problem 49
Compound A is chiral and is a liquid with the formula \(\mathrm{C}_{5} \mathrm{H}_{11} \mathrm{O}_{2} \mathrm{~N}\). A is insoluble in water and dilute acid but
View solution