Problem 49
Question
Use algebra and identities in the text to simplify the expression. Assume all denominators are nonzero. $$\tan t \cos t$$
Step-by-Step Solution
Verified Answer
Question: Simplify the expression \(\tan t \cos t\).
Answer: \(\sin t\)
1Step 1: Write the expression using the identity for the tangent function
Using the identity \(\tan t=\frac{\sin t}{\cos t}\), we can rewrite the given expression as:
$$\frac{\sin t}{\cos t} \cdot \cos t$$
2Step 2: Multiply and simplify the expression
Now, multiply the expression and notice that \(\cos t\) in the numerator and denominator will cancel out. So, we get:
$$\frac{\sin t}{\cos t} \cdot \cos t = \sin t$$
Therefore, the simplified expression is:
$$\tan t \cos t = \sin t$$
Key Concepts
Tangent FunctionSine FunctionSimplifying Trigonometric Expressions
Tangent Function
The tangent function is one of the primary trigonometric functions used in mathematics. It is often represented as \( \tan t \), where \( t \) is the angle. It relates the sine and cosine functions through the identity:
By doing so, you can manipulate trigonometric expressions more flexibly. In the exercise, understanding \( \tan t \) as \( \frac{\sin t}{\cos t} \) was essential to simplify the expression \( \tan t \cos t \) into a simpler form.
This highlights how well-known identities can be used to transform and simplify mathematical expressions efficiently.
- \( \tan t = \frac{\sin t}{\cos t} \)
By doing so, you can manipulate trigonometric expressions more flexibly. In the exercise, understanding \( \tan t \) as \( \frac{\sin t}{\cos t} \) was essential to simplify the expression \( \tan t \cos t \) into a simpler form.
This highlights how well-known identities can be used to transform and simplify mathematical expressions efficiently.
Sine Function
The sine function is a foundational trigonometric function in mathematics and is typically denoted as \( \sin t \), where \( t \) is an angle. It is a crucial part of the identity equation for the tangent function as mentioned earlier, \( \tan t = \frac{\sin t}{\cos t} \).
The ultimate goal in the exercise was to make \( \sin t \) more prominent, highlighting its role and showing its simplicity compared to more complex trigonometric expressions.Recognizing when \( \sin t \) is useful in simplifying expressions saves time and reduces calculation complexity.
- \( \sin t \) measures the opposite side over the hypotenuse in a right triangle.
- It wraps the circular distance traveled on a unit circle when moving from the positive x-axis.
The ultimate goal in the exercise was to make \( \sin t \) more prominent, highlighting its role and showing its simplicity compared to more complex trigonometric expressions.Recognizing when \( \sin t \) is useful in simplifying expressions saves time and reduces calculation complexity.
Simplifying Trigonometric Expressions
Simplifying trigonometric expressions involves using known identities and algebraic manipulation to reduce expressions to their simplest form.
This logical step rapidly simplifies the expression from something potentially complex to simply \( \sin t \). By practicing such simplifications, students learn to see beyond the initial complexity of expressions to the straightforward core that often lies within. Brevity and clarity achieved through simplification can lend incredible clarity to both homework problems and exam questions alike.
- It often makes calculations easier and solutions clearer.
- Utilizes identities like \( \tan t = \frac{\sin t}{\cos t} \) and others.
This logical step rapidly simplifies the expression from something potentially complex to simply \( \sin t \). By practicing such simplifications, students learn to see beyond the initial complexity of expressions to the straightforward core that often lies within. Brevity and clarity achieved through simplification can lend incredible clarity to both homework problems and exam questions alike.
Other exercises in this chapter
Problem 48
Convert the given radian measure to degrees. $$7 \pi / 15$$
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The original Ferris wheel, built by George Ferris for the Columbian Exposition of \(1893,\) was much larger and slower than its modern counterparts: It had a di
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In Exercises \(49-54\), prove the given identity. $$\tan t=\frac{1}{\cot t}[\text {Hint}: \text { See page } 497]$$
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Convert the given radian measure to degrees. $$27 \pi / 5$$
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