Problem 49
Question
What is the value of $$5(x-1)(x-2)+2(x-1)(x-3)-4(x-2)(x-3)$$ when \(x=3 ?\)
Step-by-Step Solution
Verified Answer
Answer: The value of the given expression when \(x=3\) is 10.
1Step 1: Substitute the value of x
Replace x with 3 in the given expression:
$$5(3-1)(3-2)+2(3-1)(3-3)-4(3-2)(3-3)$$
2Step 2: Simplify the expressions within the parentheses
Simplify the numbers inside the parentheses:
$$5(2)(1)+2(2)(0)-4(1)(0)$$
3Step 3: Multiply the numbers
Perform the multiplications:
$$10(1)+4(0)-4(0)$$
4Step 4: Simplify the sum
Add and subtract the results from the previous step:
$$10+0-0$$
5Step 5: Obtain the final value
When \(x=3\), the value of the given expression is:
$$10$$
Key Concepts
Polynomial EvaluationSubstitution MethodSimplification Process
Polynomial Evaluation
Polynomial evaluation is about finding the value of a polynomial expression when a specific variable value is given. It involves substituting the variable with the given number and computing the result. In our exercise, we start with the expression:
- \(5(x-1)(x-2)+2(x-1)(x-3)-4(x-2)(x-3)\)
- \(5(3-1)(3-2) + 2(3-1)(3-3) - 4(3-2)(3-3)\)
Substitution Method
The substitution method simplifies an algebraic expression by replacing variables with numerical values. This approach is like "plugging in" a specific number where the variable appears.
In our example, when we substitute \( x = 3 \), every occurrence of \(x\) in the expression is replaced:
In our example, when we substitute \( x = 3 \), every occurrence of \(x\) in the expression is replaced:
- \(5(\textcolor{blue}{x}-1)(\textcolor{blue}{x}-2)\) becomes \(5(3-1)(3-2)\)
- \(2(x-1)(x-3)\) becomes \(2(3-1)(3-3)\)
- \(-4(x-2)(x-3)\) becomes \(-4(3-2)(3-3)\)
Simplification Process
The simplification process involves breaking down a complex expression into its simplest form. After substitution in our exercise, we are left with the expression:
- \(5(2)(1) + 2(2)(0) - 4(1)(0)\)
- Evaluate Within Parentheses: Start by calculating expressions within the parentheses. For instance, \((3-1)\) results in \(2\) and \((3-2)\) results in \(1\).
- Perform Multiplication: Multiply the numbers together, e.g., \(5 \times 2 \times 1 = 10\).
- Combine Terms: Add or subtract the results from the multiplication, \(10 + 0 - 0\).
Other exercises in this chapter
Problem 48
What is the degree of the resulting polynomial? The sum of a degree 8 polynomial and a degree 4 polynomial.
View solution Problem 48
For what values of \(a\) does the equation have a solution in \(x\) ? $$ a-x^{5}=0 $$
View solution Problem 49
Find approximate solutions to $$ 3 x^{3}-2 x^{2}-6 x+4=0 $$ by graphing the polynomial.
View solution Problem 50
What values of the constants \(A, B,\) and \(C,\) will make \(A(x-1)(x-2)+B(x-1)(x-3)-C(x-2)(x-3)\) have the value 7 when \(x=3 ?\)
View solution