Problem 50
Question
For the following exercises, evaluate the natural logarithmic expression without using a calculator. \(\ln \left(e^{\frac{1}{3}}\right)\)
Step-by-Step Solution
Verified Answer
The expression evaluates to \( \frac{1}{3} \).
1Step 1: Identify Components
The expression given is \( \ln \left(e^{\frac{1}{3}}\right) \). Here, we need to evaluate the natural logarithm of an exponential expression. In this case, the base of the logarithm is the natural number \( e \), and the exponent of \( e \) is \( \frac{1}{3} \).
2Step 2: Apply the Property of Logarithms
Natural logarithms have a particular property: \( \ln \left( e^x \right) = x \). This is because the natural logarithm is the inverse of the exponential function with base \( e \). In our expression, \( e^x = e^{\frac{1}{3}} \), so \( x = \frac{1}{3} \).
3Step 3: Simplify the Expression
Using the property \( \ln(e^x) = x \), we simplify \( \ln \left(e^{\frac{1}{3}}\right) \) to \( \frac{1}{3} \). This simplification is direct because the logarithm and the exponential function cancel each other out.
Key Concepts
Exponential FunctionLogarithm PropertiesInverse Functions
Exponential Function
The exponential function is a fundamental mathematical concept where a constant base is raised to a variable exponent. In most cases, the base is the natural number \( e \), approximately equal to 2.71828. When we write \( e^x \), it represents an exponential growth if \( x \) is positive or a decay if \( x \) is negative. The exponential function is particularly interesting because it has a continuous growth rate proportional to its value.
Understanding the exponential function is crucial in various fields like finance, biology, and physics, where growth processes are modeled. For example:
Understanding the exponential function is crucial in various fields like finance, biology, and physics, where growth processes are modeled. For example:
- Population growth in biology often follows an exponential pattern.
- Interest compounding in finance is based on exponential functions.
Logarithm Properties
Logarithms are the inverse operations of exponentials, much like subtraction is the inverse of addition. The natural logarithm, denoted as \( \ln \), uses the base \( e \). The basic property of logarithms is \( \ln\left(e^x\right) = x \), showing the direct relationship between logarithms and exponential terms.
Some important properties include:
Some important properties include:
- Product Property: \( \ln(ab) = \ln(a) + \ln(b) \).
- Quotient Property: \( \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \).
- Power Property: \( \ln(a^b) = b \ln(a) \).
Inverse Functions
Inverse functions are operations that "undo" each other. For instance, if addition is done by one function, subtraction will be its inverse. In the world of exponential functions and logarithms, the natural logarithm \( \ln \) is the inverse of the exponential function \( e^x \). This means applying these functions successively will cancel each other out, yielding the original input.
For example, if we have an expression \( \ln(e^x) \), it simplifies directly to \( x \) because the logarithm "undoes" the exponentiation. This is a powerful tool in mathematics as:
For example, if we have an expression \( \ln(e^x) \), it simplifies directly to \( x \) because the logarithm "undoes" the exponentiation. This is a powerful tool in mathematics as:
- It helps solve equations where the variable is in the exponent.
- It makes complex exponential relationships more tractable by turning them into linear forms.
Other exercises in this chapter
Problem 50
For the following exercises, use this scenario: The equation \(N(t)=\frac{500}{1+49 e^{-0.7 t}}\) models the number of people in a town who have heard a rumor a
View solution Problem 50
For the following exercises, solve each equation for \(x\). \(\log _{3}(3 x)-\log _{3}(6)=\log _{3}(77)\)
View solution Problem 50
For the following exercises, use a graphing calculator to approximate the solutions of the equation. Round to the nearest thousandth. \(-30=-4(2)^{x+2}+2\)
View solution Problem 50
For the following exercises, evaluate each function. Round answers to four decimal places, if necessary. \(f(x)=-\frac{3}{2}(3)^{-x}+\frac{3}{2},\) for \(f(2)\)
View solution