Problem 52
Question
Plot the points \(P(-2,1)\) and \(Q(12,-1)\) on a coordinate plane. Which (if either) of the points \(A(5,-7)\) and \(B(6,7)\) lies on the perpendicular bisector of the segment \(P Q ?\)
Step-by-Step Solution
Verified Answer
Point A(5, -7) lies on the perpendicular bisector of PQ.
1Step 1: Find the Midpoint of PQ
The midpoint, M, of a line segment with endpoints \( (x_1, y_1) \) and \( (x_2, y_2) \) is calculated by the formula: \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]. Substitute \( P(-2,1) \) and \( Q(12,-1) \) into the formula: \[ M = \left( \frac{-2 + 12}{2}, \frac{1 + (-1)}{2} \right) = (5, 0) \].
2Step 2: Find the Slope of PQ
The slope \( m \) of a line that passes through two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]. Substitute \( P(-2,1) \) and \( Q(12,-1) \) into the formula: \[ m = \frac{-1 - 1}{12 - (-2)} = \frac{-2}{14} = -\frac{1}{7} \].
3Step 3: Find the Slope of the Perpendicular Bisector
The slope of a line perpendicular to another is the negative reciprocal of the original slope. Thus, if the slope of \( PQ \) is \(-\frac{1}{7}\), the slope of the perpendicular bisector is \( 7 \).
4Step 4: Write the Equation of the Perpendicular Bisector
Using the point-slope form of a linear equation \( y - y_1 = m(x - x_1) \), where \((x_1, y_1)\) is the midpoint \(M(5,0)\) and the slope \(m = 7\), the equation is: \[ y - 0 = 7(x - 5) \], which simplifies to \[ y = 7x - 35 \].
5Step 5: Check if Point A Lies on the Perpendicular Bisector
Substitute point \( A(5, -7) \) into the equation \( y = 7x - 35 \): \(-7 = 7(5) - 35\), which simplifies to \(-7 = 35 - 35 \). This equation holds true, so point \( A \) lies on the perpendicular bisector.
6Step 6: Check if Point B Lies on the Perpendicular Bisector
Substitute point \( B(6, 7) \) into the equation \( y = 7x - 35 \): \( 7 = 7(6) - 35 \), which simplifies to \( 7 = 42 - 35 \). This does not hold true as \( 7 eq 7 \), so point \( B \) does not lie on the perpendicular bisector.
Key Concepts
Midpoint FormulaSlope of a LinePerpendicular BisectorPoint-Slope Form
Midpoint Formula
The midpoint formula is a crucial tool in coordinate geometry. It allows you to find the center point of a line segment that connects two points in a coordinate plane. To calculate the midpoint of a line segment, you simply take the average of the x-coordinates and the average of the y-coordinates of the endpoints.
For instance, if you have the points \( (-2, 1) \) and \( (12, -1) \), the midpoint \( M \) is given by the formula:
For instance, if you have the points \( (-2, 1) \) and \( (12, -1) \), the midpoint \( M \) is given by the formula:
- \( M = \left( \frac{-2 + 12}{2}, \frac{1 + (-1)}{2} \right) = (5, 0) \).
Slope of a Line
The slope of a line is a measure of its steepness or angle. It describes the rate at which y-values change relative to x-values along the line. The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is calculated with the formula:
For the segment connecting points \((-2, 1)\) and \( (12, -1)\), the slope is:
- \( m = \frac{y_2 - y_1}{x_2 - x_1} \).
For the segment connecting points \((-2, 1)\) and \( (12, -1)\), the slope is:
- \( m = \frac{-1 - 1}{12 - (-2)} = -\frac{1}{7} \).
Perpendicular Bisector
A perpendicular bisector is a line that cuts another line segment into two equal parts at a right angle. In coordinate geometry, finding the perpendicular bisector involves using the midpoint as a reference and calculating the slope that is the negative reciprocal of the original line's slope.
For a line segment with a slope of \(-\frac{1}{7}\), the slope of its perpendicular bisector becomes \(7\).
This relationship is fundamental in constructing bisectors for various geometric applications, such as triangle circumcenters or simulating symmetry. By incorporating the midpoint \((5, 0)\) into the point-slope form, we get the equation of the perpendicular bisector:
For a line segment with a slope of \(-\frac{1}{7}\), the slope of its perpendicular bisector becomes \(7\).
This relationship is fundamental in constructing bisectors for various geometric applications, such as triangle circumcenters or simulating symmetry. By incorporating the midpoint \((5, 0)\) into the point-slope form, we get the equation of the perpendicular bisector:
- \( y - 0 = 7(x - 5) \).
- \( y = 7x - 35 \).
Point-Slope Form
The point-slope form is a convenient way of writing the equation of a line when you know a point on the line and its slope. The general form is expressed as:
For example, using the midpoint \((5, 0)\) and a slope \(7\), the equation of the perpendicular bisector obtained is
- \( y - y_1 = m(x - x_1) \).
For example, using the midpoint \((5, 0)\) and a slope \(7\), the equation of the perpendicular bisector obtained is
- \( y - 0 = 7(x - 5) \).
- \( y = 7x - 35 \).
Other exercises in this chapter
Problem 52
Find the slope and y-intercept of the line, and draw its graph. $$ x=-5 $$
View solution Problem 52
\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ x^{2}+(y-2)^{2}=4 $$
View solution Problem 53
Find the slope and y-intercept of the line, and draw its graph. $$ 3 x-4 y=12 $$
View solution Problem 53
\(49-54\) . Find the center and radius of the circle, and sketch its graph. $$ (x+3)^{2}+(y-4)^{2}=25 $$
View solution