Problem 54
Question
Some radionuclides decay by capturing one of their own atomic electrons, a \(K\) -shell electron, say. An example is $${ }^{49} \mathrm{~V}+\mathrm{e}^{-} \rightarrow{ }^{49} \mathrm{Ti}+\nu, \quad T_{1 / 2}=331 \mathrm{~d}$$ Show that the disintegration energy \(Q\) for this process is given by $$Q=\left(m_{\mathrm{V}}-m_{\mathrm{Ti}}\right) c^{2}-E_{K}$$ where \(m_{\mathrm{v}}\) and \(m_{\mathrm{Ti}}\) are the atomic masses of \({ }^{49} \mathrm{~V}\) and \({ }^{49} \mathrm{Ti},\) respectively, and \(E_{K}\) is the binding energy of the vanadium \(K\) -shell electron. (Hint: Put \(\mathbf{m}_{\mathrm{V}}\) and \(\mathbf{m}_{\mathrm{Ti}}\) as the corresponding nuclear masses and then add in enough electrons to use the atomic masses.)
Step-by-Step Solution
VerifiedKey Concepts
Binding Energy
The binding energy plays a crucial role in nuclear decay processes. In electron capture, a K-shell electron is captured by the nucleus. This particular process absorbs the binding energy of the electron.
- This energy must be considered when calculating the disintegration energy.
- In our example, the binding energy is subtracted from the total energy release, as the K-shell electron is assumed to be absorbed.
Disintegration Energy
- The disintegration energy is a crucial factor in determining the behavior of nuclear decays, as it reflects the changed binding energy from before and after the reaction.
- In the exercise, the equation \(Q = \left(m_{\text{V}} - m_{\text{Ti}}\right)c^2 - E_{K}\) illustrates how to account for the captured electron's binding energy when calculating the energy released.
Nuclear Decay
- Transmutation of elements: In electron capture, as detailed in this example, a K-shell electron is captured by the nucleus of an atom, transforming it into a different element.
- Stability factors: This process often occurs when the original atom is more unstable compared to the resulting atom. The electron capture process stabilizes the atom by converting a proton into a neutron, usually when additional neutrons can lead to a more stable nucleus.
- Released particles: In electron capture, a neutrino (often denoted \(u\)) is released. This process is one form of nuclear decay, differing from others like alpha or beta decay where particles are expelled from the atom.