Problem 55
Question
Use the compound interest formulas \(A=P\left(1+\frac{r}{n}\right)^{n t}\) and \(A=P e^{n}\) to solve \(.\) Round answers to the nearest cent. Suppose that you have \(\$ 12,000\) to invest. Which investment yields the greater return over 3 years: \(7 \%\) compounded monthly or \(6.85 \%\) compounded continuously?
Step-by-Step Solution
Verified Answer
The investment with a 7% annual interest rate compounded monthly yields a greater return over 3 years.
1Step 1: Identify the variables for the first investment
The principal \(P = \$12,000\), the annual interest rate \(r = 7%\), the number of times the interest is compounded per year \(n = 12\) because the interest is compounded monthly, and the investment time \(t = 3\) years.
2Step 2: Calculate the amount for the first investment
Plugging the variables into the compound interest formula yields the amount \(A\$ for the first investment: \(A = P\left(1+\frac{r}{n}\right)^{nt} = 12000\left(1+\frac{0.07}{12}\right)^{12*3} = \$14,976.41\)
3Step 3: Identify the variables for the second investment
The principal \(P = \$12,000\), the annual interest rate \(n = 6.85%\), and the investment time \(t = 3\) years.
4Step 4: Calculate the amount for the second investment
Plugging the variables into the continuous compound interest formula yields the amount \(A\$ for the second investment: \(A = Pe^{nt} = 12000e^{0.0685*3} = \$14,929.76\)
5Step 5: Compare the amounts
The first investment yields \$14,976.41 and the second investment yields \$14,929.76.
Key Concepts
Compounded MonthlyContinuous CompoundingInterest Rate ComparisonInvestment GrowthFinancial Mathematics
Compounded Monthly
In the world of investing, understanding how compounding works is crucial. When interest is compounded monthly, it means that the interest for an investment is added to the principal amount twelve times a year. Each month, the new principal becomes larger, as it includes the previously accumulated interest. This method of compounding can significantly increase the amount of return you receive over the investment period.
Monthly compounding is calculated using the formula:
Monthly compounding is calculated using the formula:
- \[ A = P \left(1 + \frac{r}{n} \right)^{nt} \]
- \(A\) is the future value of the investment,
- \(P\) is the principal amount (initial investment),
- \(r\) is the annual interest rate (in decimal),
- \(n\) is the number of compounding periods per year (12 for monthly), and
- \(t\) is the time the money is invested for (in years).
Continuous Compounding
Continuous compounding takes the idea of compounding interest to its theoretical extreme, where interest is calculated and added to the account balance an infinite number of times per year. Though it’s more of a mathematical concept than a practical banking method, it can represent the ultimate growth potential of an investment.
The formula used for continuous compounding is:
The formula used for continuous compounding is:
- \[ A = Pe^{rt} \]
- \(A\) is the amount of money accumulated after n years, including interest,
- \(P\) is the principal investment amount,
- \(r\) is the annual interest rate (in decimal),
- \(t\) is the time in years, and
- \(e\) is the base of the natural logarithm, approximately equal to 2.71828.
Interest Rate Comparison
When choosing between different investment options, comparing interest rates is crucial. The rate isn't everything—how it's compounded also matters greatly. In this exercise, we assess:
To compare effectively, replace each rate into their respective formulas and see which yields a higher final amount. This comparison helps investors understand the impact of not only the rate itself but also how the interest accrues over time. It's an exercise in understanding "time value of money," a pillar in financial mathematics.
- 7% compounded monthly
- 6.85% compounded continuously
To compare effectively, replace each rate into their respective formulas and see which yields a higher final amount. This comparison helps investors understand the impact of not only the rate itself but also how the interest accrues over time. It's an exercise in understanding "time value of money," a pillar in financial mathematics.
Investment Growth
The objective of any investment strategy is to maximize growth over time. By leveraging different compounding methods, investors can increase their returns with the same initial amount. For example, a 7% rate compounded monthly can lead to a larger return compared to a slightly lesser rate compounded in different scenarios.
Investment growth is a function of rate, time, and compounding frequency. By understanding these components, investors can more neatly align their investment choices with growth targets.
In applying these principles to real-world scenarios, one must always aim to select the method that maximizes returns while aligning with risk tolerance and financial goals.
Investment growth is a function of rate, time, and compounding frequency. By understanding these components, investors can more neatly align their investment choices with growth targets.
In applying these principles to real-world scenarios, one must always aim to select the method that maximizes returns while aligning with risk tolerance and financial goals.
Financial Mathematics
Financial mathematics plays a pivotal role in analyzing investments and evaluating their potential performance. By breaking down complex scenarios into calculable formulas, it offers a path to making informed decisions.
- It helps in determining the future value of investments.
- Allows comparison of different financial options.
- Assists in recognizing the benefits of compounding interest over the simple interest scenario.
Other exercises in this chapter
Problem 55
In Exercises \(53-56,\) rewrite the equation in terms of base \(e\). Express the answer in terms of a natural logarithm and then round to three decimal places.
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Begin by graphing \(f(x)=\log _{2} x .\) Then use transformations of this graph to graph the given function. What is the vertical asymptote? Use the graphs to d
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Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
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