Problem 52
Question
Derive the subtraction formula for the tangent function.
Step-by-Step Solution
Verified Answer
\( \tan(A-B) = \frac{\tan(A) - \tan(B)}{1 + \tan(A)\tan(B)} \)
1Step 1: Understanding the Goal
We aim to deduce the formula for \( \tan(A-B) \) in terms of \( \tan(A) \) and \( \tan(B) \). This is known as the tangent subtraction formula.
2Step 2: Using the Tangent Identity
Recall that \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). Hence, \( \tan(A-B) = \frac{\sin(A-B)}{\cos(A-B)} \).
3Step 3: Apply Sine and Cosine Difference Identities
Utilize the identities \( \sin(A-B) = \sin(A)\cos(B) - \cos(A)\sin(B) \) and \( \cos(A-B) = \cos(A)\cos(B) + \sin(A)\sin(B) \).
4Step 4: Substitute the Difference Identities
Insert the sine and cosine difference identities into the tangent definition: \( \tan(A-B) = \frac{\sin(A)\cos(B) - \cos(A)\sin(B)}{\cos(A)\cos(B) + \sin(A)\sin(B)} \).
5Step 5: Express in Terms of Tangents
Replace the sine and cosine terms using \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). This gives: \( \tan(A) = \frac{\sin(A)}{\cos(A)} \) and \( \tan(B) = \frac{\sin(B)}{\cos(B)} \).
6Step 6: Simplification
Substitute \( \sin(A) = \tan(A)\cos(A) \) and \( \sin(B) = \tan(B)\cos(B) \) into the equation: \( \tan(A-B) = \frac{\tan(A)\cos(A)\cos(B) - \tan(B)\cos(A)\cos(B)}{\cos(A)\cos(B) + \tan(A)\tan(B)\cos(A)\cos(B)} \).
7Step 7: Final Expression Derivation
Factor out \( \cos(A)\cos(B) \) from both the numerator and the denominator: \( \tan(A-B) = \frac{\cos(A)\cos(B)[\tan(A) - \tan(B)]}{\cos(A)\cos(B)[1 + \tan(A)\tan(B)]} \).
8Step 8: Cancellation of Common Terms
Cancel out the common \( \cos(A)\cos(B) \) terms from the numerator and denominator, resulting in: \( \tan(A-B) = \frac{\tan(A) - \tan(B)}{1 + \tan(A)\tan(B)} \). This is the tangent difference formula.
Key Concepts
Tangent Subtraction FormulaSine and Cosine Difference IdentitiesTrigonometric SimplificationTangent Function
Tangent Subtraction Formula
The tangent subtraction formula is a fundamental trigonometric identity used to express the tangent of the difference between two angles. In its essence, it allows us to find the value of \( \tan(A-B) \) using the individual tangents \( \tan(A) \) and \( \tan(B) \). This formula is crucial for simplifying complex trigonometric expressions and solving problems that involve angle differences. The subtraction formula for tangent is given by:
- \( \tan(A-B) = \frac{\tan(A) - \tan(B)}{1 + \tan(A)\tan(B)} \)
Sine and Cosine Difference Identities
Sine and cosine difference identities are key tools employed in deriving the tangent subtraction formula. These identities help break down more complex expressions involving angle differences into combinations of sine and cosine functions. The identities include:
- \( \sin(A-B) = \sin(A)\cos(B) - \cos(A)\sin(B) \)
- \( \cos(A-B) = \cos(A)\cos(B) + \sin(A)\sin(B) \)
Trigonometric Simplification
Trigonometric simplification is the process of reducing complex trigonometric expressions to simpler, more manageable forms. This is particularly important when solving equations or proving identities. In the context of the tangent subtraction formula, simplification involves:
- Substituting equivalent expressions using trigonometric identities.
- Factoring common terms in the expression.
- Canceling like terms to derive a cleaner formula.
Tangent Function
The tangent function is one of the primary trigonometric functions, closely linked with the sine and cosine functions. It is defined as the ratio of the sine to the cosine of an angle: \( \tan(x) = \frac{\sin(x)}{\cos(x)} \). This unique relationship means that tangent can often be utilized to relate sine and cosine in various formulas, including the subtraction formula.The tangent function is periodic with a period of \( \pi \), meaning it repeats its values over intervals of \( \pi \). It is also important to note that tangent has asymptotes where \( \cos(x) = 0 \) because it makes the function undefined at those points. When applying the subtraction formula, the properties of the tangent function ensure that we can handle angle differences effectively by leveraging its relationship with sine and cosine.
Other exercises in this chapter
Problem 52
Exer. 39-62: Find the solutions of the equation that are in the interval \([0,2 \pi\) ). $$ \cos \theta-\sin \theta=1 $$
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Exer. 51-60: Show that the equation is not an identity. (Hint: Find one number for which the equation is false.) $$ \sqrt{\sin ^{2} t+\cos ^{2} t}=\sin t+\cos t
View solution Problem 53
Exer. 53-64: Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four dec
View solution Problem 53
Exer. 39-62: Find the solutions of the equation that are in the interval \([0,2 \pi\) ). $$ \cos \alpha+\sin \alpha=1 $$
View solution