Problem 50
Question
Verify the Identity. $$\ln |\csc x-\cot x|=-\ln |\csc x+\cot x|$$
Step-by-Step Solution
Verified Answer
The identity is verified by showing the logarithms sum to zero, confirming they are negatives.
1Step 1: Understand the Problem
We need to verify that the given identity holds true. The identity states that \( \ln |\csc x - \cot x| = -\ln |\csc x + \cot x| \). This means that the logarithms of two expressions involving cosecant and cotangent are negatives of each other.
2Step 2: Simplify the Expression
Let's start by simplifying \( \ln |\csc x - \cot x| \). Using the Pythagorean identity \( \csc^2 x - \cot^2 x = 1 \), we can express \( \csc x - \cot x \) and \( \csc x + \cot x \) as conjugates such that their product is 1: \((\csc x - \cot x)(\csc x + \cot x) = (\csc^2 x - \cot^2 x) = 1\).
3Step 3: Use Logarithmic Properties
Utilize the logarithmic property that \( \ln(a) + \ln(b) = \ln(ab) \). Therefore, if \( \csc x - \cot x \) and \( \csc x + \cot x \) are such that \((\csc x - \cot x)(\csc x + \cot x) = 1\), then \( \ln |\csc x - \cot x| + \ln |\csc x + \cot x| = \ln 1 = 0 \).
4Step 4: Rearrange the Expression
From Step 3, we have \( \ln |\csc x - \cot x| + \ln |\csc x + \cot x| = 0 \). Rearrange this to find \( \ln |\csc x - \cot x| = -\ln |\csc x + \cot x| \), which matches the given identity.
5Step 5: Conclusion: Verify the Identity
We showed that the expression \( \ln |\csc x - \cot x| = -\ln |\csc x + \cot x| \) is true by utilizing properties of logarithms and trigonometric identities.
Key Concepts
Trigonometric IdentitiesPythagorean IdentityCosecant and CotangentProperties of Logarithms
Trigonometric Identities
Trigonometric identities are equations that relate the angles and lengths of triangles, primarily for the six trigonometric functions: sine (\( \sin \)), cosine (\( \cos \)), tangent (\( \tan \)), cosecant (\( \csc \)), secant (\( \sec \)), and cotangent (\( \cot \)). These identities are essential for simplifying complex trigonometric expressions and solving equations.
- **Basic Identities**: These include \( \sin^2 x + \cos^2 x = 1 \), \( \tan x = \frac{\sin x}{\cos x }\), and \( \csc x = \frac{1}{\sin x}\).
- **Reciprocal Identities**: Such as \( \csc x = \frac{1}{\sin x} \) and \( \cot x = \frac{1}{\tan x} \).
- **Pythagorean Identities**: These are extensions of the Pythagorean theorem, like \( \csc^2 x - \cot^2 x = 1 \).
Pythagorean Identity
The Pythagorean identity refers to a set of fundamental equations that are derived from the Pythagorean theorem. Most commonly known is:\[ \sin^2 x + \cos^2 x = 1 \]For cosecant and cotangent, we rely on the identity:\[ \csc^2 x - \cot^2 x = 1 \]This identity can be viewed as a rearrangement of the fundamental Pythagorean theorem applied to the unit circle.
- **Application**: This identity is useful for transforming trigonometric expressions and plays a key role in our example where we expand \((\csc x - \cot x)(\csc x + \cot x)\) into 1, verifying the original identity.It demonstrates how expressions involving trigonometric functions can multiply to give simple values, facilitating easier manipulation and simplification of equations.
- **Application**: This identity is useful for transforming trigonometric expressions and plays a key role in our example where we expand \((\csc x - \cot x)(\csc x + \cot x)\) into 1, verifying the original identity.It demonstrates how expressions involving trigonometric functions can multiply to give simple values, facilitating easier manipulation and simplification of equations.
Cosecant and Cotangent
The cosecant (\( \csc x \)) and cotangent (\( \cot x \)) functions are reciprocal trigonometric functions.
Their interplay through identities like the Pythagorean identity aids in establishing that their product \((\csc x - \cot x)(\csc x + \cot x) = 1\), crucial for the logarithmic property used in the solution.
- **Cosecant Function**: Defined as \( \csc x = \frac{1}{\sin x} \). It is the reciprocal of the sine function.
- **Cotangent Function**: Defined as \( \cot x = \frac{1}{\tan x} \) or equivalently \( \cot x = \frac{\cos x}{\sin x} \). It is the reciprocal of the tangent function.
Their interplay through identities like the Pythagorean identity aids in establishing that their product \((\csc x - \cot x)(\csc x + \cot x) = 1\), crucial for the logarithmic property used in the solution.
Properties of Logarithms
Logarithms have several properties that are crucial for solving equations involving them.
- **Product Property**: \( \ln(a) + \ln(b) = \ln(ab) \). This property states that the log of a product is the sum of the logs.
- **Identity for Zero**: \( \ln 1 = 0 \). Since any number to the power of 0 is 1, the logarithm of 1 is always 0.
- **Negative Property**: \( \ln(a) = -\ln(\frac{1}{a}) \). This property shows that the logarithm of a reciprocal is the negative of the logarithm.
Other exercises in this chapter
Problem 49
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$\sin ^{2} \theta+\sin \theta-6=0$$
View solution Problem 50
Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$y=6-3 \cos x ; \quad[0, \pi]$$
View solution Problem 50
If \(\alpha\) and \(\beta\) are complementary angles, show that $$ \sin ^{2} \alpha+\sin ^{2} \beta=1 $$
View solution Problem 50
Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$2 \sin ^{2} u+\sin u-6=0$$
View solution