Problem 4
Question
Write each system of differential equations in matrix form. $$ \begin{array}{l} \frac{d x_{1}}{d t}=2 x_{2}-3 x_{1}-x_{3} \\ \frac{d x_{2}}{d t}=-x_{1}+x_{2} \end{array} $$
Step-by-Step Solution
Verified Answer
The system in matrix form is \( \frac{d\mathbf{X}}{dt} = \begin{bmatrix} -3 & 2 & -1 \\ -1 & 1 & 0 \end{bmatrix} \cdot \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} \).
1Step 1: Understand the System of Differential Equations
We have two differential equations with three variables: 1. \( \frac{d x_{1}}{d t}=2 x_{2}-3 x_{1}-x_{3} \) 2. \( \frac{d x_{2}}{d t}=-x_{1}+x_{2} \). These equations describe how \( x_1 \) and \( x_2 \) change with respect to time \( t \).
2Step 2: Identify Coefficients for Matrix Representation
Identify the coefficients of each variable from both equations. For the first equation \( \frac{d x_{1}}{d t}=2 x_{2}-3 x_{1}-x_{3} \), the coefficients are: - For \( x_1 \): -3 - For \( x_2 \): 2 - For \( x_3 \): -1. For the second equation \( \frac{d x_{2}}{d t}=-x_{1}+x_{2} \), the coefficients are: - For \( x_1 \): -1 - For \( x_2 \): 1 - For \( x_3 \): 0.
3Step 3: Construct the Coefficient Matrix
Based on the coefficients identified, form a matrix. The coefficients for the variables \( x_1, x_2, \) and \( x_3 \) for the two equations form the matrix: \[ A = \begin{bmatrix} -3 & 2 & -1 \ -1 & 1 & 0 \end{bmatrix} \] This is called the coefficient matrix \( A \).
4Step 4: Write the System in Matrix Form
Express the system of differential equations in matrix form using the coefficient matrix \( A \), the vector of derivatives, and the vector of variables: Let \( \mathbf{X} = \begin{bmatrix} x_1 \ x_2 \ x_3 \end{bmatrix} \) and \( \frac{d\mathbf{X}}{dt} = \begin{bmatrix} \frac{dx_1}{dt} \ \frac{dx_2}{dt} \ \frac{dx_3}{dt} \end{bmatrix} \). The system in matrix form is: \[ \frac{d\mathbf{X}}{dt} = A \cdot \mathbf{X} = \begin{bmatrix} -3 & 2 & -1 \ -1 & 1 & 0 \end{bmatrix} \cdot \begin{bmatrix} x_1 \ x_2 \ x_3 \end{bmatrix} \]
Key Concepts
Coefficient MatrixDifferential EquationsSystem of Equations
Coefficient Matrix
The coefficient matrix is a crucial element when transforming a system of differential equations into matrix form. It is a compact way of organizing the coefficients from each equation into a structured grid.
This matrix represents the relationship between variables in a system of equations. For instance, in our specific system:
This matrix represents the relationship between variables in a system of equations. For instance, in our specific system:
- The first differential equation \( \frac{d x_{1}}{d t}=2 x_{2}-3 x_{1}-x_{3} \) gives us the coefficients: \(-3\) for \(x_1\), \(2\) for \(x_2\), and \(-1\) for \(x_3\).
- The second differential equation \( \frac{d x_{2}}{d t}=-x_{1}+x_{2} \) provides: \(-1\) for \(x_1\), \(1\) for \(x_2\), and \(0\) for \(x_3\). This zero indicates the absence of \(x_3\).
Differential Equations
Differential equations are equations that involve an unknown function and its derivatives. They describe how a specific function changes over time or space. These equations can be quite complex, but they are fundamental in modeling real-world scenarios such as motion, heat, population dynamics, and more.
In the given exercise, we consider two differential equations:
In the given exercise, we consider two differential equations:
- \( \frac{d x_{1}}{d t} = 2x_2 - 3x_1 - x_3 \)
- \( \frac{d x_{2}}{d t} = -x_1 + x_2 \)
System of Equations
A system of equations consists of multiple, interrelated equations involving several variables to solve together. When working with systems of differential equations, they showcase how variables interact in tandem, affecting each other's rates of change.
In our exercise, the system includes:
In our exercise, the system includes:
- \( \frac{d x_{1}}{d t} = 2 x_2 - 3 x_1 - x_3 \)
- \( \frac{d x_{2}}{d t} = -x_1 + x_2 \)
Other exercises in this chapter
Problem 3
Write each system of differential equations in matrix form. $$ \begin{array}{l} \frac{d x_{1}}{d t}=x_{3}-2 x_{1} \\ \frac{d x_{2}}{d t}=-x_{1} \end{array} $$
View solution Problem 3
The point \((0,0)\) is always an equilibrium. Use the analytical approach to investigate its stability \(\frac{d x_{1}}{d t}=x_{1}+x_{1}^{2}-2 x_{1} x_{2}+x_{2}
View solution Problem 4
The point \((0,0)\) is always an equilibrium. Use the analytical approach to investigate its stability \(\frac{d x_{1}}{d t}=3 x_{1} x_{2}-x_{1}+x_{2}\) \(\frac
View solution Problem 5
Consider $$ \begin{array}{l} \frac{d x_{1}}{d t}=-x_{1}+2 x_{2} \\ \frac{d x_{2}}{d t}=x_{1} \end{array} $$ Determine the direction vectors associated with the
View solution