Problem 47
Question
Find the sign of the expression if the terminal point determined by \(t\) is in the given quadrant. \(\frac{\tan t \sin t}{\cot t}, \quad\) quadrant III
Step-by-Step Solution
Verified Answer
The expression is negative.
1Step 1: Understanding Quadrant III
In Quadrant III, both sine and tangent functions are negative. Cotangent, being the reciprocal of tangent, is also negative.
2Step 2: Expressing Trigonometric Functions
Express the given expression in terms of sine and cosine functions: \( \frac{\tan t \cdot \sin t}{\cot t} = \frac{\left(\frac{\sin t}{\cos t}\right) \cdot \sin t}{\frac{\cos t}{\sin t}} \). This simplifies to \( \frac{\sin^2 t}{\cos t} \cdot \frac{\sin t}{\cos t} \).
3Step 3: Simplifying the Expression
Now simplify: \( \frac{\sin^2 t \cdot \sin t}{\cos t \cdot \cos t} = \frac{\sin^3 t}{\cos^2 t} \).
4Step 4: Determining the Sign of the Expression
Since both \(\sin t\) and \(\cos t\) are negative in Quadrant III, \(\sin^3 t\) (the cube of a negative number) is negative, and \(\cos^2 t\) (the square of a negative number) is positive. Thus, the overall expression \( \frac{\sin^3 t}{\cos^2 t} \) is negative.
Key Concepts
Quadrant AnalysisTrigonometric IdentitiesExpression Simplification
Quadrant Analysis
When dealing with trigonometric functions, knowing the quadrant of the terminal point is essential to determine the sign of the expression. Each quadrant has specific characteristics:
- In Quadrant III, both sine (\(\sin t\)) and tangent (\(\tan t\)) are negative.
- Coscine (\(\cos t\)) is also negative because cosine is negative in Quadrants II and III.
- Cotangent (\(\cot t\)), being the reciprocal of \(\tan t\), remains negative.
Trigonometric Identities
Trigonometric identities are essential tools for transforming and simplifying expressions. In this exercise, we used these identities:
- The tangent function: \(\tan t = \frac{\sin t}{\cos t}\).
- The cotangent function: \(\cot t = \frac{\cos t}{\sin t}\).
Expression Simplification
Simplifying expressions involves reducing them to their simplest form while preserving equivalency. Let’s see this in action:First, express the given trigonometric expression:
- We rewrite \(\frac{\tan t \cdot \sin t}{\cot t}\) as \(\frac{\left(\frac{\sin t}{\cos t}\right) \cdot \sin t}{\frac{\cos t}{\sin t}}\).
- Multiply to get \(\frac{\sin^2 t}{\cos t} \cdot \frac{\sin t}{\cos t} = \frac{\sin^3 t}{\cos^2 t}\).
Other exercises in this chapter
Problem 46
Find (a) the reference number for each value of t, and (b) the terminal point determined by t. $$ t=\frac{17 \pi}{4} $$
View solution Problem 46
7–52 Find the period and graph the function. $$y=\frac{1}{2} \sec (2 \pi x-\pi)$$
View solution Problem 47
Find (a) the reference number for each value of t, and (b) the terminal point determined by t. $$ t=-\frac{11 \pi}{3} $$
View solution Problem 47
7–52 Find the period and graph the function. $$y=\tan \left(\frac{2}{3} x-\frac{\pi}{6}\right)$$
View solution