Problem 49
Question
From the information given, find the quadrant in which the terminal point determined by \(t\) lies. $$ \sin t>0 \text { and } \cos t<0 $$
Step-by-Step Solution
Verified Answer
The terminal point determined by \(t\) lies in the second quadrant.
1Step 1: Understanding Sine and Cosine
The sine function, \( \sin t \), is positive in the first and second quadrants. The cosine function, \( \cos t \), is negative in the second and third quadrants.
2Step 2: Identifying the Common Quadrant
Combine the information. We know \( \sin t > 0 \) (first and second quadrants) and \( \cos t < 0 \) (second and third quadrants). The only quadrant where both conditions are true simultaneously is the second quadrant.
Key Concepts
Sine FunctionCosine FunctionQuadrant Analysis
Sine Function
The sine function is a fundamental concept in trigonometry, represented by the symbol \( \sin \). It measures the y-coordinate of a point on the unit circle, which is a circle with a radius of one centered at the origin of a coordinate system. The value of \( \sin t \) corresponds to how high above or below the x-axis a point lies when you move counterclockwise from the positive x-axis by an angle \( t \).
Here's an easy way to remember its values in relation to the quadrants:
Here's an easy way to remember its values in relation to the quadrants:
- In Quadrant I, both sine and cosine are positive, so \( \sin t > 0 \).
- In Quadrant II, sine remains positive while cosine becomes negative, \( \sin t > 0 \).
- In Quadrant III and IV, the sine function becomes negative because points are either directly below or towards the negative side of the x-axis.
Cosine Function
The cosine function, denoted by \( \cos \), is another key function in trigonometry. It represents the x-coordinate on the unit circle. Essentially, \( \cos t \) tells us how far left or right a point on the unit circle is from the y-axis after rotating an angle \( t \).
Here's how the cosine function behaves across the quadrants:
Here's how the cosine function behaves across the quadrants:
- In Quadrant I, cosine is positive because the points are to the right of the y-axis, \( \cos t > 0 \).
- In Quadrant II, cosine becomes negative because points are now to the left of the y-axis, \( \cos t < 0 \).
- In Quadrant III, cosine remains negative as the points continue to be on the left.
- In Quadrant IV, cosine turns positive again.
Quadrant Analysis
Quadrant Analysis helps us determine the location of an angle or point on the coordinate plane based on trigonometric values. The coordinate plane is divided into four regions, or quadrants:
In the provided exercise, the conditions \( \sin t > 0 \) and \( \cos t < 0 \) were given. Using quadrant analysis, we find:- \( \sin t > 0 \) limits the possibilities to Quadrants I and II.- \( \cos t < 0 \) restricts it further to Quadrants II and III.By intersecting these conditions, only Quadrant II satisfies both, as it is the only quadrant where sine is positive and cosine is negative. This analytic approach simplifies the process of determining the correct quadrant efficiently.
- Quadrant I: Both sine and cosine values are positive.
- Quadrant II: Sine is positive, but cosine is negative.
- Quadrant III: Both sine and cosine are negative.
- Quadrant IV: Sine is negative, but cosine is positive.
In the provided exercise, the conditions \( \sin t > 0 \) and \( \cos t < 0 \) were given. Using quadrant analysis, we find:- \( \sin t > 0 \) limits the possibilities to Quadrants I and II.- \( \cos t < 0 \) restricts it further to Quadrants II and III.By intersecting these conditions, only Quadrant II satisfies both, as it is the only quadrant where sine is positive and cosine is negative. This analytic approach simplifies the process of determining the correct quadrant efficiently.
Other exercises in this chapter
Problem 48
Find (a) the reference number for each value of t, and (b) the terminal point determined by t. $$ t=\frac{31 \pi}{6} $$
View solution Problem 48
7–52 Find the period and graph the function. $$y=\tan \frac{1}{2}\left(x+\frac{\pi}{4}\right)$$
View solution Problem 49
7–52 Find the period and graph the function. $$y=3 \sec \pi\left(x+\frac{1}{2}\right)$$
View solution Problem 50
From the information given, find the quadrant in which the terminal point determined by \(t\) lies. $$ \tan t>0 \text { and } \sin t
View solution