Problem 50
Question
Solve each equation by completing the square. $$ 3 x^{2}-4 x=4 $$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 2\) and \(x = -\frac{2}{3}\).
1Step 1: Move the Constant Term
First, move the constant term on the right-hand side to the left-hand side. Subtract 4 from both sides: \[ 3x^2 - 4x - 4 = 0 \].
2Step 2: Divide by the Leading Coefficient
To make the coefficient of \(x^2\) equal to 1, divide every term in the equation by 3: \[ x^2 - \frac{4}{3}x - \frac{4}{3} = 0 \].
3Step 3: Move the Constant Term Again
Move the constant term to the right-hand side by adding \(\frac{4}{3}\) to both sides: \[ x^2 - \frac{4}{3}x = \frac{4}{3} \].
4Step 4: Complete the Square
To complete the square, take half of the coefficient of x (\(-\frac{4}{3}\)), square it, and add it to both sides. Half of \(-\frac{4}{3}\) is \(-\frac{2}{3}\). Squaring \(-\frac{2}{3}\) gives \(\frac{4}{9}\): \[ x^2 - \frac{4}{3}x + \frac{4}{9} = \frac{4}{3} + \frac{4}{9} \].
5Step 5: Simplify and Express as a Square
Combine the terms on the right-hand side. The common denominator is 9, so: \[ \frac{4}{3} = \frac{12}{9} \rightarrow \frac{12}{9} + \frac{4}{9} = \frac{16}{9} \]. Write the left side as a perfect square: \[ \left(x - \frac{2}{3}\right)^2 = \frac{16}{9} \].
6Step 6: Solve for x
Take the square root of both sides to solve for \(x\): \[ x - \frac{2}{3} = \pm \frac{4}{3} \]. This gives two solutions: \( x = \frac{2}{3} + \frac{4}{3} \) and \( x = \frac{2}{3} - \frac{4}{3}\).
7Step 7: Simplify the Solutions
Simplify each solution: for \( x = \frac{2}{3} + \frac{4}{3} \), you get \( x = 2 \); for \( x = \frac{2}{3} - \frac{4}{3} \), you get \( x = -\frac{2}{3} \).
Key Concepts
Quadratic EquationsAlgebraic ManipulationSolving Equations
Quadratic Equations
Quadratic equations are polynomial equations of degree two, which generally take the form of \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) are constants, and \( x \) represents the variable. These equations often result in parabolas when graphed on the coordinate plane.
Understanding quadratic equations is crucial as they frequently appear in various mathematical and real-world applications.
Understanding quadratic equations is crucial as they frequently appear in various mathematical and real-world applications.
- Standard Form: As mentioned, the quadratic equation in its standard form is \( ax^2 + bx + c = 0 \).
- Roots: The solutions to the quadratic equation, also called roots, can be real or complex numbers. They are the x-values where the parabola intersects the x-axis.
Algebraic Manipulation
Algebraic Manipulation is the skill of rearranging and simplifying algebraic expressions to make equations easier to work with. It’s like solving a puzzle, where the goal is to isolate the variable or make the equation more manageable.
The process of completing the square involves several algebraic manipulations:
The process of completing the square involves several algebraic manipulations:
- Moving Terms: Initially, you often move constants or known terms from one side to the other to prepare the equation for further simplification.
- Dividing by Coefficients: Dividing the entire equation by the leading coefficient (the coefficient of \( x^2 \)) helps simplify the equation and makes completing the square straightforward.
- Balancing the Equation: Whatever operation is done to one side of the equation must be performed on the other side to maintain equality.
Solving Equations
Solving equations can be thought of as a process of finding the values that satisfy a given equation. For quadratic equations, solving them means finding the values of \( x \) that make the equation true, essentially the points where the function crosses the x-axis on a graph.
Here is how solving was approached in the given exercise:
Here is how solving was approached in the given exercise:
- Completing the Square: By transforming the left side into a perfect square trinomial, the equation becomes easier to solve using square roots.
- Taking Square Roots: Once the equation is in the form of \((x - d)^2 = e\), you can take the square root of both sides to find \( x \), which results in two possible solutions due to the \( \pm \) sign.
- Simplifying: After taking the square root and rearranging, simplify the solutions to their simplest numerical form.
Other exercises in this chapter
Problem 50
Solve. See Examples 1 through 5. $$ x^{4}-10 x^{2}+9=0 $$
View solution Problem 50
Without calculating, tell whether each graph has a minimum value or a maximum value. See the Concept Check in the section. $$ G(x)=3-\frac{1}{2} x+0.8 x^{2} $$
View solution Problem 50
Write the equation of the parabola that has the same shape as \(f(x)=5 x^{2}\) but with the given vertex. Call each function \(g(x) .\) $$ (4,-1) $$
View solution Problem 51
Solve each inequality. Write the solution set in interval notation. $$ \frac{z}{z-5} \geq 2 z $$
View solution