Problem 5
Question
a. Show that $$ u(x, t)=20 e^{-t} \sin \pi x, \quad 0 \leq x \leq 1, \quad 0 \leq t $$ solves $$ u_{t}(x, t)=\frac{1}{\pi^{2}} u_{x x}(x, t), \quad u(x, 0)=20 \sin \pi x, \quad \text { and } \quad u(0, t)=u(1, t)=0 $$ b. Describe a physical problem for which this is a solution. c. What is the 'eventual' value of \(u(x, t)\) (what is \(\left.\lim _{t \rightarrow \infty} u(x, t)\right) ?\) d. At what time, \(t,\) will the maximum value of \(u(x, t)\) for \(0 \leq x \leq 1\) be \(20 ?\)
Step-by-Step Solution
Verified Answer
a: Yes. b: Heat conduction in a rod. c: 0. d: \(t = 0\).
1Step 1: Verify the initial condition
To verify the initial condition, substitute \(t=0\) into the given function \(u(x, t)\):\[ u(x, 0) = 20 e^{0} \sin \pi x = 20 \sin \pi x. \]This matches the initial condition \(u(x, 0)=20 \sin \pi x\). Thus, the initial condition is satisfied.
2Step 2: Verify the boundary conditions
For the boundary conditions, evaluate \(u(x, t)\) at \(x=0\) and \(x=1\):- At \(x=0\), \[ u(0, t) = 20 e^{-t} \sin (0) = 0. \] - At \(x=1\), \[ u(1, t) = 20 e^{-t} \sin (\pi \times 1) = 0. \] Thus, the boundary conditions \(u(0, t)=0\) and \(u(1, t)=0\) are satisfied.
3Step 3: Compute \(u_t(x, t)\)
Differentiate \(u(x, t) = 20 e^{-t} \sin \pi x\) with respect to \(t\):\[ u_t(x, t) = \frac{d}{dt} [20 e^{-t} \sin \pi x] = -20 e^{-t} \sin \pi x. \]
4Step 4: Compute \(u_{xx}(x, t)\)
Differentiate \(u(x, t) = 20 e^{-t} \sin \pi x\) twice with respect to \(x\):- First derivative: \[ u_x(x, t) = 20 e^{-t} \pi \cos \pi x. \]- Second derivative: \[ u_{xx}(x, t) = -20 e^{-t} \pi^2 \sin \pi x. \]
5Step 5: Verify the differential equation
Substitute \(u_t(x, t)\) and \(u_{xx}(x, t)\) into the differential equation \(u_t = \frac{1}{\pi^2}u_{xx}\):\[ -20 e^{-t} \sin \pi x = \frac{1}{\pi^2}(-20 e^{-t} \pi^2 \sin \pi x). \]This simplifies to \(-20 e^{-t} \sin \pi x = -20 e^{-t} \sin \pi x\), confirming that the differential equation is satisfied.
6Step 6: Describe a physical problem
This solution corresponds to the heat equation, which models the temperature distribution along a one-dimensional rod of length 1 over time. The initial temperature distribution is given by \(20 \sin \pi x\), and the ends of the rod are kept at 0 temperature.
7Step 7: Determine eventual value of \(u(x, t)\)
Compute the limit as \(t\) approaches infinity:\[ \lim_{t \rightarrow \infty} u(x, t) = \lim_{t \rightarrow \infty} 20 e^{-t} \sin \pi x = 0. \]As \(t\) gets large, the exponential term \(e^{-t}\) approaches 0, so \(u(x, t)\) tends to 0.
8Step 8: Find time when maximum value is 20
The maximum value of \(u(x, t)\) occurs when \(\sin \pi x = 1\), which is at \(x = 0.5\). The given value to reach is 20, thus:\[ u(0.5, t) = 20 e^{-t} (1) = 20. \]Solving the equation \(20 e^{-t} = 20\) gives:\[ e^{-t} = 1, \quad \Rightarrow \quad t = 0. \]
Key Concepts
Initial ConditionBoundary ConditionsTemperature DistributionDifferential Equation
Initial Condition
The initial condition of a problem refers to the state of a system at the very beginning of the time period being considered. This is essential as it sets the stage for how the system will evolve over time.
For this problem, the initial condition is given by:
This initial temperature distribution is fundamental as it impacts the trajectory of the temperature changes over time. Understanding this helps in predicting how the system will behave as it reaches equilibrium.
For this problem, the initial condition is given by:
- \( u(x, 0) = 20 \sin \pi x \)
This initial temperature distribution is fundamental as it impacts the trajectory of the temperature changes over time. Understanding this helps in predicting how the system will behave as it reaches equilibrium.
Boundary Conditions
Boundary conditions are critical in defining how the solution to a differential equation should behave at the edges of the domain. They ensure that the solution is physically viable and aligns with real-world constraints.
In our problem, the boundary conditions are:
Boundary conditions help shape the entire behavior of the temperature distribution, ensuring a realistic simulation of thermal dynamics.
In our problem, the boundary conditions are:
- \( u(0, t) = 0 \)
- \( u(1, t) = 0 \)
Boundary conditions help shape the entire behavior of the temperature distribution, ensuring a realistic simulation of thermal dynamics.
Temperature Distribution
The temperature distribution describes how temperature varies along the rod over time. This is key to understanding heat flow in the system.
The given function:
The exponential decay factor \( e^{-t} \) indicates that as time progresses, the temperature across the entire rod decreases until it eventually stabilizes at zero. This suggests that without an external input of heat, the temperature equalizes due to dissipation. Understanding the temperature distribution over time helps in predicting system behavior and ensures that one can derive conclusions about how quickly the system reaches thermal equilibrium.
The given function:
- \( u(x, t) = 20 e^{-t} \sin \pi x \)
The exponential decay factor \( e^{-t} \) indicates that as time progresses, the temperature across the entire rod decreases until it eventually stabilizes at zero. This suggests that without an external input of heat, the temperature equalizes due to dissipation. Understanding the temperature distribution over time helps in predicting system behavior and ensures that one can derive conclusions about how quickly the system reaches thermal equilibrium.
Differential Equation
A differential equation is a mathematical expression that relates a function to its derivatives, describing how that function changes. In this problem, the differential equation is:
The term \( u_{t}(x, t) \) represents the rate of change of temperature with respect to time, while \( u_{xx}(x, t) \) reflects how temperature changes with respect to space. The right side of the equation, \( \frac{1}{\pi^{2}} u_{xx}(x, t) \), indicates that the rate of temperature change is directly proportional to its spatial curvature, meaning that steeper temperature gradients (higher curvatures) result in faster heat flow.
Solving this differential equation provides insights into how the rod's temperature evolves over time, crucial for applications involving thermal management and material design.
- \( u_{t}(x, t) = \frac{1}{\pi^{2}} u_{xx}(x, t) \)
The term \( u_{t}(x, t) \) represents the rate of change of temperature with respect to time, while \( u_{xx}(x, t) \) reflects how temperature changes with respect to space. The right side of the equation, \( \frac{1}{\pi^{2}} u_{xx}(x, t) \), indicates that the rate of temperature change is directly proportional to its spatial curvature, meaning that steeper temperature gradients (higher curvatures) result in faster heat flow.
Solving this differential equation provides insights into how the rod's temperature evolves over time, crucial for applications involving thermal management and material design.
Other exercises in this chapter
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