Problem 51
Question
Use a graphing calculator to graph each equation. $$ x^{2}+y^{2}=7 $$
Step-by-Step Solution
Verified Answer
Graph the circle centered at (0,0) with a radius of approximately 2.65.
1Step 1: Identify the Equation Type
The given equation is in the form of \[ x^2 + y^2 = r^2 \]which is the standard form of a circle centered at the origin \((0,0)\) with radius \(r\).
2Step 2: Calculate the Radius
From the equation \[ x^2 + y^2 = 7 \]we see that\( r^2 = 7 \).Thus, the radius \( r \) is \( \sqrt{7} \approx 2.65 \).
3Step 3: Input Equation into Graphing Calculator
Access the graphing function on your graphing calculator. Input the equation \[ x^2 + y^2 = 7 \]which represents a circle.
4Step 4: Graph the Equation
Plot the equation on the graphing calculator. You should see a circle centered at the origin \((0,0)\) with a radius of approximately 2.65.
Key Concepts
Equation of a CircleRadius CalculationStandard Form
Equation of a Circle
When you're dealing with the equation of a circle, it's important to recognize its specific form. A circle's equation is typically written as \( (x - h)^2 + (y - k)^2 = r^2 \), where \((h, k)\) represents the center of the circle and \(r\) is the circle's radius.
In the special case where the circle is centered at the origin, which means \((h, k) = (0, 0)\), the equation simplifies to \(x^2 + y^2 = r^2\).
This simplified form is what we have here: \(x^2 + y^2 = 7\).
In the special case where the circle is centered at the origin, which means \((h, k) = (0, 0)\), the equation simplifies to \(x^2 + y^2 = r^2\).
This simplified form is what we have here: \(x^2 + y^2 = 7\).
- The expression \(x^2\) involves the horizontal distance from the center.
- The expression \(y^2\) involves the vertical distance from the center.
Radius Calculation
Understanding how to calculate the radius from the circle's equation is crucial.
To find the radius, look at \(r^2\) in the equation \(x^2 + y^2 = r^2\).
From \(x^2 + y^2 = 7\), we can see that \(r^2 = 7\).
To find \(r\), simply take the square root of both sides ---- \(r = \sqrt{7}\).
This process reveals that the radius of our circle is \(\sqrt{7} \approx 2.65\).
To find the radius, look at \(r^2\) in the equation \(x^2 + y^2 = r^2\).
From \(x^2 + y^2 = 7\), we can see that \(r^2 = 7\).
To find \(r\), simply take the square root of both sides ---- \(r = \sqrt{7}\).
This process reveals that the radius of our circle is \(\sqrt{7} \approx 2.65\).
- The square root transformation is key to translating \(r^2\) into \(r\).
- It's important to note that the radius is always a positive value as it represents a distance.
Standard Form
The standard form of a circle's equation is a powerful tool in geometry and algebra.
It provides a straightforward way to understand and graph circles.
For example, the standard form \( (x - h)^2 + (y - k)^2 = r^2 \) directly tells us about the circle's center \((h, k)\) and radius \(r\).
Understanding the standard form also makes it easier to translate between different mathematical representations, such as shifting a circle from one location to another on a coordinate plane.
It provides a straightforward way to understand and graph circles.
For example, the standard form \( (x - h)^2 + (y - k)^2 = r^2 \) directly tells us about the circle's center \((h, k)\) and radius \(r\).
- If \(h = 0\) and \(k = 0\), as in \(x^2 + y^2 = 7\), the circle is centered at the origin.
- The equation \((x - h)^2 + (y - k)^2 = r^2\) provides all the necessary information to plot the circle on a graph.
Understanding the standard form also makes it easier to translate between different mathematical representations, such as shifting a circle from one location to another on a coordinate plane.
Other exercises in this chapter
Problem 51
Solve each system of equations for real values of \(x\) and \(y.\) $$ \left\\{\begin{array}{l} x^{2}-y=0 \\ x^{2}-4 x+y=0 \end{array}\right. $$
View solution Problem 51
Write each equation in standard form, if it is not already so, and graph it. The problems include equations that describe circles, parabolas, ellipses, and hype
View solution Problem 52
Solve each system of equations for real values of \(x\) and \(y.\) $$ \left\\{\begin{array}{l} x y=-\frac{9}{2} \\ 3 x+2 y=6 \end{array}\right. $$
View solution Problem 52
Use a graphing calculator to graph each equation. $$ x^{2}+y^{2}=5 $$
View solution