Problem 5
Question
Consider $$ \begin{array}{l} \frac{d x_{1}}{d t}=-x_{1}+2 x_{2} \\ \frac{d x_{2}}{d t}=x_{1} \end{array} $$ Determine the direction vectors associated with the following points in the \(x_{1}-x_{2}\) plane, and graph the direction vectors in the \(x_{1}-\) \(x_{2}\) plane: \((1,0),(0,1),(-1,0),(0,-1),(1,1),(0,0)\), and \((-2,1)\)
Step-by-Step Solution
Verified Answer
Direction vectors are: \((-1,1),(2,0),(1,-1),(-2,0),(1,1),(0,0),(4,-2)\). Plot them with tails at given points.
1Step 1: Understanding the System of Differential Equations
The given system of differential equations is \( \frac{d x_{1}}{d t} = -x_{1} + 2x_{2} \) and \( \frac{d x_{2}}{d t} = x_{1} \). These describe how \( x_{1} \) and \( x_{2} \) change over time. We need to determine the direction vectors \((\frac{d x_{1}}{d t}, \frac{d x_{2}}{d t})\) at specific points in the \( x_{1}-x_{2} \) plane.
2Step 2: Calculate Direction Vectors for Each Point
For every point \((x_{1}, x_{2})\), substitute the values into the differential equations to find the direction vector:- **At (1, 0):** \( \frac{d x_{1}}{d t} = -1 + 0 = -1 \), \( \frac{d x_{2}}{d t} = 1 \). Direction vector: \((-1, 1)\).- **At (0, 1):** \( \frac{d x_{1}}{d t} = 0 + 2 = 2 \), \( \frac{d x_{2}}{d t} = 0 \). Direction vector: \((2, 0)\).- **At (-1, 0):** \( \frac{d x_{1}}{d t} = 1 + 0 = 1 \), \( \frac{d x_{2}}{d t} = -1 \). Direction vector: \((1, -1)\).- **At (0, -1):** \( \frac{d x_{1}}{d t} = 0 - 2 = -2 \), \( \frac{d x_{2}}{d t} = 0 \). Direction vector: \((-2, 0)\).- **At (1, 1):** \( \frac{d x_{1}}{d t} = -1 + 2 = 1 \), \( \frac{d x_{2}}{d t} = 1 \). Direction vector: \((1, 1)\).- **At (0, 0):** Both derivatives are zero, so the direction vector is \((0, 0)\).- **At (-2, 1):** \( \frac{d x_{1}}{d t} = 2 + 2 = 4 \), \( \frac{d x_{2}}{d t} = -2 \). Direction vector: \((4, -2)\).
3Step 3: Graphing the Direction Vectors
Plot each point in the \( x_{1}-x_{2} \) plane and draw the corresponding direction vector by considering the point as the tail of the vector. For example, at point \((1, 0)\), draw a vector with tail at (1, 0) and head at \((1, 0) + (-1, 1) = (0, 1)\). Repeat this process for all points with their respective vectors.
Key Concepts
Direction VectorsSystem of EquationsGraphing in the Plane
Direction Vectors
A direction vector helps us visualize how a point in the \(x_1-x_2\) plane changes over time according to given differential equations. These vectors are essentially arrows that point in the direction of change. Think of them as guiding arrows that tell us which way a point wants to "move."
- The direction vector at each point is obtained by substituting the point's coordinates \(x_1, x_2\) into the system of differential equations provided.
- For example, if you substitute a point like \(x_1 = 1\) and \(x_2 = 0\) into the equations \(\frac{d x_1}{d t}=-x_1+2x_2\) and \(\frac{d x_2}{d t}=x_1\), you find that \(\frac{d x_1}{d t}=-1\) and \(\frac{d x_2}{d t}=1\). Hence, the direction vector at this point is \(-1, 1\).
System of Equations
A system of differential equations consists of multiple equations that describe how variables change with respect to one another over time. In our example, \(\frac{d x_1}{d t}=-x_1+2x_2\) and \(\frac{d x_2}{d t}=x_1\) form such a system.
- This system is interconnected, meaning the change in one variable, \(x_1\), affects the other, \(x_2\), and vice versa. In these equations, the rate of change of \(x_1\) depends on both \(x_1\) and \(x_2\), while the rate of change of \(x_2\) depends solely on \(x_1\).
- Solving such systems usually involves finding solutions that identify how the variables evolve together through time. This highlights interdependencies between variables.
Graphing in the Plane
Graphing direction vectors in a plane involves plotting points and drawing vectors that represent their direction of change. This visualization provides insight into the behavior of the system over time.
- To draw a direction vector, first plot the given point \(x_1, x_2\) on the plane. The vector starts at this point, which serves as its tail.
- The vector itself \(dx_1/dt, dx_2/dt\) is an arrow pointing from the tail to the head determined by summing the point coordinates with the direction vector.
Other exercises in this chapter
Problem 4
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Consider $$ \begin{array}{l} \frac{d x_{1}}{d t}=2 x_{1}-x_{2} \\ \frac{d x_{2}}{d t}=-x_{2} \end{array} $$ Determine the direction vectors associated with the
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