Problem 55
Question
Use properties of logarithms to condense logarithmic expression. Write the expression as a single logarithm whose coefficient is 1. Where possible, evaluate logarithmic expressions without using a calculator. \(5 \ln x-2 \ln y\)
Step-by-Step Solution
Verified Answer
The simplified form of the given expression \(5 \ln x - 2 \ln y\) is \(\ln (x^5 / y^2)\)
1Step 1: Applying the Power Rule
Apply the power rule of logarithms which states, \(a \ln b = \ln (b^a)\). This can be applied to both \(5 \ln x\) and \(-2 \ln y\) separately to get the new expression: \(\ln (x^5) - \ln (y^2)\)
2Step 2: Applying the Quotient Rule
Next, apply the quotient rule of logarithms which states, \(\ln a - \ln b = \ln( a / b)\). Apply this rule to the modified expression to get: \(\ln (x^5 / y^2)\)
3Step 3: Final Simplification
Now the expression has been converted to a single logarithm with no coefficient, which is the final answer.
Key Concepts
Properties of LogarithmsPower RuleQuotient RuleSingle Logarithm
Properties of Logarithms
Logarithms transform complex multiplication and division problems into simpler addition and subtraction tasks. Several properties make this possible.
These rules are essential for simplifying logarithmic expressions and solving logarithmic equations. They help you condense or expand logs into simpler forms.
- Product Rule: This rule tells us that \( \ln(a) + \ln(b) = \ln(ab) \). In other words, when multiplying numbers inside a logarithm, you can add the logs instead.
- Quotient Rule: This states that \( \ln(a) - \ln(b) = \ln(a/b) \). For division, you subtract one log from the other.
- Power Rule: It's represented by \( a \ln(b) = \ln(b^a) \). You can turn the coefficient of a log into an exponent.
These rules are essential for simplifying logarithmic expressions and solving logarithmic equations. They help you condense or expand logs into simpler forms.
Power Rule
The Power Rule is a handy property for simplifying logarithms that come with coefficients.
To use this rule, you should transform the coefficient of the log expression into an exponent. For example, in the term \( 5 \ln x \), the coefficient 5 becomes an exponent to give \( \ln(x^5) \).
Similarly, when you have \(-2 \ln y\), it changes to \( \ln(y^{-2}) \). This conversion makes both logs easier to manage and allows further simplifications. It prepares logarithmic expressions for the Quotient Rule, which comes next.
To use this rule, you should transform the coefficient of the log expression into an exponent. For example, in the term \( 5 \ln x \), the coefficient 5 becomes an exponent to give \( \ln(x^5) \).
Similarly, when you have \(-2 \ln y\), it changes to \( \ln(y^{-2}) \). This conversion makes both logs easier to manage and allows further simplifications. It prepares logarithmic expressions for the Quotient Rule, which comes next.
Quotient Rule
The Quotient Rule simplifies expressions involving the difference of two logarithms.
By using this rule, you can turn \( \ln(a) - \ln(b) \) into \( \ln(a/b) \). It essentially means that you can divide numbers inside the log function instead of dealing with subtraction outside.
In the exercise given, \( \ln(x^5) - \ln(y^2) \) gets condensed into \( \ln(x^5 / y^2) \). The expression is now a single logarithm, indicating successful simplification using the quotient property.
By using this rule, you can turn \( \ln(a) - \ln(b) \) into \( \ln(a/b) \). It essentially means that you can divide numbers inside the log function instead of dealing with subtraction outside.
In the exercise given, \( \ln(x^5) - \ln(y^2) \) gets condensed into \( \ln(x^5 / y^2) \). The expression is now a single logarithm, indicating successful simplification using the quotient property.
Single Logarithm
Turning multiple logarithm expressions into a single logarithm is often the goal to simplify problems. Through properties like the Power and Quotient Rules, log expressions can be condensed.
The primary aim is to have no extra coefficients and result in an expression such as \( \ln(x/y) \) rather than \( a \ln(x) - b \ln(y) \). In the exercise, by applying these rules, \( 5 \ln(x) - 2 \ln(y) \) becomes \( \ln(x^5 / y^2) \). This form is easy to interpret and can be calculated in simpler steps.
A single logarithm is often easier to evaluate or use in further calculations. This is why learning these properties is crucial to mastering logarithmic problems.
The primary aim is to have no extra coefficients and result in an expression such as \( \ln(x/y) \) rather than \( a \ln(x) - b \ln(y) \). In the exercise, by applying these rules, \( 5 \ln(x) - 2 \ln(y) \) becomes \( \ln(x^5 / y^2) \). This form is easy to interpret and can be calculated in simpler steps.
A single logarithm is often easier to evaluate or use in further calculations. This is why learning these properties is crucial to mastering logarithmic problems.
Other exercises in this chapter
Problem 54
Solve each logarithmic equation. Be sure to reject any value of \(x\) that is not in the domain of the original logarithmic expressions. Give the exact answer.
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In Exercises \(53-56,\) rewrite the equation in terms of base \(e\). Express the answer in terms of a natural logarithm and then round to three decimal places.
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Use the compound interest formulas \(A=P\left(1+\frac{r}{n}\right)^{n t}\) and \(A=P e^{n}\) to solve \(.\) Round answers to the nearest cent. Suppose that you
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Begin by graphing \(f(x)=\log _{2} x .\) Then use transformations of this graph to graph the given function. What is the vertical asymptote? Use the graphs to d
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