Problem 47
Question
The area of a square is 14 square centimeters. What is the length of a side of the square?
Step-by-Step Solution
Verified Answer
The length of a side of the square is approximately 3.74 centimeters.
1Step 1: Understand the Area Formula
The formula for the area of a square is given by \( A = s^2 \), where \( s \) is the length of a side of the square.
2Step 2: Set Up the Equation
Set up the equation using the provided area. Since the area \( A \) is 14 square centimeters, the equation is \( 14 = s^2 \).
3Step 3: Solve for the Side Length
To find the side length \( s \), take the square root of both sides of the equation. Thus, \( s = \sqrt{14} \).
4Step 4: Approximate the Square Root
Using a calculator, evaluate \( \sqrt{14} \). The approximate value is \( 3.74 \) (rounded to two decimal places).
Key Concepts
Area of a SquareSolving Quadratic EquationsGeometry Formulas
Area of a Square
To understand how to find the side length when given the area of a square, it's essential to grasp the concept of area itself. The area measures the space inside a two-dimensional shape.
The specific formula for the area of a square is simple yet powerful:
The specific formula for the area of a square is simple yet powerful:
- \( A = s^2 \)
Solving Quadratic Equations
When working with the square's area formula, solving for a side length becomes a problem of solving a quadratic equation. A quadratic equation follows the form \( ax^2 + bx + c = 0 \). In geometric contexts like this exercise, it typically simplifies to \( s^2 = A \), where we'll solve for \( s \).
Here’s a quick process for solving such an equation:
Here’s a quick process for solving such an equation:
- Rearrange the equation to set the quadratic term on one side.
- Isolate \( s^2 \) (our squared variable).
- Take the square root of both sides to solve for \( s \).
Geometry Formulas
Geometry involves numerous formulas that describe and measure different shapes and their properties. Here are a few foundational formulas relevant to squares and similar problems:
- Perimeter of a square: \( P = 4s \)
- Diagonal of a square: \( d = s\sqrt{2} \)
Other exercises in this chapter
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