Problem 50
Question
Convert the polar equation to rectangular coordinates. $$ r=6 \cos \theta $$
Step-by-Step Solution
Verified Answer
The rectangular form is \\(x^2 - 6x + y^2 = 0\\) or \\( (x-3)^2 + y^2 = 9\\).
1Step 1: Understand Polar and Rectangular Coordinates
In polar coordinates, a point is represented by \(r, \theta\), where \(r\) is the distance from the origin and \(\theta\) is the angle from the positive x-axis. To convert to rectangular coordinates \(x, y\), use the conversions \(x = r \cos \theta\) and \(y = r \sin \theta\).
2Step 2: Substitute Polar Equation into Rectangular Formula
Our given equation is \(r = 6 \cos \theta\). Multiply both sides by \(r\): \[ r^2 = 6r \cos \theta \]
3Step 3: Use Rectangular Conversion Formula
Recall that \(r^2 = x^2 + y^2\) and \(r \cos \theta = x\). Substitute these into the equation: \[ x^2 + y^2 = 6x \]
4Step 4: Rearrange to Rectangular Equation Form
Rearrange the equation to place all terms on one side: \[ x^2 - 6x + y^2 = 0 \]
5Step 5: Complete the Square (Optional)
If needed, complete the square for the \(x\) terms to further simplify or analyze the equation: Add and subtract \(9\) (which is \(\left( \frac{6}{2} \right)^2\)) to the equation: \[(x-3)^2 + y^2 = 9\]This represents a circle with center (3, 0) and radius 3.
Key Concepts
Polar CoordinatesRectangular CoordinatesCoordinate TransformationEquation Conversion
Polar Coordinates
Polar coordinates offer a unique way of representing points in a plane through a combination of distance and direction. In this system, every point is described by two values: \( r \) and \( \theta \).
- \( r \) represents the distance from the origin (like the radius of a circle).
- \( \theta \) denotes the angle measured from the positive x-axis.
Rectangular Coordinates
Rectangular coordinates are the more traditional way of plotting points on a graph, utilizing horizontal and vertical distances. These are denoted as \((x, y)\).
- \( x \): The horizontal distance from the y-axis (positive towards the right).
- \( y \): The vertical distance from the x-axis (positive upwards).
Coordinate Transformation
Switching between polar and rectangular coordinates is a valuable technique, especially in mathematical fields where different perspectives or angles help clarify relationships.
- To transform from polar to rectangular, use:
- \( x = r \cos \theta \)
- \( y = r \sin \theta \)
- Conversely, for transforming from rectangular to polar, use:
- \( r = \sqrt{x^2 + y^2} \)
- \( \theta = \tan^{-1}(y/x) \)
Equation Conversion
When converting an equation from polar to rectangular coordinates, like the original exercise \( r = 6 \cos \theta \), you substitute polar terms with their rectangular equivalents.
- Inicio: Multiply both sides by \( r \) yielding \( r^2 = 6r \cos \theta \).
- Step: Replace terms using known conversions. For example, use \( r^2 = x^2 + y^2 \) and \( r \cos \theta = x \).
- Resultados: Simplify into a typical rectangular equation, such as \( x^2 + y^2 = 6x \).
- Further: Optional simplification steps, like completing the square, reveal useful information (e.g., circles, ellipses).
Other exercises in this chapter
Problem 49
47–50 Sketch a graph of the rectangular equation. [Hint: First convert the equation to polar coordinates.] $$\left(x^{2}+y^{2}\right)^{2}=x^{2}-y^{2}$$
View solution Problem 50
Velocity A woman walks due west on the deck of an ocean liner at 2 milh. The ocean liner is moving due north at a speed of 25 \(\mathrm{mi} / \mathrm{h}\) . Fin
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\(49-56\) me product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\) . Express your answer in polar form. $$ z_{1}=\cos \frac{\pi}{4}+i \sin \frac{\pi}{4}, \
View solution Problem 50
47–50 Sketch a graph of the rectangular equation. [Hint: First convert the equation to polar coordinates.] $$x^{2}+y^{2}=\left(x^{2}+y^{2}-x\right)^{2}$$
View solution