Problem 50
Question
If \(\alpha\) and \(\beta\) are complementary angles, show that $$ \sin ^{2} \alpha+\sin ^{2} \beta=1 $$
Step-by-Step Solution
Verified Answer
The angles are complementary, so \(\sin^2 \alpha + \sin^2 \beta = 1\) using trigonometric identities.
1Step 1: Understanding Complementary Angles
Two angles are complementary if their sum is 90°. This means if the measure of one angle is \(\alpha\), then the other angle \(\beta\) is given by \(\beta = 90° - \alpha\).
2Step 2: Using the Complementary Angle Identity
The identity \(\sin(90° - x) = \cos(x)\) can be applied to complementary angles. For angle \(\beta\), use: \(\sin(\beta) = \sin(90° - \alpha) = \cos(\alpha)\).
3Step 3: Square and Sum the Sine Functions
We are tasked to prove \(\sin^2 \alpha + \sin^2 \beta = 1\). Using the identity from the previous step, \(\sin^2 \beta = \cos^2 \alpha\). Thus, the expression becomes \(\sin^2 \alpha + \cos^2 \alpha\).
4Step 4: Apply the Pythagorean Identity
According to the Pythagorean Identity, \(\sin^2 \alpha + \cos^2 \alpha = 1\). Since we have arrived at this identity, \(\sin^2 \alpha + \sin^2 \beta\) indeed equals 1.
Key Concepts
Trigonometric IdentitiesSine and Cosine FunctionsPythagorean Identity
Trigonometric Identities
Trigonometric identities are fundamental equations involving the trigonometric functions that are true for every value of the variables involved. These identities help us solve complex trigonometric problems more easily.
One of the key identities used in solving problems with complementary angles is the Complementary Angle Identity. This states that the sine of one angle is equal to the cosine of its complement. Expressed mathematically, it is written as follows:
One of the key identities used in solving problems with complementary angles is the Complementary Angle Identity. This states that the sine of one angle is equal to the cosine of its complement. Expressed mathematically, it is written as follows:
- \( \sin(90° - x) = \cos(x) \)
Sine and Cosine Functions
The sine and cosine functions are two of the most essential functions in trigonometry. They describe the relationships of the angles of a triangle to the lengths of its sides in the context of a right triangle. Understanding these
For complementary angles \( \alpha \) and \( \beta \), the important identity is that \( \sin(\beta) \) equals \( \cos(\alpha) \). This fundamentally connects these functions when dealing with right triangles and their angles.
- The sine function (\( \sin(x) \)) relates a given angle to the ratio of the opposite side to the hypotenuse.
- The cosine function (\( \cos(x) \)) is the ratio of the adjacent side to the hypotenuse.
For complementary angles \( \alpha \) and \( \beta \), the important identity is that \( \sin(\beta) \) equals \( \cos(\alpha) \). This fundamentally connects these functions when dealing with right triangles and their angles.
Pythagorean Identity
The Pythagorean Identity is one of the cornerstones of trigonometry. Derived from the Pythagorean theorem, it connects the sine and cosine functions together in a powerful relationship:
In the context of complementary angles like \( \alpha \) and \( \beta \), we see its strength. By expressing \( \sin^2(\beta) \) as \( \cos^2(\alpha) \), we ultimately demonstrate that \( \sin^2(\alpha) + \sin^2(\beta) = 1 \) through this very identity. Always count on the Pythagorean identity when you need to transition between squares of these functions.
- \( \sin^2(x) + \cos^2(x) = 1 \)
In the context of complementary angles like \( \alpha \) and \( \beta \), we see its strength. By expressing \( \sin^2(\beta) \) as \( \cos^2(\alpha) \), we ultimately demonstrate that \( \sin^2(\alpha) + \sin^2(\beta) = 1 \) through this very identity. Always count on the Pythagorean identity when you need to transition between squares of these functions.
Other exercises in this chapter
Problem 50
Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$y=6-3 \cos x ; \quad[0, \pi]$$
View solution Problem 50
Verify the Identity. $$\ln |\csc x-\cot x|=-\ln |\csc x+\cot x|$$
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Find the solutions of the equation that are in the interval \([0,2 \pi)\). $$2 \sin ^{2} u+\sin u-6=0$$
View solution Problem 51
Solve the equation for \(x\) in terms of \(y\) if \(0
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