Problem 46
Question
When log \(y\) is graphed as a function of \(x, a\) straight line results. Graph straight lines, each given by two points, on a log-linear plot, and determine the functional relationship. (The original \(x-y\) coordinates are given.) $$ \left(x_{1}, y_{1}\right)=(1,4),\left(x_{2}, y_{2}\right)=(6,1) $$
Step-by-Step Solution
Verified Answer
The functional relationship is \(y = 4^{(\frac{6-x}{5})}\).
1Step 1: Understand the Context
The problem gives two points in the original coordinates \((x_1, y_1)=(1,4)\) and \((x_2, y_2)=(6,1)\). The problem states that when \(\log y\) is plotted against \(x\), the result is a straight line. This indicates a logarithmic relationship between \(x\) and \(y\).
2Step 2: Transform the Data
Convert the original \(y\)-values to their logarithms. The points become \((x_1, \log(y_1)) = (1, \log(4))\) and \((x_2, \log(y_2)) = (6, \log(1))\). Since \(\log(1) = 0\), the points are \((1, \log(4))\) and \((6, 0)\).
3Step 3: Calculate the Slope of the Line
Calculate the slope \(m\) of the straight line formed by the points on the log-linear plot. Use the formula for the slope: \[ m = \frac{\log(y_2) - \log(y_1)}{x_2 - x_1} = \frac{0 - \log(4)}{6 - 1} = \frac{-\log(4)}{5}. \]
4Step 4: Determine the Equation of the Line
Use the slope-point form of a line, \(y - y_1 = m(x - x_1)\), where \(y_1 = \log(4)\) and \(x_1 = 1\). Thus, \[ \log(y) - \log(4) = \frac{-\log(4)}{5}(x - 1). \]Simplifying gives the equation of the line: \[ \log(y) = -\frac{\log(4)}{5}x + \frac{6\log(4)}{5}. \]
5Step 5: Convert the Log Equation Back to Functional Form
By taking exponentials, convert \(\log(y) = -\frac{\log(4)}{5}x + \frac{6\log(4)}{5}\) back to \(y\). The result is:\[ y = 4^{(\frac{6-x}{5})}. \]
Key Concepts
Log-Linear PlotsSlope CalculationExponential Functions
Log-Linear Plots
In a log-linear plot, one axis represents the logarithm of the variable while the other remains in its natural scale. This type of graph is particularly useful when dealing with exponential functions, allowing us to transform complex exponential relationships into simplified linear ones. Transforming the data often involves taking the logarithm of one variable, such as plotting \( \log(y) \) against \( x \). This can reveal a straight line when there is an underlying exponential relationship between the variables.
For instance, if a dataset is believed to follow an exponential form of \( y = a \cdot b^x \), taking the logarithm base 10 or base e of \( y \) changes the relationship to \( \log(y) = \log(a) + x \cdot \log(b) \). This equation illustrates a linear form, with \( \log(a) \) as the intercept and \( \log(b) \) as the slope.
Converting exponential data to a linear form is beneficial because it simplifies the analysis process. By using a regression line to fit the transformed data, predictions and interpretations become more straightforward and intuitive.
For instance, if a dataset is believed to follow an exponential form of \( y = a \cdot b^x \), taking the logarithm base 10 or base e of \( y \) changes the relationship to \( \log(y) = \log(a) + x \cdot \log(b) \). This equation illustrates a linear form, with \( \log(a) \) as the intercept and \( \log(b) \) as the slope.
Converting exponential data to a linear form is beneficial because it simplifies the analysis process. By using a regression line to fit the transformed data, predictions and interpretations become more straightforward and intuitive.
Slope Calculation
The slope of a line in any form indicates how one variable changes in relation to another. In a log-linear plot, it reveals how the logarithm of one variable changes with respect to the other variable. This is a measure of the growth rate in the transformed function.
When calculating the slope \( m \) of a straight line connecting two points \( (x_1, \log(y_1)) \) and \( (x_2, \log(y_2)) \), use the formula:
\[ m = \frac{\log(y_2) - \log(y_1)}{x_2 - x_1} \]
This formula essentially reflects the rate of change in \( \log(y) \) per unit change in \( x \). For linear data on a log-linear plot, the slope can provide insights into the underlying exponential growth or decay pattern. If the slope is negative, it indicates decay, whereas a positive slope indicates growth.
Understanding and calculating the slope in log-linear contexts is crucial. It not only helps in formulating the relationship but also provides quantitative insights into how rapidly or slowly a function is changing.
When calculating the slope \( m \) of a straight line connecting two points \( (x_1, \log(y_1)) \) and \( (x_2, \log(y_2)) \), use the formula:
\[ m = \frac{\log(y_2) - \log(y_1)}{x_2 - x_1} \]
This formula essentially reflects the rate of change in \( \log(y) \) per unit change in \( x \). For linear data on a log-linear plot, the slope can provide insights into the underlying exponential growth or decay pattern. If the slope is negative, it indicates decay, whereas a positive slope indicates growth.
Understanding and calculating the slope in log-linear contexts is crucial. It not only helps in formulating the relationship but also provides quantitative insights into how rapidly or slowly a function is changing.
Exponential Functions
Exponential functions are characterized by their constant proportional rate of growth or decay. These functions frequently appear in various fields, from biology to finance, due to their nature of representing rapidly increasing or decreasing quantities.
An exponential function typically takes the form \( y = a \cdot b^x \), where \( a \) is the initial value and \( b \) is the base indicating the growth (if \( b > 1 \)) or decay (if \( 0 < b < 1 \)) factor. Their unique property is the constant ratio of the function's value at subsequent intervals.
Converting exponential functions into log-linear plots allows for easier interpretation. By taking the logarithm of both sides, the exponential equation transforms into a linear form \( \log(y) = \log(a) + x \cdot \log(b) \). This linear form can then be analyzed using linear regression to estimate the values of \( a \) and \( b \).
Understanding exponential functions is essential due to their widespread application. They provide invaluable insights into growth patterns and help predict future behavior in dynamic systems.
An exponential function typically takes the form \( y = a \cdot b^x \), where \( a \) is the initial value and \( b \) is the base indicating the growth (if \( b > 1 \)) or decay (if \( 0 < b < 1 \)) factor. Their unique property is the constant ratio of the function's value at subsequent intervals.
Converting exponential functions into log-linear plots allows for easier interpretation. By taking the logarithm of both sides, the exponential equation transforms into a linear form \( \log(y) = \log(a) + x \cdot \log(b) \). This linear form can then be analyzed using linear regression to estimate the values of \( a \) and \( b \).
Understanding exponential functions is essential due to their widespread application. They provide invaluable insights into growth patterns and help predict future behavior in dynamic systems.
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