Problem 55
Question
Solve each quadratic equation using the method that seems most appropriate. $$ 4 x^{2}-8 x+3=0 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = \frac{3}{2}\) and \(x = \frac{1}{2}\).
1Step 1: Identify the Equation Type
The given equation is a quadratic equation in the standard form, \(4x^2 - 8x + 3 = 0\). The coefficients are \(a = 4\), \(b = -8\), and \(c = 3\).
2Step 2: Check for Factoring Possibility
We first check if the quadratic is easily factorable. We look for two numbers that multiply to \(ac = 4 \times 3 = 12\) and add up to \(b = -8\). However, such numbers do not exist. Thus, factoring is not possible here.
3Step 3: Use the Quadratic Formula
As factoring is not straightforward, we use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\).
4Step 4: Calculate the Discriminant
Calculate the discriminant \(b^2 - 4ac = (-8)^2 - 4 \times 4 \times 3 = 64 - 48 = 16\).
5Step 5: Solve Using the Quadratic Formula
Substitute the values into the quadratic formula: \[x = \frac{-(-8) \pm \sqrt{16}}{2 \times 4}\]Simplify: \[x = \frac{8 \pm 4}{8}\].
6Step 6: Evaluate the Expressions
Now solve for the two possible values of \(x\).1. \(x = \frac{8 + 4}{8} = \frac{12}{8} = \frac{3}{2}\)2. \(x = \frac{8 - 4}{8} = \frac{4}{8} = \frac{1}{2}\).
7Step 7: Conclusion
The solutions for the quadratic equation \(4x^2 - 8x + 3 = 0\) are \(x = \frac{3}{2}\) and \(x = \frac{1}{2}\).
Key Concepts
Quadratic FormulaDiscriminantSolving Quadratic Equations
Quadratic Formula
One of the most effective methods for solving quadratic equations is the quadratic formula. The quadratic formula is specifically designed to find solutions (also known as "roots" or "zeros") for any quadratic equation, which takes the standard form: \[ ax^2 + bx + c = 0 \] The formula itself is: \[ x = \frac{-b \pm \sqrt{b^2-4ac}}{2a} \] Where:
- \(a\) is the coefficient of \(x^2\)
- \(b\) is the coefficient of \(x\)
- \(c\) is the constant term
Discriminant
The discriminant is a part of the quadratic formula that provides essential information about the roots of a quadratic equation even before solving it. It is given by the expression under the square root in the quadratic formula: \( b^2 - 4ac \).The discriminant determines the nature and number of roots as follows:
- If \(b^2 - 4ac > 0\), the quadratic equation has two distinct real roots.
- If \(b^2 - 4ac = 0\), there is exactly one real root (also known as a repeated or double root).
- If \(b^2 - 4ac < 0\), the equation has two complex roots (imaginary roots) with no real solutions.
Solving Quadratic Equations
Solving quadratic equations involves finding the values of \(x\) that make the equation true. Quadratic equations are second-degree polynomials, and solving them can be done through several methods, but the quadratic formula is one of the most universal.To begin solving a quadratic equation, you first need to ensure it's set to zero, like this: \[ ax^2 + bx + c = 0 \]Let's briefly touch upon possible methods:
- Factoring: Attempt to express the equation as a product of binomials. This works best when the equation is easily factorable.
- Quadratic Formula: Use this formula to find solutions when factoring is difficult or impossible.
- Completing the Square: This method transforms the quadratic into a perfect square trinomial.
Other exercises in this chapter
Problem 55
Set up an equation and solve each problem. Charlotte's time to travel 250 miles is 1 hour more than Lorraine's time to travel 180 miles. Charlotte drove 5 miles
View solution Problem 55
For each quadratic equation, first use the discriminant to determine whether the equation has two nonreal complex solutions, one real solution with a multiplici
View solution Problem 55
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. $$ \frac{\sqrt{-25}}{\sqrt{-4}} $$
View solution Problem 56
Solve each inequality. $$ \frac{x+3}{x-4} \geq 1 $$
View solution