Problem 50
Question
For the following exercises, solve each equation for \(x\). \(\log _{3}(3 x)-\log _{3}(6)=\log _{3}(77)\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 154\).
1Step 1: Apply Logarithm Property
We start by using the properties of logarithms. The equation is: \(\log_{3}(3x) - \log_{3}(6) = \log_{3}(77)\).The difference of two logarithms can be expressed as the logarithm of a quotient: \(\log_{3}\left(\frac{3x}{6}\right) = \log_{3}(77)\).
2Step 2: Simplify the Quotient
Now simplify the expression inside the logarithm on the left side:\(\log_{3}\left(\frac{3x}{6}\right)\) simplifies to \(\log_{3}\left(\frac{x}{2}\right)\).So, the equation becomes: \(\log_{3}\left(\frac{x}{2}\right) = \log_{3}(77)\).
3Step 3: Equate the Arguments
Since the bases of the logarithms are the same, we can equate the arguments:\(\frac{x}{2} = 77\).
4Step 4: Solve for x
To solve for \(x\), multiply both sides by 2:\(x = 77 \times 2\).Thus, \(x = 154\).
Key Concepts
Understanding Logarithm PropertiesSimplifying Expressions Inside LogarithmsEquating the Arguments of LogarithmsAlgebraic Manipulation to Solve for the Variable
Understanding Logarithm Properties
To solve equations involving logarithms, it's crucial to understand the basic properties they possess. Logarithms convert multiplicative relationships into additive ones, and this feature is what makes them so powerful. In our equation, we have a case where we can use the property that allows us to express the subtraction of two logarithms as a single logarithm of a quotient:
- If you have an equation of the form \[\log_b(A) - \log_b(B) = \log_b(C)\], this can be rewritten as \[\log_b\left(\frac{A}{B}\right) = \log_b(C)\]
- This transformation is based on one of the key logarithm properties: \[\log_b\left(\frac{A}{B}\right) = \log_b(A) - \log_b(B)\]
Simplifying Expressions Inside Logarithms
Once we've applied the logarithm property to convert the equation into a single logarithm, our next step is simplifying the expression within this logarithm. In our example, we transformed the equation to:\[\log_3\left(\frac{3x}{6}\right) = \log_3(77)\]By dividing inside the logarithm, we simplify \(\frac{3x}{6}\) to \(\frac{x}{2}\). This is a vital step because it often simplifies the problem dramatically, reducing complex expressions into simpler forms:
- Simplifying \[\log_3\left(\frac{3x}{6}\right)\] provides us \[\log_3\left(\frac{x}{2}\right)\]
- This simplification helps in making the equation more approachable for solving
Equating the Arguments of Logarithms
With the simplified equations in hand, where both sides of the logarithm equation share the same base, we can use another logarithm property to simplify further:
- If \[\log_b(M) = \log_b(N)\], then \[M = N\]
- Equate \[\frac{x}{2} = 77\]
- This step directly simplifies logarithmic equations into a manageable algebraic form
Algebraic Manipulation to Solve for the Variable
After equating the arguments of both sides of the equation, we are left with a simple algebraic equation to solve. We use basic algebraic manipulation to find the value of \(x\):
- Start by isolating \(x\) in the equation \[\frac{x}{2} = 77\]
- Multiply both sides by 2 to solve for \(x\): \[x = 77 \times 2\]
- Calculate to find \[x = 154\]
Other exercises in this chapter
Problem 49
For the following exercises, evaluate each function. Round answers to four decimal places, if necessary. \(f(x)=1.2 e^{2 x}-0.3,\) for \(f(3)\)
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For the following exercises, use this scenario: The equation \(N(t)=\frac{500}{1+49 e^{-0.7 t}}\) models the number of people in a town who have heard a rumor a
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For the following exercises, evaluate the natural logarithmic expression without using a calculator. \(\ln \left(e^{\frac{1}{3}}\right)\)
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For the following exercises, use a graphing calculator to approximate the solutions of the equation. Round to the nearest thousandth. \(-30=-4(2)^{x+2}+2\)
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