Problem 55
Question
Evaluate the infinite geometric series \(\frac{2}{5}+\frac{4}{25}+\frac{8}{125}+\ldots\) Enter your answer as a fraction.
Step-by-Step Solution
Verified Answer
The sum of the infinite geometric series \(\frac{2}{5}+\frac{4}{25}+\frac{8}{125}+\ldots\) is \(\frac{2}{3}\).
1Step 1: Identify the first term and the common ratio
The first term (a) of the series is \(\frac{2}{5}\). The common ratio (r) can be found by dividing the second term by the first term, which gives us \(\frac{4}{25} / \frac{2}{5} = \frac{2}{5}\)
2Step 2: Apply the geometric series sum formula
The formula for the sum of an infinite geometric series is \(S = a / (1 - r)\). Plug the values of a and r into this formula: \(S = \frac{2}{5} / (1 - \frac{2}{5})\).
3Step 3: Simplify the fraction
Simplifying, we get \(S = \frac{2}{5} / \frac{3}{5} = 2/3\).
Key Concepts
Understanding the Common Ratio in Geometric SeriesThe Geometric Series Sum FormulaFraction Simplification
Understanding the Common Ratio in Geometric Series
In an infinite geometric series, the "common ratio" is a pivotal concept. The common ratio, denoted by \(r\), is the factor by which we multiply each term to get the next one. In this context, our series looks like this: \(\frac{2}{5}, \frac{4}{25}, \frac{8}{125}, \ldots\). To find the common ratio \(r\), we need to divide the second term by the first term.
Let's do the math: Divide \(\frac{4}{25}\) by \(\frac{2}{5}\). When dividing fractions, we multiply by the reciprocal. So, \(\frac{4}{25} / \frac{2}{5}\) becomes \(\frac{4}{25} \times \frac{5}{2}\). Calculating further, we find that \(r = \frac{2}{5}\).
Thus, every term in the series is \(\frac{2}{5}\) times the previous one, a defining feature of geometric series.
Let's do the math: Divide \(\frac{4}{25}\) by \(\frac{2}{5}\). When dividing fractions, we multiply by the reciprocal. So, \(\frac{4}{25} / \frac{2}{5}\) becomes \(\frac{4}{25} \times \frac{5}{2}\). Calculating further, we find that \(r = \frac{2}{5}\).
Thus, every term in the series is \(\frac{2}{5}\) times the previous one, a defining feature of geometric series.
The Geometric Series Sum Formula
The geometric series sum formula is essential for computing the sum of an infinite geometric series, especially when we're dealing with infinite terms. The formula is expressed as:
For our series, \(a = \frac{2}{5}\) and \(r = \frac{2}{5}\). Plugging these values into the formula gives us:
- \(S = \frac{a}{1 - r}\)
For our series, \(a = \frac{2}{5}\) and \(r = \frac{2}{5}\). Plugging these values into the formula gives us:
- \(S = \frac{\frac{2}{5}}{1 - \frac{2}{5}}\)
- \( 1 - \frac{2}{5} = \frac{3}{5}\)
Fraction Simplification
Simplifying fractions is a key mathematical skill used to find easier numbers to work with, especially when applying the geometric series sum formula. After plugging in the variables, we have:
So, the sum of this infinite geometric series is \(\frac{2}{3}\). Mastering fraction simplification makes handling complex algebra much smoother and less intimidating.
- \(S = \frac{\frac{2}{5}}{\frac{3}{5}}\)
- \(\frac{2}{5} \times \frac{5}{3} = \frac{2}{3}\)
So, the sum of this infinite geometric series is \(\frac{2}{3}\). Mastering fraction simplification makes handling complex algebra much smoother and less intimidating.
Other exercises in this chapter
Problem 54
Writing Describe the similarities and differences between a common difference and a common ratio.
View solution Problem 54
Write an explicit and a recursive formula for each sequence. \(-5,-4,-3,-2,-1, \ldots\)
View solution Problem 55
Write the equation of each hyperbola in standard form. Sketch the graph. $$ 16 x^{2}-10 y^{2}=160 $$
View solution Problem 55
Write an expression for the sum of a 6 -term arithmetic sequence with first term of 3 and a common difference of 4 . Then find the sum.
View solution