Problem 46
Question
$$ (y-2)(a+1)=x \quad \text { for } y $$
Step-by-Step Solution
Verified Answer
\(y = \frac{x}{a+1} + 2\)
1Step 1: Identify the Equation
We are given the equation \((y-2)(a+1)=x\) and need to solve for \(y\), meaning \(y\) should be isolated on one side.
2Step 2: Divide by \((a+1)\)
To eliminate the \((a+1)\) term from the left side of the equation, divide both sides by \((a+1)\). This yields: \(y-2 = \frac{x}{a+1}\), given that \(a+1 eq 0\).
3Step 3: Solve for \(y\)
To isolate \(y\), add 2 to both sides of the equation: \(y = \frac{x}{a+1} + 2\).
4Step 4: Finalize the Solution
Ensure that all terms are simplified as much as possible. The expression for \(y\) is already in its simplest form: \(y = \frac{x}{a+1} + 2\).
Key Concepts
Understanding Algebraic ExpressionsEquation Manipulation TechniquesMastering Variable Isolation
Understanding Algebraic Expressions
Algebraic expressions form the building blocks of algebra, consisting of numbers, variables, and arithmetic operations. In the given problem, the expression
Algebraic expressions are modified following specific rules and operations. Their versatility allows us to describe various mathematical phenomena. To comprehend algebraic expressions, it's important to get comfortable with variables, symbols used to represent unknown or any number. They are essential for creating mathematical models and solving for unknowns in equations. Properly managing algebraic expressions means simplifying them and understanding how to perform operations on them, like addition, subtraction, multiplication, and division.
- \((y-2)(a+1)=x\)
Algebraic expressions are modified following specific rules and operations. Their versatility allows us to describe various mathematical phenomena. To comprehend algebraic expressions, it's important to get comfortable with variables, symbols used to represent unknown or any number. They are essential for creating mathematical models and solving for unknowns in equations. Properly managing algebraic expressions means simplifying them and understanding how to perform operations on them, like addition, subtraction, multiplication, and division.
Equation Manipulation Techniques
Manipulating an equation means performing operations to transform it into a more useful form. Each modification must maintain the equality between both sides.
To manipulate the given equation, \((y-2)(a+1)=x\), start by identifying your goal: isolating \(y\). Each modification hinges on this goal to maintain balance between each equation side and simplify the expression.
Key manipulation strategies include:
To manipulate the given equation, \((y-2)(a+1)=x\), start by identifying your goal: isolating \(y\). Each modification hinges on this goal to maintain balance between each equation side and simplify the expression.
Key manipulation strategies include:
- **Distributive Property**: Useful in expanding expressions and simplifying terms.
- **Factoring**: Can simplify complex expressions, providing more manageable forms.
- **Canceling**: Operations that simplify fractions or eliminate terms, as seen when dividing by \((a+1)\).
- **Balancing**: Consistently applying transformations on both sides, keeping the equality intact.
Mastering Variable Isolation
Variable isolation is the process of rearranging an equation to get a singular variable on one side. This allows you to determine the value or expression for that variable.
In our equation, \((y-2)(a+1)=x\), isolate \(y\) by systematically performing inverse operations. Begin by removing the multiplication factor, \((a+1)\), by dividing both sides by it, creating a simpler equation: \(y-2 = \frac{x}{a+1}\).
Finally, tackle any constants affecting \(y\). Here, adding 2 isolates \(y\), giving:
In our equation, \((y-2)(a+1)=x\), isolate \(y\) by systematically performing inverse operations. Begin by removing the multiplication factor, \((a+1)\), by dividing both sides by it, creating a simpler equation: \(y-2 = \frac{x}{a+1}\).
Finally, tackle any constants affecting \(y\). Here, adding 2 isolates \(y\), giving:
- \[ y = \frac{x}{a+1} + 2 \]
Other exercises in this chapter
Problem 45
$$ (y+1)(a-3)=x-2 \text { for } y $$
View solution Problem 46
6+9+12+15+\cdots+93
View solution Problem 47
(-7)+(-10)+(-13)+(-16)+\cdots+(-109) \quad-2030 \quad=
View solution Problem 47
Solve each of Problems 47– 62 by setting up and solving an appropriate algebraic equation. Suppose that the length of a certain rectangle is \(2 \mathrm{me}-\)
View solution