Problem 47
Question
(-7)+(-10)+(-13)+(-16)+\cdots+(-109) \quad-2030 \quad=
Step-by-Step Solution
Verified Answer
The result of the expression is -4060.
1Step 1: Recognize the Sequence
The sequence provided is arithmetic with a common difference. The sequence begins with -7, and each subsequent term decreases by 3, i.e., -7, -10, -13, and so on.The general form for the nth term (a_n) in an arithmetic sequence is given by: \[ a_n = a_1 + (n-1) imes d \]where:- \(a_1\) is the first term (-7 in this case),- \(d\) is the common difference (-3 in this case).
2Step 2: Determine the Number of Terms
We need to find how many terms there are until the last term -109. Using the formula for the nth term:\[ a_n = a_1 + (n-1) imes d \]Substitute the known values:\[ -109 = -7 + (n-1) imes (-3) \]Solve for \(n\):\[ -109 = -7 - 3(n-1) \]\[ -109 + 7 = -3(n-1) \]\[ -102 = -3(n-1) \]\[ 102 = 3(n-1) \]\[ 34 = n-1 \]\[ n = 35 \]Thus, there are 35 terms in the sequence.
3Step 3: Apply the Sum Formula for Arithmetic Sequences
The sum \( S_n \) of the first \( n \) terms of an arithmetic sequence can be calculated using the formula:\[ S_n = \frac{n}{2} \times (a_1 + a_n) \]Substituting the values we found:\[ S_{35} = \frac{35}{2} \times (-7 + (-109)) \]\[ S_{35} = \frac{35}{2} \times (-116) \]\[ S_{35} = 35 \times (-58) \]\[ S_{35} = -2030 \]
4Step 4: Solve for the Expression
The expression given was:\[ S_{35} - 2030 = 0 \]We found that \( S_{35} = -2030 \), thus:\[ -2030 - 2030 \]\[ = -4060 \]
Key Concepts
nth term formulacommon differencesum of arithmetic sequence
nth term formula
The nth term formula for an arithmetic sequence helps you find any term in the sequence without listing all the terms one by one. In an arithmetic sequence, each term increases or decreases by a constant amount, known as the common difference.
To determine the nth term, use the formula: \[ a_n = a_1 + (n-1) \times d \]
By setting up the equation \( -109 = -7 + (n-1) \times (-3) \) and solving, it becomes clear that \( n = 35 \) for the last term \( -109 \). You have successfully derived the position of the last term in the series.
To determine the nth term, use the formula: \[ a_n = a_1 + (n-1) \times d \]
- \( a_n \) is the nth term you want to find.
- \( a_1 \) is the first term in the sequence.
- \( n \) is the position of the term in the sequence.
- \( d \) represents the common difference.
By setting up the equation \( -109 = -7 + (n-1) \times (-3) \) and solving, it becomes clear that \( n = 35 \) for the last term \( -109 \). You have successfully derived the position of the last term in the series.
common difference
The common difference in an arithmetic sequence is what separates it from other sequences—it is the consistent amount that each term changes from one to the next.
Consider the sequence in the problem: \( -7, -10, -13, -16, ... \)
This sequence decreases by 3 each time you move from one term to the next.
Consider the sequence in the problem: \( -7, -10, -13, -16, ... \)
This sequence decreases by 3 each time you move from one term to the next.
- Start with any two consecutive terms, for example, \(-10 - (-7) = -3 \).
- This calculation shows that \(-3\) is the common difference, noted as \(d\).
sum of arithmetic sequence
The sum of an arithmetic sequence is the total you get when adding up all the terms in the sequence. This can be important for scenarios where you need the cumulative value of these numbers.
For an arithmetic sequence, you can find the sum of its first \( n \) terms with this formula:\[ S_n = \frac{n}{2} \times (a_1 + a_n) \] Here's a breakdown:
For an arithmetic sequence, you can find the sum of its first \( n \) terms with this formula:\[ S_n = \frac{n}{2} \times (a_1 + a_n) \] Here's a breakdown:
- \( S_n \) represents the sum of the first \( n \) terms.
- \( n \) is the total number of terms you're summing.
- \( a_1 \) is the first term in the series.
- \( a_n \) is the nth term or last term in your series.
Other exercises in this chapter
Problem 46
6+9+12+15+\cdots+93
View solution Problem 46
$$ (y-2)(a+1)=x \quad \text { for } y $$
View solution Problem 47
Solve each of Problems 47– 62 by setting up and solving an appropriate algebraic equation. Suppose that the length of a certain rectangle is \(2 \mathrm{me}-\)
View solution Problem 48
$$ (-5)+(-9)+(-13)+(-17)+\cdots+(-169) $$ \(-3654\)
View solution