Problem 55
Question
Find each product. Assume that all variables represent positive real numbers. $$-4 k\left(k^{7 / 3}-6 k^{1 / 3}\right)$$
Step-by-Step Solution
Verified Answer
-4k^{10/3} + 24k^{4/3}
1Step 1: Distribute the term outside the parentheses
Multiply the term outside the parentheses, \(-4k\), by each term inside the parentheses, \(k^{7/3}\) and \(-6k^{1/3}\), separately.
2Step 2: Multiply \\(-4k\\) by \\(k^{7/3}\\)
The expression becomes \(-4k imes k^{7/3} = -4k^{1 + 7/3}\). Add the exponents: \(1 + 7/3 = 3/3 + 7/3 = 10/3\). This results in \(-4k^{10/3}\).
3Step 3: Multiply \\(-4k\\) by \\(-6k^{1/3}\\)
The expression becomes \(-4k imes -6k^{1/3} = 24k^{1 + 1/3}\). Here, a negative times a negative is positive. Add the exponents: \(1 + 1/3 = 3/3 + 1/3 = 4/3\). This results in \(+24k^{4/3}\).
4Step 4: Combine the resulting terms
The terms \(-4k^{10/3}\) and \(+24k^{4/3}\) are combined to form the final expression: \(-4k^{10/3} + 24k^{4/3}\).
Key Concepts
Exponent RulesDistributive PropertyAlgebraic Expressions
Exponent Rules
Understanding exponent rules is crucial when dealing with polynomial multiplication. In this exercise, we encounter expressions like \(k^{7/3}\) and \(k^{1/3}\). Exponents are shorthand for repeated multiplication, and they follow specific rules which simplify the multiplication process.
- Product of Powers Rule: When multiplying like bases, you can add the exponents together. For example, when you have \(k^a \times k^b\), the result is \(k^{a+b}\). This rule was used when multiplying \(-4k \times k^{7/3}\), resulting in \(k^{10/3}\).
- Power of a Power Rule: Although not directly used here, it's a good reminder that when taking a power of a power, you multiply the exponents. For instance, \((k^a)^b = k^{a \cdot b}\).
Distributive Property
The distributive property is a fundamental principle in algebra, especially in polynomial multiplication. It allows us to "distribute" or multiply a single term by each term within a parenthesis in an expression.
In this particular exercise, the expression \(-4k(k^{7/3} - 6k^{1/3})\) requires distributing the \(-4k\) across each term inside the parenthesis:
In this particular exercise, the expression \(-4k(k^{7/3} - 6k^{1/3})\) requires distributing the \(-4k\) across each term inside the parenthesis:
- First, \(-4k\) is multiplied by \(k^{7/3}\).
- Then, \(-4k\) is applied to \(-6k^{1/3}\), keeping in mind that a negative times a negative gives a positive result.
Algebraic Expressions
At the heart of algebra are expressions like \(-4k(k^{7/3} - 6k^{1/3})\), which consist of variables, numbers, and operations. Algebraic expressions help us model real-world scenarios and solve mathematical problems.
- Terms: Each part of an expression that is added or subtracted is called a term. In the expression, \(-4k^{10/3}\) and \(+24k^{4/3}\) are terms.
- Coefficients: These are the numerical factors of terms. In our problem, \(-4\) and \(+24\) are coefficients.
- Variables and Exponents: The letters (e.g., \(k\)) in expressions signify variables, which can change. Exponents show the power a variable is raised to, indicating repeated multiplication.
Other exercises in this chapter
Problem 54
Perform the indicated operations. $$(6 k-3)^{2}$$
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If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\frac{\sqrt[4]{32 x^{5} y} \cdot \sqrt[4]{2 x y^{4}}
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Factor each sum or difference of cubes completely. $$27 y^{9}+125 z^{6}$$
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Find each sum or difference. $$\frac{x+y}{2 x-y}-\frac{2 x}{y-2 x}$$
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