Problem 54
Question
Perform the indicated operations. $$(6 k-3)^{2}$$
Step-by-Step Solution
Verified Answer
The expanded form is \(36k^2 - 36k + 9\).
1Step 1: Identify the Expression to Expand
The expression given is \[(6k - 3)^2\].This means we need to square the binomial \(6k - 3\).
2Step 2: Apply the Binomial Square Formula
The formula for squaring a binomial is:\((a - b)^2 = a^2 - 2ab + b^2\).Identify the parts of the binomial: \(a = 6k\) and \(b = 3\).
3Step 3: Square the First Term
Calculate \((6k)^2\):\[(6k)^2 = 36k^2\].
4Step 4: Compute Twice the Product of the Terms
Find \(-2ab\):\[-2(6k)(3) = -36k\].
5Step 5: Square the Second Term
Calculate \(3^2\):\[3^2 = 9\].
6Step 6: Combine All Terms Together
Combine the results from the previous steps:\[36k^2 - 36k + 9\].This is the expanded form of the expression.
Key Concepts
Understanding Algebraic ExpressionsExploring the Binomial TheoremPerforming Mathematical Operations
Understanding Algebraic Expressions
Algebraic expressions are mathematical phrases that can consist of numbers, variables, and operations. They represent values and form the foundation of algebra. An algebraic expression can be as simple as a single number or variable, or as complex as multiple terms combined with operators.
For example, in the given expression \(6k - 3\), we have:
For example, in the given expression \(6k - 3\), we have:
- 6 is the coefficient of the variable \(k\).
- \(k\) is a variable, which means it can represent different values.
- -3 is a constant term.
Exploring the Binomial Theorem
The binomial theorem is a powerful tool used to expand expressions that are raised to a power. It is particularly useful for binomials, which are algebraic expressions with two terms. In this exercise, we are dealing with \(6k - 3\)^2, which fits this description perfectly.
The formula used for squaring a binomial is:
This expansion makes complex expressions more manageable, revealing the underlying values.
The formula used for squaring a binomial is:
- \((a + b)^2 = a^2 + 2ab + b^2\)
- \((a - b)^2 = a^2 - 2ab + b^2\)
This expansion makes complex expressions more manageable, revealing the underlying values.
Performing Mathematical Operations
Mathematical operations involve applying basic arithmetic processes such as addition, subtraction, multiplication, and division to solve problems. In the case of expanding \(6k - 3\)^2, these operations come into play as follows:
- Squaring terms: First, we square each individual term. \(a = 6k\) results in \((6k)^2 = 36k^2\), and \(b = 3\) gives \(3^2 = 9\).
- Multiplication and subtraction: We calculate twice the product of the terms using \(-2ab = -2(6k)(3) = -36k\).
- Combining terms: Finally, add all the calculated values to form the expanded expression: \(36k^2 - 36k + 9\).
Other exercises in this chapter
Problem 54
Factor each sum or difference of cubes completely. $$8 m^{3}-27 n^{3}$$
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Find each sum or difference. $$\frac{q}{p-q}-\frac{q}{q-p}$$
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If possible, simplify each radical expression. Assume that all variables represent positive real numbers. $$\frac{\sqrt[4]{32 x^{5} y} \cdot \sqrt[4]{2 x y^{4}}
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Find each product. Assume that all variables represent positive real numbers. $$-4 k\left(k^{7 / 3}-6 k^{1 / 3}\right)$$
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