Problem 53
Question
Let \(A B C D\) be a general, not necessarily planar, quadrilateral in space. Show that the two segments joining the midpoints of opposite sides of \(A B C D\) bisect each other. (Hint: Show that the segments have the same midpoint.)
Step-by-Step Solution
Verified Answer
The segments joining the midpoints of opposite sides bisect each other as they share the same midpoint.
1Step 1: Determine Midpoints of Opposite Sides
Let the coordinates of the vertices of quadrilateral \(ABCD\) be \(A(x_1, y_1, z_1)\), \(B(x_2, y_2, z_2)\), \(C(x_3, y_3, z_3)\), and \(D(x_4, y_4, z_4)\).Compute the midpoints of opposite sides \(AB\) and \(CD\). The midpoint \(M_1\) of side \(AB\) is given by:\[M_1 = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}, \frac{z_1 + z_2}{2} \right)\]The midpoint \(M_2\) of side \(CD\) is given by:\[M_2 = \left( \frac{x_3 + x_4}{2}, \frac{y_3 + y_4}{2}, \frac{z_3 + z_4}{2} \right)\]
2Step 2: Determine Midpoints for the Other Pair of Opposite Sides
Now consider the other pair of opposite sides, \(BC\) and \(DA\).Compute the midpoints of these sides. The midpoint \(M_3\) of side \(BC\) is:\[M_3 = \left( \frac{x_2 + x_3}{2}, \frac{y_2 + y_3}{2}, \frac{z_2 + z_3}{2} \right)\]The midpoint \(M_4\) of side \(DA\) is:\[M_4 = \left( \frac{x_1 + x_4}{2}, \frac{y_1 + y_4}{2}, \frac{z_1 + z_4}{2} \right)\]
3Step 3: Find Midpoint of Segments Connecting Midpoints
We need to find the midpoint of the segment connecting \(M_1\) and \(M_2\), and similarly for the segment connecting \(M_3\) and \(M_4\).The midpoint \(P_1\) of the segment \(M_1M_2\) is:\[P_1 = \left( \frac{\left(\frac{x_1 + x_2}{2}\right) + \left(\frac{x_3 + x_4}{2}\right)}{2}, \frac{\left(\frac{y_1 + y_2}{2}\right) + \left(\frac{y_3 + y_4}{2}\right)}{2}, \frac{\left(\frac{z_1 + z_2}{2}\right) + \left(\frac{z_3 + z_4}{2}\right)}{2} \right)\]which simplifies to:\[P_1 = \left( \frac{x_1 + x_2 + x_3 + x_4}{4}, \frac{y_1 + y_2 + y_3 + y_4}{4}, \frac{z_1 + z_2 + z_3 + z_4}{4} \right)\]
4Step 4: Show that Segment Midpoints Are Equal
Now, compute the midpoint \(P_2\) of the segment \(M_3M_4\):\[P_2 = \left( \frac{\left(\frac{x_2 + x_3}{2}\right) + \left(\frac{x_1 + x_4}{2}\right)}{2}, \frac{\left(\frac{y_2 + y_3}{2}\right) + \left(\frac{y_1 + y_4}{2}\right)}{2}, \frac{\left(\frac{z_2 + z_3}{2}\right) + \left(\frac{z_1 + z_4}{2}\right)}{2} \right)\]which simplifies to:\[P_2 = \left( \frac{x_1 + x_2 + x_3 + x_4}{4}, \frac{y_1 + y_2 + y_3 + y_4}{4}, \frac{z_1 + z_2 + z_3 + z_4}{4} \right)\]Since \(P_1 = P_2\), the segments bisect each other.
Key Concepts
Quadrilateral propertiesMidpointsSpatial geometry
Quadrilateral properties
In the world of geometry, a quadrilateral is a four-sided shape with straight sides. The basic properties of a quadrilateral include:
- Four sides and four vertices.
- The sum of the interior angles is always 360 degrees.
- The quadrilateral can be simple (not intersecting) or complex (self-intersecting).
Midpoints
A midpoint is a point that divides a line segment into two equal parts. The concept of finding midpoints is crucial in geometry, as it helps in analyzing equal divisions within geometric shapes. To find the midpoint of a line segment in three-dimensional space between two points:
- Average the x-coordinates of the endpoints: \( \frac{x_1 + x_2}{2} \)
- Average the y-coordinates: \( \frac{y_1 + y_2}{2} \)
- Average the z-coordinates: \( \frac{z_1 + z_2}{2} \)
Spatial geometry
Spatial geometry revolves around the study of geometrical shapes in three-dimensional space. Unlike plane geometry, which deals with two-dimensional shapes, spatial geometry considers how shapes extend into a space that encompasses length, width, and height. This allows for more complex shapes and configurations, like spatial quadrilaterals.
- Understanding spatial geometry is crucial when examining relationships between geometric figures in space, such as how lines or segments interact.
- In spatial geometry, it's common to explore how midpoints and bisecting segments relate to one another, as demonstrated in the original problem where segments formed by connecting midpoints of opposite sides bisect each other.
Other exercises in this chapter
Problem 53
In Exercises \(53-56,\) find the point in which the line meets the plane. $$ x=1-t, \quad y=3 t, \quad z=1+t ; \quad 2 x-y+3 z=6 $$
View solution Problem 53
Find equations for the spheres whose centers and radii are given in Exercises \(51-54 .\) $$\frac{\text { Center }}{\left(-1, \frac{1}{2},-\frac{2}{3}\right)} \
View solution Problem 54
In Exercises \(53-56,\) find the point in which the line meets the plane. $$ x=2, \quad y=3+2 t, \quad z=-2-2 t ; \quad 6 x+3 y-4 z=-12 $$
View solution Problem 54
Find equations for the spheres whose centers and radii are given in Exercises \(51-54 .\) $$\frac{\text { Center }}{(0,-7,0)} \frac{\text { Radius }}{7}$$
View solution