Problem 49
Question
In Exercises \(49-54\), prove the given identity. $$\tan t=\frac{1}{\cot t}[\text {Hint}: \text { See page } 497]$$
Step-by-Step Solution
Verified Answer
Question: Prove that the given identity \(\tan t=\frac{1}{\cot t}\) is true.
Answer: We proved the given identity by first recalling the definitions of the tangent and cotangent functions, and then relating the tangent function to the cotangent function. By substituting the expression for cotangent and simplifying, we showed that the given identity is true.
1Step 1: Recall the definitions of \(\tan\) and \(\cot\)
The tangent function, \(\tan\), is defined as the ratio of the sine function to the cosine function, i.e,
$$\tan t = \frac{\sin t}{\cos t}$$
The cotangent function, \(\cot\), is defined as the ratio of the cosine function to the sine function, i.e,
$$\cot t = \frac{\cos t}{\sin t}$$
2Step 2: Relate the \(\tan\) function to the \(\cot\) function
As we know that the \(\cot t\) is the reciprocal of the \(\tan t\), we can rewrite the \(\cot t\) expression as follows:
$$\cot t = \frac{1}{\tan t}$$
Substitute the definition of the tangent function:
$$\cot t = \frac{1}{\dfrac{\sin t}{\cos t}}$$
3Step 3: Substitute the expression for \(\cot t\) and simplify
Now, we will substitute the expression of \(\cot t\) into the given identity and simplify it:
$$\tan t = \frac{1}{\cot t} = \frac{1}{\dfrac{1}{\dfrac{\sin t}{\cos t}}}$$
Simplify it by taking the reciprocal of \(\cot t\):
$$\tan t = \frac{\sin t}{\cos t}$$
4Step 4: Conclusion
We have shown that the given identity,
$$\tan t = \frac{1}{\cot t}$$
is true, as we were able to simplify it to
$$\tan t = \frac{\sin t}{\cos t}$$
which is the definition of the tangent function.
Key Concepts
Tangent FunctionCotangent FunctionReciprocal IdentitiesTrigonometry Proofs
Tangent Function
The tangent function, abbreviated as \( \tan \), is a trigonometric function that arises frequently in mathematics, particularly in the study of triangles and circles. It is defined as the ratio of the sine and cosine functions. Specifically, the tangent of an angle \( t \) is given by: \[ \tan t = \frac{\sin t}{\cos t} \] This means that for any angle, the tangent function will take the value of the sine of that angle divided by the cosine of the same angle.
This relationship helps in understanding and calculating the angle and side length relationships in right triangles.
This relationship helps in understanding and calculating the angle and side length relationships in right triangles.
- In a right triangle, the tangent of an angle represents the ratio of the opposite side to the adjacent side.
- Tangent is periodic with a period of \( \pi \) or 180 degrees, meaning \( \tan(t + \pi) = \tan t \).
Cotangent Function
The cotangent function, represented as \( \cot \), is another key function in trigonometry that is the reciprocal of tangent. If an angle \( t \) is given, the cotangent of that angle is expressed as the cosine of the angle divided by its sine: \[ \cot t = \frac{\cos t}{\sin t} \]
Because it is the reciprocal of the tangent function, there is a simple, useful reciprocal identity:
In the context of a right triangle, cotangent represents the ratio of the adjacent side to the opposite side. Mastering the cotangent function and its relationship with tangent provides a deeper understanding of trigonometric identities.
Because it is the reciprocal of the tangent function, there is a simple, useful reciprocal identity:
- \( \cot t = \frac{1}{\tan t} \)
In the context of a right triangle, cotangent represents the ratio of the adjacent side to the opposite side. Mastering the cotangent function and its relationship with tangent provides a deeper understanding of trigonometric identities.
Reciprocal Identities
Reciprocal identities are a fundamental concept in trigonometry, forming the backbone of many simplifications and proofs. These identities help link the primary trigonometric functions through their reciprocal relations. For instance, the cotangent and tangent functions are reciprocals: \[ \cot t = \frac{1}{\tan t} \]
This relationship showcases how tangent and cotangent are intertwined. By knowing one, you can instantly infer the other. Reciprocal identities also apply to other trigonometric functions besides tangent and cotangent, such as sine and cosecant, or cosine and secant.
Understanding and using reciprocal identities:
This relationship showcases how tangent and cotangent are intertwined. By knowing one, you can instantly infer the other. Reciprocal identities also apply to other trigonometric functions besides tangent and cotangent, such as sine and cosecant, or cosine and secant.
Understanding and using reciprocal identities:
- Simplifies expressions and calculations, making solving complex trigonometric problems more manageable.
- Facilitates converting between different trigonometric functions.
Trigonometry Proofs
Trigonometry proofs are logical arguments that demonstrate the truth of a trigonometric identity or statement. They are crucial for validating relationships between trigonometric functions. In the given exercise, the statement proved was \( \tan t = \frac{1}{\cot t} \). This proof involves several steps:
To develop skills in trigonometry proofs:
- Understanding the definitions of the involved trigonometric functions.
- Expressing these functions in terms of sine and cosine, their most basic forms.
- Employing reciprocal identities to transform one side of the equation to match the other.
To develop skills in trigonometry proofs:
- Practice regularly, focusing on different types of identities.
- Become familiar with common strategies such as substituting identities and simplifying fractions.
Other exercises in this chapter
Problem 49
The original Ferris wheel, built by George Ferris for the Columbian Exposition of \(1893,\) was much larger and slower than its modern counterparts: It had a di
View solution Problem 49
Use algebra and identities in the text to simplify the expression. Assume all denominators are nonzero. $$\tan t \cos t$$
View solution Problem 49
Convert the given radian measure to degrees. $$27 \pi / 5$$
View solution Problem 49
In Exercises \(47-54\), find the average rate of change of the function over the given interval. Exact answers are required. $$g(t)=\sin t \text { from } t=\pi
View solution