Problem 2
Question
Find the partial derivatives, \(F_{1}, F_{2}, F_{1,1}, F_{1,2}, F_{2,1}\) and \(F_{2,2}\) of the following functions. a. \(\quad F(x, y)=3 x-5 y+7\) b. \(\quad F(x, y)=x^{2}+4 x y+3 y^{2}\) c. \(\quad F(x, y)=x^{3} y^{5}\) d. \(\quad F(x, y)=\sqrt{x y}\) e. \(\quad F(x, y)=\ln (x \times y) \quad\) f. \(\quad F(x, y)=\frac{x}{y}\) g. \(\quad F(x, y)=e^{x+y}\) h. \(\quad F(x, y)=x^{2} e^{-y}\) i. \(\quad F(x, y)=\sin (2 x+3 y)\) j. \(F(x, y)=e^{-x} \cos y\)
Step-by-Step Solution
Verified Answer
Compute first and second order partial derivatives for each function using definitions; apply symmetry for mixed derivatives and summarize results.
1Step 1: Understanding Partial Derivatives
Before solving, recognize that partial derivatives measure the function's rate of change with respect to one variable while keeping other variables constant. Notations: For a function \( F(x,y) \), \( F_1 = \frac{\partial F}{\partial x} \), \( F_2 = \frac{\partial F}{\partial y} \), and second-order derivatives are \( F_{1,1} = \frac{\partial^2 F}{\partial x^2} \), \( F_{1,2} = \frac{\partial^2 F}{\partial x \partial y} \), and similarly for other combinations.
2Step 2: Compute First Order Partial Derivatives for each function
For each function, find \( F_1 \) and \( F_2 \). For instance, take \( F(x,y) = 3x - 5y + 7 \). Differentiate \( F \) with respect to \( x \) to find \( F_1 = 3 \), and differentiate with respect to \( y \) to find \( F_2 = -5 \). Repeat the process for functions (b) to (j).
3Step 3: Compute Second Order Partial Derivatives for each function
For each function, compute \( F_{1,1} \), \( F_{1,2} \), \( F_{2,1} \), and \( F_{2,2} \). Continuing from (a), since \( F_1 = 3 \) is constant, \( F_{1,1} = 0 \). Similarly, \( F_2 = -5 \) being constant implies \( F_{2,2} = 0 \), and \( F_{1,2} = F_{2,1} = 0 \) since cross-partial derivatives of constants are zero. Repeat similar operations for functions (b) to (j).
4Step 4: Check Symmetry of Mixed Partial Derivatives
Verify that \( F_{1,2} = F_{2,1} \) if the function is continuously differentiable according to Clairaut's theorem. This implies that the mixed partials should be equal unless the function's continuity assumptions are violated.
5Step 5: Present Calculations Succinctly
Summarize the computed partial derivatives for each function. Each function's results should present \( F_1, F_2, F_{1,1}, F_{1,2}, F_{2,1}, F_{2,2} \) in sequence for clarity.
Key Concepts
Multivariable CalculusSecond-order DerivativesClairaut's TheoremRate of ChangeContinuously Differentiable Functions
Multivariable Calculus
Multivariable calculus is an extension of the concepts of single-variable calculus to functions of more than one variable. In multivariable calculus, we often work with functions like \( F(x, y) \), where changes can occur in any of the variables—independently or simultaneously. This field is essential as many real-world problems involve multiple variables. Understanding multivariable calculus enables us to:
- Analyze surfaces and curves in higher dimensions.
- Examine the behavior of functions across variables.
- Apply calculus concepts to physics and engineering.
Second-order Derivatives
Second-order derivatives are an extension of the concept of first-order derivatives. They measure how the rate of change of a function—the derivative—changes. For a function \( F(x,y) \), second-order derivatives include:
- \( F_{1,1} = \frac{\partial^2 F}{\partial x^2} \): the second derivative of \( F \) with respect to \( x \).
- \( F_{2,2} = \frac{\partial^2 F}{\partial y^2} \): the second derivative of \( F \) with respect to \( y \).
- \( F_{1,2} = \frac{\partial^2 F}{\partial x \partial y} \) or \( F_{2,1} = \frac{\partial^2 F}{\partial y \partial x} \): mixed partial derivatives.
Clairaut's Theorem
Clairaut's theorem, also known as the equality of mixed partials, provides that if a function \( F(x,y) \) is continuously differentiable in a neighborhood of a point, then the mixed partial derivatives at that point are equal. Mathematically, if the mixed partials:
- \( F_{1,2} = \frac{\partial^2 F}{\partial x \partial y} \)
- \( F_{2,1} = \frac{\partial^2 F}{\partial y \partial x} \)
Rate of Change
Rate of change is a fundamental concept involving how one quantity varies in relation to another. In the context of multivariable functions, the rate of change is illustrated by partial derivatives. Partial derivatives measure the sensitivity of a function regarding changes in one variable alone. For example:
- \( F_1 = \frac{\partial F}{\partial x} \): measures how \( F \) changes as \( x \) changes, keeping \( y \) constant.
- \( F_2 = \frac{\partial F}{\partial y} \): measures how \( F \) changes as \( y \) changes, keeping \( x \) constant.
Continuously Differentiable Functions
Continuously differentiable functions are those functions for which the first and second (or higher) derivatives are continuous. This continuity is crucial in calculus because it ensures that the function behaves predictably and smoothly. Important features include:
- Smoothness, meaning no abrupt changes in function direction.
- The ability to apply theorems like Clairaut's, which rely on this property.
- Ensures validity for computations involving second-order derivatives since continuity guarantees equality of mixed partials.
Other exercises in this chapter
Problem 1
Draw three dimensional graphs of a. $$ F(x, y)=2 \quad \text { b. } \quad F(x, y)=x $$ c. $$ F(x, y)=x^{2} $$ $$ \text { d. } \quad F(x, y)=(x+y) / 2 $$ e. \(F(
View solution Problem 2
For each of the following functions, find the critical points and use Theorem 13.2 .1 to determine whether they are local maxima, local minima, or saddle points
View solution Problem 3
Find \(C\) and \(b\) so that \(C e^{0 x}\) closely approximates the data \begin{tabular}{|r|r|r|r|r|r|} \hline\(x\) & 0 & 1 & 2 & 3 & 4 \\ \hline\(y\) & 2.18 &
View solution Problem 5
a. Show that $$ u(x, t)=20 e^{-t} \sin \pi x, \quad 0 \leq x \leq 1, \quad 0 \leq t $$ solves $$ u_{t}(x, t)=\frac{1}{\pi^{2}} u_{x x}(x, t), \quad u(x, 0)=20 \
View solution