Problem 49
Question
47–50 Sketch a graph of the rectangular equation. [Hint: First convert the equation to polar coordinates.] $$\left(x^{2}+y^{2}\right)^{2}=x^{2}-y^{2}$$
Step-by-Step Solution
Verified Answer
The polar graph of the equation resembles a rose with four petals.
1Step 1: Convert Rectangular to Polar Coordinates
In polar coordinates, we know that \( x = r\cos\theta \) and \( y = r\sin\theta \). Substituting these into the equation \( (x^{2}+y^{2})^{2}=x^{2}-y^{2} \), we get:\( (r^{2})^{2} = (r\cos\theta)^{2} - (r\sin\theta)^{2} \).Simplify to get:\( r^{4} = r^{2}\cos^{2}\theta - r^{2}\sin^{2}\theta \) which simplifies to \( r^{4} = r^{2} (\cos^{2}\theta - \sin^{2}\theta) \).
2Step 2: Simplify the Polar Equation
Factor and simplify the polar equation:Divide both sides by \( r^{2} \) (assuming \( r eq 0 \)):\( r^{2} = \cos^{2}\theta - \sin^{2}\theta \).Recall that \( \cos^{2}\theta - \sin^{2}\theta = \cos(2\theta) \). So we have:\( r^{2} = \cos(2\theta) \).Thus, \( r = \pm \sqrt{\cos(2\theta)} \).
3Step 3: Analyze the Polar Equation
In the polar form \( r = \pm \sqrt{\cos(2\theta)} \), graphically analyze the equation to understand the shape.The equation stipulates that \( r \) is real only when \( \cos(2\theta) \geq 0 \), which implies that \( 2\theta \) must be in the range where \( \cos \) is non-negative, i.e., in intervals \([0, \frac{\pi}{2}]) \cup [\pi, \frac{3\pi}{2}]\).
4Step 4: Sketch the Graph Based on Analysis
Within the valid ranges of \( 2\theta \), the values of \( r \) alternate between positive and negative, forming symmetrical lobes.Reflect the structure of the polar plot in the Cartesian plane corresponding to these specific \( 2\theta \) ranges.The polar graph has symmetry and reflects around the origin with lobes appearing along the axis in the specified ranges due to the periodicity of cosine.
Key Concepts
Rectangular to Polar ConversionGraphing Polar EquationsSymmetry in Polar Graphs
Rectangular to Polar Conversion
Converting from rectangular to polar coordinates is a useful skill in mathematics, especially when dealing with certain types of graphs or equations that are more easily expressed in polar form. The key relationships to note are:
To convert a rectangular equation into a polar equation, substitute these expressions for \(x\) and \(y\). For example, in our equation \((x^{2} + y^{2})^{2} = x^{2} - y^{2} \), substituting the polar equivalents results in an equation that can be simplified further. This simplification often reveals symmetry or periodic behavior that is not immediately apparent in the rectangular form.
Understanding these conversions is crucial when you need to sketch or analyze graphs that are easier to manage in the polar format.
- \( x = r\cos\theta \)
- \( y = r\sin\theta \)
To convert a rectangular equation into a polar equation, substitute these expressions for \(x\) and \(y\). For example, in our equation \((x^{2} + y^{2})^{2} = x^{2} - y^{2} \), substituting the polar equivalents results in an equation that can be simplified further. This simplification often reveals symmetry or periodic behavior that is not immediately apparent in the rectangular form.
Understanding these conversions is crucial when you need to sketch or analyze graphs that are easier to manage in the polar format.
Graphing Polar Equations
Graphing polar equations is an intriguing exercise that often results in beautiful and complex shapes. Once an equation is simplified in polar form, like \( r = \pm \sqrt{\cos(2\theta)} \), the next step is to graph it to identify its shape and characteristics.
The form \( r = \pm \sqrt{\cos(2\theta)} \) suggests a behavior that depends on the angle \(\theta\), primarily since \(\cos(2\theta)\) dictates when \(r\) is real and manageable. When graphing, you need to account for where the cosine term is non-negative, because radians of \(\theta\) outside this range would yield imaginary or non-real values of \(r\).
Graphing involves plotting points for various values of \(\theta\) within accepted intervals, typically where \(r\) is defined, which are from
The form \( r = \pm \sqrt{\cos(2\theta)} \) suggests a behavior that depends on the angle \(\theta\), primarily since \(\cos(2\theta)\) dictates when \(r\) is real and manageable. When graphing, you need to account for where the cosine term is non-negative, because radians of \(\theta\) outside this range would yield imaginary or non-real values of \(r\).
Graphing involves plotting points for various values of \(\theta\) within accepted intervals, typically where \(r\) is defined, which are from
- \([0, \frac{\pi}{2}]\)
- \([\pi, \frac{3\pi}{2}]\)
Symmetry in Polar Graphs
Symmetry plays a critical role in understanding and simplifying polar graphs. When examining an equation like \( r = \pm \sqrt{\cos(2\theta)} \), identifying symmetry helps predict and confirm the structure of the graph without having to calculate every possible point.
There are typical types of symmetry in polar graphs:
the graph through the origin, such that if a lobe appears in one half of the graph, its symmetrical counterpart will appear in the opposite half. Identifying symmetry early on can significantly reduce the work required in graphing a polar function, enabling more focused calculation of points where necessary.
There are typical types of symmetry in polar graphs:
- Symmetry about the polar axis (x-axis in rectangular coordinates).
- Symmetry about the line \(\theta = \frac{\pi}{2}\) (y-axis in rectangular coordinates).
- Symmetry about the origin.
the graph through the origin, such that if a lobe appears in one half of the graph, its symmetrical counterpart will appear in the opposite half. Identifying symmetry early on can significantly reduce the work required in graphing a polar function, enabling more focused calculation of points where necessary.
Other exercises in this chapter
Problem 49
Convert the polar equation to rectangular coordinates. $$ r \cos \theta=6 $$
View solution Problem 49
\(49-56\) me product \(z_{1} z_{2}\) and the quotient \(z_{1} / z_{2}\) . Express your answer in polar form. $$ z_{1}=\cos \pi+i \sin \pi, \quad z_{2}=\cos \fra
View solution Problem 50
Velocity A woman walks due west on the deck of an ocean liner at 2 milh. The ocean liner is moving due north at a speed of 25 \(\mathrm{mi} / \mathrm{h}\) . Fin
View solution Problem 50
Convert the polar equation to rectangular coordinates. $$ r=6 \cos \theta $$
View solution