Problem 53
Question
Find equations for the spheres whose centers and radii are given in Exercises \(51-54 .\) $$\frac{\text { Center }}{\left(-1, \frac{1}{2},-\frac{2}{3}\right)} \frac{\text { Radius }}{\frac{4}{9}}$$
Step-by-Step Solution
Verified Answer
The equation is \((x + 1)^2 + \left(y - \frac{1}{2}\right)^2 + \left(z + \frac{2}{3}\right)^2 = \frac{16}{81}\)."
1Step 1: Identify the Center and Radius of the Sphere
The exercise gives us the center of the sphere as \((-1, \frac{1}{2}, -\frac{2}{3})\) and the radius as \(\frac{4}{9}\).
2Step 2: Standard Equation of a Sphere
The standard equation for a sphere with center \((h, k, l)\) and radius \(r\) is given by: \[(x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\]
3Step 3: Substitute the Given Values
Substitute the center \((-1, \frac{1}{2}, -\frac{2}{3})\) and radius \(\frac{4}{9}\) into the standard equation: \[(x + 1)^2 + \left(y - \frac{1}{2}\right)^2 + \left(z + \frac{2}{3}\right)^2 = \left(\frac{4}{9}\right)^2\]
4Step 4: Simplify the Equation
Calculate the square of the radius \(\frac{4}{9}\): \[\left(\frac{4}{9}\right)^2 = \frac{16}{81}\]Thus, the final equation of the sphere will be: \[(x + 1)^2 + \left(y - \frac{1}{2}\right)^2 + \left(z + \frac{2}{3}\right)^2 = \frac{16}{81}\]
Key Concepts
Center of a SphereRadius of a Sphere3D Coordinate Geometry
Center of a Sphere
The center of a sphere is a crucial component in 3D coordinate geometry. It serves as the point from which every point on the sphere's surface is equidistant. In the exercise provided, the center of the sphere is given as \((-1, \frac{1}{2}, -\frac{2}{3})\). This set of coordinates represents the exact point in a three-dimensional space that is at the core of the sphere. We can think of this point as the sphere's 'home base'.
This center point is indicated by three coordinates \(h, k, l\), which define its position along the x, y, and z axes, respectively. Each axis corresponds to a dimension in space, helping to localize the position of the center within three-dimensional space:
This center point is indicated by three coordinates \(h, k, l\), which define its position along the x, y, and z axes, respectively. Each axis corresponds to a dimension in space, helping to localize the position of the center within three-dimensional space:
- \(h\) is the x-coordinate, which in this case is -1.
- \(k\) is the y-coordinate, here given as \(+\frac{1}{2}\).
- \(l\) is the z-coordinate, given as \(-\frac{2}{3}\).
Radius of a Sphere
The radius is another fundamental element in defining a sphere. It represents the distance from the center to any point on the surface of the sphere. In this exercise, the radius is given as \(\frac{4}{9}\). This means that every point along the surface of the sphere is exactly \(\frac{4}{9}\) units away from the center coordinate \((-1, \frac{1}{2}, -\frac{2}{3})\).
The significance of the radius lies in its role in determining the size of the sphere. Larger radii mean larger spheres and vice versa. Hence, it has a profound influence on the spatial extent of the sphere. Mathematically, the radius \(r\) appears in the equation of a sphere as \(r^2\), representing its squared value:
For example, the equation used was \[(x + 1)^2 + \left(y - \frac{1}{2}\right)^2 + \left(z + \frac{2}{3}\right)^2 = \frac{16}{81}\] where the right side \(\frac{16}{81}\) is \(\left(\frac{4}{9}\right)^2\).
Understanding how to determine and use the radius directly impacts how we visualize shapes in 3D space.
The significance of the radius lies in its role in determining the size of the sphere. Larger radii mean larger spheres and vice versa. Hence, it has a profound influence on the spatial extent of the sphere. Mathematically, the radius \(r\) appears in the equation of a sphere as \(r^2\), representing its squared value:
For example, the equation used was \[(x + 1)^2 + \left(y - \frac{1}{2}\right)^2 + \left(z + \frac{2}{3}\right)^2 = \frac{16}{81}\] where the right side \(\frac{16}{81}\) is \(\left(\frac{4}{9}\right)^2\).
Understanding how to determine and use the radius directly impacts how we visualize shapes in 3D space.
3D Coordinate Geometry
3D coordinate geometry is the study of points, lines, and shapes in a three-dimensional space. It expands on the familiar concepts of 2D coordinate geometry by adding a third z-dimension, allowing for a more comprehensive representation of objects like spheres.
In this context, the coordinates \(x, y, z\) define positions within this 3D space. Each point is a precise location that can be occupied by any geometric entity. When we talk about spheres, we use these coordinates to describe both the center and points on the surface.
In this context, the coordinates \(x, y, z\) define positions within this 3D space. Each point is a precise location that can be occupied by any geometric entity. When we talk about spheres, we use these coordinates to describe both the center and points on the surface.
- **Center**: Described by \(h, k, l\), it is the anchor point of the sphere.
- **Equation of Sphere**: The equation \((x - h)^2 + (y - k)^2 + (z - l)^2 = r^2\) leverages these coordinates to define every point on the sphere's surface.
Other exercises in this chapter
Problem 52
Find equations for the spheres whose centers and radii are given in Exercises \(51-54 .\) $$\frac{\text { Center }}{(0,-1,5)} \frac{\text { Radius }}{2}$$
View solution Problem 53
In Exercises \(53-56,\) find the point in which the line meets the plane. $$ x=1-t, \quad y=3 t, \quad z=1+t ; \quad 2 x-y+3 z=6 $$
View solution Problem 53
Let \(A B C D\) be a general, not necessarily planar, quadrilateral in space. Show that the two segments joining the midpoints of opposite sides of \(A B C D\)
View solution Problem 54
In Exercises \(53-56,\) find the point in which the line meets the plane. $$ x=2, \quad y=3+2 t, \quad z=-2-2 t ; \quad 6 x+3 y-4 z=-12 $$
View solution