Problem 48
Question
Solve each quadratic equation using the method that seems most appropriate. $$x^{2}=16 x$$
Step-by-Step Solution
Verified Answer
The solutions are \(x = 0\) and \(x = 16\).
1Step 1: Rewrite the Equation
Start by rewriting the given equation in the standard form of a quadratic equation, which is \(ax^2 + bx + c = 0\). The given equation is \(x^2 = 16x\). Move all terms to one side of the equation to get \(x^2 - 16x = 0\).
2Step 2: Factor the Expression
The equation \(x^2 - 16x = 0\) can be factored by taking out the common factor \(x\). So, the equation becomes \(x(x - 16) = 0\).
3Step 3: Apply the Zero Product Property
Use the zero product property, which states that if \(ab = 0\), then \(a = 0\) or \(b = 0\). This gives us two equations: \(x = 0\) and \(x - 16 = 0\). Solve each equation separately.
4Step 4: Solve Each Equation
Solve the first equation: \(x = 0\).Solve the second equation: \(x - 16 = 0\) which gives \(x = 16\).
5Step 5: Write the Solution
The solutions to the quadratic equation \(x^2 = 16x\) are \(x = 0\) and \(x = 16\).
Key Concepts
Factoring QuadraticsZero Product PropertySolving Quadratic Equations
Factoring Quadratics
Factoring quadratics is an essential algebraic technique used to simplify and solve quadratic equations. A quadratic equation typically takes the standard form of \(ax^2 + bx + c = 0\). In the exercise, converting the given equation \(x^2 = 16x\) to a standard form yields \(x^2 - 16x = 0\).
Factoring involves finding two terms that multiply together to give the original quadratic equation. For \(x^2 - 16x = 0\), we notice that both terms share a common factor: \(x\). By pulling out this common factor, the equation becomes \(x(x - 16) = 0\).
Factoring not only simplifies the problem but also sets the stage for the next step in solving the equation by allowing us to use the Zero Product Property.
Factoring involves finding two terms that multiply together to give the original quadratic equation. For \(x^2 - 16x = 0\), we notice that both terms share a common factor: \(x\). By pulling out this common factor, the equation becomes \(x(x - 16) = 0\).
Factoring not only simplifies the problem but also sets the stage for the next step in solving the equation by allowing us to use the Zero Product Property.
Zero Product Property
The Zero Product Property is a crucial principle in algebra that helps solve equations after factoring. It states that if a product of two numbers is zero, then at least one of the numbers must be zero. Using the property is straightforward: given \(ab = 0\), either \(a = 0\) or \(b = 0\).
In the equation \(x(x - 16) = 0\), you apply this property directly. This means that either \(x = 0\) or \(x - 16 = 0\).
In the equation \(x(x - 16) = 0\), you apply this property directly. This means that either \(x = 0\) or \(x - 16 = 0\).
- For \(x = 0\), the solution is immediate.
- For \(x - 16 = 0\), rearrange to find \(x = 16\).
Solving Quadratic Equations
Solving quadratic equations involves finding values of \(x\) that make the equation true. The manual steps include rewriting the equation in standard form, factoring, applying the Zero Product Property, and finally solving the resulting simple equations.
The conversion of the initial quadratic equation \(x^2 = 16x\) to \(x^2 - 16x = 0\) set the stage for solving. Once the quadratic was factored to \(x(x - 16) = 0\), solving became straightforward by using the Zero Product Property.
The conversion of the initial quadratic equation \(x^2 = 16x\) to \(x^2 - 16x = 0\) set the stage for solving. Once the quadratic was factored to \(x(x - 16) = 0\), solving became straightforward by using the Zero Product Property.
- Confirming that \(x = 0\) is a solution is as simple as substituting back into the original equation to check that it holds true.
- Similarly, for \(x = 16\), substitution verifies its correctness.
Other exercises in this chapter
Problem 48
Set up an equation and solve each problem. The difference between two whole numbers is 8 , and the difference between their reciprocals is \(\frac{1}{6}\). Find
View solution Problem 48
Use the quadratic formula to solve each of the quadratic equations. Check your solutions by using the sum and product relationships. $$-2 x^{2}+6 x-5=0$$
View solution Problem 48
Write each of the following in terms of \(i\), perform the indicated operations, and simplify. For example, $$ \begin{aligned} \sqrt{-3} \sqrt{-8} &=(i \sqrt{3}
View solution Problem 49
Solve each inequality. $$\frac{x-1}{x-5} \leq 2$$
View solution