Problem 55
Question
Simplify the algebraic expressions for the following problems. $$ 2\left\\{5\left[6\left(b+2 a+c^{2}\right)\right]\right\\} $$
Step-by-Step Solution
Verified Answer
Question: Simplify the given algebraic expression: $$
2\left\{5\left[6\left(b+2a+c^{2}\right)\right]\right\}
$$
Answer: $$
120a + 60b + 60c^{2}
$$
1Step 1: Distribute the constants inside the brackets
First, distribute the innermost constant 6 inside the parentheses (b + 2a + c^2):
$$
2\left\{5\left[6b+12a+6c^{2}\right]\right\}
$$
2Step 2: Distribute the constants inside the braces
Next, distribute the constant 5 inside the brackets [6b + 12a + 6c^2]:
$$
2\left\{30b+60a+30c^{2}\right\}
$$
3Step 3: Distribute the constant outside the braces
Finally, distribute the constant 2 inside the braces {30b + 60a + 30c^2}:
$$
60b+120a+60c^{2}
$$
4Step 4: Write the simplified expression
Now that we've distributed all the constants and combined like terms, we can write the simplified algebraic expression:
$$
120a + 60b + 60c^{2}
$$
Key Concepts
Distributive PropertyCombining Like TermsAlgebraic Expression
Distributive Property
The distributive property is a fundamental principle in algebra that enables us to multiply a single term by each term inside a parenthesis or bracket. Essentially, it helps us simplify expressions where multiplication is distributed over addition or subtraction.
Consider an expression like \( a(b + c) \). The distributive property tells us that you multiply \( a \) by both \( b \) and \( c \), resulting in \( ab + ac \). This is precisely what we did in Step 1 of our exercise, where the number 6 was distributed over the terms inside the parentheses which contained \( b \), \( 2a \), and \( c^2 \).
Understanding how to correctly apply the distributive property can make complex expressions much simpler to handle. It's analogous to sharing an equal amount of something among a few friends – everyone gets their fair portion. In algebra, every term within the brackets gets its 'fair share' of the outside number.
Consider an expression like \( a(b + c) \). The distributive property tells us that you multiply \( a \) by both \( b \) and \( c \), resulting in \( ab + ac \). This is precisely what we did in Step 1 of our exercise, where the number 6 was distributed over the terms inside the parentheses which contained \( b \), \( 2a \), and \( c^2 \).
Understanding how to correctly apply the distributive property can make complex expressions much simpler to handle. It's analogous to sharing an equal amount of something among a few friends – everyone gets their fair portion. In algebra, every term within the brackets gets its 'fair share' of the outside number.
Combining Like Terms
Once we have used the distributive property to expand an algebraic expression, we often need to look out for like terms to further simplify the expression. Like terms are terms that have the same variable parts raised to the same powers, which means their coefficients can be combined through addition or subtraction.
For example, \( 3a + 5a \) can be simplified by combining the coefficients of \( a \) to get \( 8a \). However, terms like \( 2a \) and \( 3b \) are not like terms because they have different variable parts.
In the final steps of our exercise, we applied this concept after expanding the entire expression. The process we followed didn’t create additional like terms, but in cases where it does, combining them is a key step to reach the simplest form of the expression. This could be thought of as gathering all similar fruits into their respective baskets to see what you have at a glance.
For example, \( 3a + 5a \) can be simplified by combining the coefficients of \( a \) to get \( 8a \). However, terms like \( 2a \) and \( 3b \) are not like terms because they have different variable parts.
In the final steps of our exercise, we applied this concept after expanding the entire expression. The process we followed didn’t create additional like terms, but in cases where it does, combining them is a key step to reach the simplest form of the expression. This could be thought of as gathering all similar fruits into their respective baskets to see what you have at a glance.
Algebraic Expression
An algebraic expression is a mathematical phrase that can contain ordinary numbers, variables (like \( x \) or \( y \)), and operators (like addition and multiplication). Expressions are the building blocks of algebra and are used to represent relationships between different quantities.
In our exercise, \( 2\big\{5\big[6(b+2a+c^2)\big]\big\) is an example of an algebraic expression. It includes numerical coefficients (2, 5, 6), variables (\( a, b, c \) ), and exponents (as seen in \( c^2 \) which stands for \( c \times c \) ). There are no equal signs in an expression, so they don’t state an equality like an equation would, but they can be simplified or manipulated algebraically.
Learning to work with algebraic expressions is like learning a new language; each part has a role, and when put together correctly, they convey meaningful information which can be used to solve problems.
In our exercise, \( 2\big\{5\big[6(b+2a+c^2)\big]\big\) is an example of an algebraic expression. It includes numerical coefficients (2, 5, 6), variables (\( a, b, c \) ), and exponents (as seen in \( c^2 \) which stands for \( c \times c \) ). There are no equal signs in an expression, so they don’t state an equality like an equation would, but they can be simplified or manipulated algebraically.
Learning to work with algebraic expressions is like learning a new language; each part has a role, and when put together correctly, they convey meaningful information which can be used to solve problems.
Other exercises in this chapter
Problem 55
For the following problems, perform the multiplications and combine any like terms. $$ 6 a(a-5) $$
View solution Problem 55
For the following problems, note how many: \(y^{3}\) 's in \(6 y^{3} ?\)
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For the following problems, find the products. $$ (2 y+3)(2 y-3) $$
View solution Problem 56
For the following problems, simplify each of the algebraic expressions. $$ 8 x-3 x+4(2 x+5)+3(6 x-4) $$
View solution