Problem 53
Question
Find the slope and y-intercept of the line, and draw its graph. $$ 3 x-4 y=12 $$
Step-by-Step Solution
Verified Answer
Slope: \( \frac{3}{4} \), Y-intercept: \( -3 \). Graph the line using these values.
1Step 1: Rearrange the Equation into Slope-Intercept Form
The slope-intercept form of a line is given by \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. We start by rearranging the given equation \( 3x - 4y = 12 \) to this form. Subtract \( 3x \) from both sides to get \( -4y = -3x + 12 \). Then, divide every term by \(-4\) to solve for \( y \): \( y = \frac{3}{4}x - 3 \).
2Step 2: Identify the Slope and Y-Intercept
From the equation \( y = \frac{3}{4}x - 3 \), we can directly read off the slope and y-intercept. The slope \( m \) is \( \frac{3}{4} \) and the y-intercept \( b \) is \( -3 \).
3Step 3: Plot the Y-Intercept on the Graph
To draw the graph of the line, first plot the y-intercept. The point where the line crosses the y-axis is \( (0, -3) \). Place a point on the coordinate plane at this location.
4Step 4: Use the Slope to Plot Another Point
The slope of \( \frac{3}{4} \) means that for every 4 units you move to the right (along the x-axis), you move up 3 units (along the y-axis). Starting from \( (0, -3) \), move 4 units right and 3 units up to plot the second point at \( (4, 0) \).
5Step 5: Draw the Line
Connect the two points \( (0, -3) \) and \( (4, 0) \) with a straight line. Extend the line in both directions to cover the graph.
Key Concepts
Slope-Intercept FormLinear EquationsGraphing Lines
Slope-Intercept Form
Understanding the slope-intercept form is essential in algebra, especially when dealing with linear equations. The slope-intercept form of a line is expressed as \( y = mx + b \). This is a standard way of writing the equation of a line so that both the slope and the y-intercept are immediately apparent.
- \( m \) represents the slope. Think of this as the steepness or tilt of the line.
- \( b \) signifies the y-intercept, the point where the line crosses the y-axis.
Linear Equations
Linear equations appear as straight lines when graphed. They are algebraic expressions that represent lines, with each term being either a constant or a product of a constant and a variable. Standard forms of linear equations include the slope-intercept form, point-slope form, and standard form.
- The main feature of a linear equation is its constant rate of change, expressed by the slope.
- The equation itself can be manipulated to express this relationship explicitly, often making calculations and graphing easier.
Graphing Lines
Graphing lines involves using equations to draw a straight path through the coordinate plane. One of the first steps is identifying points that the line passes through. This often begins with determining the y-intercept and using the slope to find additional points.
- Start by plotting the y-intercept, an easy and direct point found in the slope-intercept equation.
- Utilize the slope to calculate another point by moving up or down and then left or right from the y-intercept.
- Draw a straight line through these points to visualize the equation.
Other exercises in this chapter
Problem 52
\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ x^{2}+(y-2)^{2}=4 $$
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Plot the points \(P(-2,1)\) and \(Q(12,-1)\) on a coordinate plane. Which (if either) of the points \(A(5,-7)\) and \(B(6,7)\) lies on the perpendicular bisecto
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\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ (x+3)^{2}+(y-4)^{2}=25 $$
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Plot the points \(P(-1,-4), Q(1,1),\) and \(R(4,2)\) on a coordinate plane. Where should the point \(S\) be located so that the figure \(P Q R S\) is a parallel
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