Problem 48
Question
Express \(\tan (u+v+w)\) in terms of trigonometric functions of \(u, v\), and \(w\).
Step-by-Step Solution
Verified Answer
\(\tan(u+v+w) = \frac{\tan u + \tan v + \tan w - \tan u \tan v \tan w}{1 - \tan u \tan v - \tan v \tan w - \tan u \tan w}\)
1Step 1: Use the Identity for Two Angles
First, recall the identity for \( \tan(a + b) \): \[\tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b}\]We will utilize this identity to express \(\tan(u+v+w)\) in terms of \(\tan u\), \(\tan v\), and \(\tan w\) in stages.
2Step 2: Apply Identity to \(\tan(u+v)\)
Applying the identity to \(\tan(u+v)\), we get:\[\tan(u+v) = \frac{\tan u + \tan v}{1 - \tan u \tan v}\]This expression gives us the tangent of \(u+v\) in terms of \(\tan u\) and \(\tan v\).
3Step 3: Express \(\tan(u+v+w)\) Using \(\tan(u+v)\) and \(\tan w\)
Now, substitute \(\tan(u+v)\) and \(\tan w\) into the two-angle tangent identity:\[\tan(u+v+w) = \frac{\tan(u+v) + \tan w}{1 - \tan(u+v) \tan w}\]We already have \(\tan(u+v)\) from Step 2, so substitute that in:\[\tan(u+v+w) = \frac{\frac{\tan u + \tan v}{1 - \tan u \tan v} + \tan w}{1 - \left(\frac{\tan u + \tan v}{1 - \tan u \tan v}\right) \tan w}\]
4Step 4: Simplify the Expression
To simplify the expression for \(\tan(u+v+w)\), compute the numerator and the denominator separately:**Numerator**:\[(\tan u + \tan v + \tan w(1 - \tan u \tan v))\]**Denominator**:\[((1 - \tan u \tan v) - (\tan u + \tan v) \tan w)\]The expression for \(\tan(u+v+w)\) becomes:\[\tan(u+v+w) = \frac{\tan u + \tan v + \tan w - \tan u \tan v \tan w}{1 - \tan u \tan v - \tan v \tan w - \tan u \tan w}\]
5Step 5: Conclusion
We arrived at the expression for \(\tan(u+v+w)\) using the formula for the tangent of a sum of angles:\[\tan(u+v+w) = \frac{\tan u + \tan v + \tan w - \tan u \tan v \tan w}{1 - \tan u \tan v - \tan v \tan w - \tan u \tan w}\]
Key Concepts
Sum of Angles FormulaTangent FunctionAngle Addition Identity
Sum of Angles Formula
Trigonometric identities can be incredibly useful when we're dealing with complex angles.
One important concept is the "sum of angles formula." This formula helps us find the tangent or sine of a sum of two or three angles using the tangents or sines of individual angles.
As a reminder, the formula for the sum of two angles in terms of tangent is:
You first calculate the sum of two angles, then add the third one using the same concept. This method of gradually building with these identities helps break down complicated problems into simpler parts, making them easier to understand and solve.
One important concept is the "sum of angles formula." This formula helps us find the tangent or sine of a sum of two or three angles using the tangents or sines of individual angles.
As a reminder, the formula for the sum of two angles in terms of tangent is:
- \( \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \)
You first calculate the sum of two angles, then add the third one using the same concept. This method of gradually building with these identities helps break down complicated problems into simpler parts, making them easier to understand and solve.
Tangent Function
The tangent function is a crucial part of trigonometry and, along with sine and cosine, is a fundamental trigonometric function.
The tangent of an angle, often abbreviated as \( \tan \), represents the ratio between the sine and cosine of an angle:
In practical terms, tangent can describe angles in various scenarios, from simple triangle problems to complex wave functions.
For solving sums of angles, knowing that tangent relates to sine and cosine helps us utilize identities like the sum of angles formula effectively, as it allows us to connect different trigonometric properties seamlessly.
The tangent of an angle, often abbreviated as \( \tan \), represents the ratio between the sine and cosine of an angle:
- \( \tan \theta = \frac{\sin \theta}{\cos \theta} \)
In practical terms, tangent can describe angles in various scenarios, from simple triangle problems to complex wave functions.
For solving sums of angles, knowing that tangent relates to sine and cosine helps us utilize identities like the sum of angles formula effectively, as it allows us to connect different trigonometric properties seamlessly.
Angle Addition Identity
The angle addition identity is a powerful tool that allows us to combine angles in trigonometric expressions efficiently.
When dealing with tangent, the angle addition identity formula becomes instrumental:
It's especially useful in our exercise for simplifying expressions like \( \tan(u+v+w) \).
By applying this identity incrementally, first to \( u+v \) and then to add \( w \), we build up the solution progressively.
The angle addition identity is essential because it allows us to manage complex angles by breaking them into simpler, more manageable parts, helping us solve equations and understand geometric and wave relationships.
When dealing with tangent, the angle addition identity formula becomes instrumental:
- \( \tan(a + b) = \frac{\tan a + \tan b}{1 - \tan a \tan b} \)
It's especially useful in our exercise for simplifying expressions like \( \tan(u+v+w) \).
By applying this identity incrementally, first to \( u+v \) and then to add \( w \), we build up the solution progressively.
The angle addition identity is essential because it allows us to manage complex angles by breaking them into simpler, more manageable parts, helping us solve equations and understand geometric and wave relationships.
Other exercises in this chapter
Problem 48
Exer. 39-62: Find the solutions of the equation that are in the interval \([0,2 \pi\) ). $$ \sin x-\cos x=0 $$
View solution Problem 48
Exer. 1-50: Verify the identity. $$ \ln \sec \theta=-\ln \cos \theta $$
View solution Problem 49
Exer. 47-50: Solve the equation for \(x\) in terms of \(y\) if \(x\) is restricted to the given interval. $$ y=15-2 \cos x ; \quad[0, \pi] $$
View solution Problem 49
Exer. 39-62: Find the solutions of the equation that are in the interval \([0,2 \pi\) ). $$ \sin ^{2} \theta+\sin \theta-6=0 $$
View solution