Problem 53
Question
What is the common ratio for the geometric series \(\sum_{n=1}^{10} 7\left(\frac{4}{7}\right)^{n-1} ?\) Enter your answer as a fraction.
Step-by-Step Solution
Verified Answer
The common ratio of the geometric series is \(\frac{4}{7}\).
1Step 1: Identify the geometric series
The geometric series in this exercise is \(\sum_{n=1}^{10} 7\left(\frac{4}{7}\right)^{n-1}\).
2Step 2: Determine the common ratio
The common ratio (r) is the value being raised to the power of \(n-1\). Looking at the geometric series, the common ratio is \(\frac{4}{7}\).
Key Concepts
Common RatioGeometric SequenceAlgebra 2
Common Ratio
In a geometric series, the common ratio is a key element that determines how the terms progress. It is the factor by which each term is multiplied to get the next term. Identifying the common ratio helps us understand the pattern of the series.
The common ratio is often represented by the letter \( r \) and is constant throughout the series.
A good tip is to always look for this consistent multiplier when identifying geometric series, as it reveals the steady growth or decay of the series.
The common ratio is often represented by the letter \( r \) and is constant throughout the series.
- In the given series \( \sum_{n=1}^{10} 7\left(\frac{4}{7}\right)^{n-1} \), look closely at the expression inside the series.
- The value that is raised to the power of \( n-1 \) is the common ratio.
A good tip is to always look for this consistent multiplier when identifying geometric series, as it reveals the steady growth or decay of the series.
Geometric Sequence
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. This sequence can appear in various forms, including finite and infinite sequences.
In the context of a geometric series, which is the sum of the terms of a geometric sequence, understanding the sequence helps us predict and find values. Here's how it works:
Understanding this pattern is crucial in solving problems involving geometric sequences.
In the context of a geometric series, which is the sum of the terms of a geometric sequence, understanding the sequence helps us predict and find values. Here's how it works:
- The first term is multiplied by the common ratio to get the second term.
- The second term is multiplied by the common ratio again to get the third term, and so on.
Understanding this pattern is crucial in solving problems involving geometric sequences.
Algebra 2
Algebra 2 is a branch of mathematics that builds upon the concepts learned in Algebra 1, introducing students to more complex functions and advanced topics such as geometric sequences and series.
In Algebra 2, geometric sequences are often explored deeper as students learn to solve problems involving formula and sequence patterns. This involves:
In the given exercise, identifying the common ratio and recognizing the structure of the series are part of the broader learning objectives in Algebra 2.
In Algebra 2, geometric sequences are often explored deeper as students learn to solve problems involving formula and sequence patterns. This involves:
- Understanding how geometric sequences form the basis for series.
- Applying formulas to find specific terms within sequences.
- Having the ability to calculate the sum of a series, both finite and infinite.
In the given exercise, identifying the common ratio and recognizing the structure of the series are part of the broader learning objectives in Algebra 2.
Other exercises in this chapter
Problem 52
Find the 10 th term of each geometric sequence. $$ a_{9}=-\frac{1}{3}, r=\frac{1}{2} $$
View solution Problem 52
Write an explicit and a recursive formula for each sequence. \(2,4,6,8,10, \dots\)
View solution Problem 53
Write the equation of each hyperbola in standard form. Sketch the graph. $$ 9 x^{2}-16 y^{2}=144 $$
View solution Problem 53
Which expression represents the sum of the finite series \(13+10+7+4 ?\) I. \(\sum_{n=1}^{4}(16-3 n)\) II. \(\sum_{n=3}^{6}(22-3 n)\) III. \(\sum_{n=1}^{4}(4+3
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