Problem 45
Question
Assume that the distance a car travels is proportional to the time it takes to cover the distance. Find an equation that relates distance and time if it takes the car 15 min to travel \(10 \mathrm{mi}\). What is the constant of proportionality if distance is measured in miles and time is measured in hours?
Step-by-Step Solution
Verified Answer
The constant of proportionality is 40, and the equation relating distance and time is \( D = 40T \).
1Step 1: Understand the Proportional Relationship
The relationship between distance and time suggests that distance (D) is proportional to time (T), which can be expressed as: \[ D = kT \]where \( k \) is the constant of proportionality.
2Step 2: Convert Time to Appropriate Unit
Since the distance is given in miles and we need to find the constant of proportionality in terms of hours, convert 15 minutes to hours:\[ T = \frac{15}{60} = 0.25 \text{ hours} \]
3Step 3: Solve for the Proportionality Constant k
Using the distance \( D = 10 \text{ miles} \) and the time \( T = 0.25 \text{ hours} \), substitute these values into the equation:\[ 10 = k \times 0.25 \]Now, solve for \( k \):\[ k = \frac{10}{0.25} = 40 \]
4Step 4: Write the Equation Relating Distance and Time
With \( k = 40 \), the equation that relates distance and time is:\[ D = 40T \]
Key Concepts
Distance-Time RelationshipConstant of ProportionalityUnit Conversion
Distance-Time Relationship
A Distance-Time Relationship is a foundational concept in understanding how objects move. When we say that distance is proportional to time, we are expressing a simple yet powerful idea about movement. Imagine you are on a road trip. The farther you travel, the longer you have been driving. This direct relationship can be described with the equation:
- \( D = kT \) where:
- \( D \) is the distance traveled.
- \( T \) is the time spent traveling.
- \( k \) is the constant of proportionality.
Constant of Proportionality
The Constant of Proportionality is the magic number that ties two proportional quantities together. In our distance-time relationship, this constant tells us how fast something is moving. For example, if you know the car travels 10 miles in 15 minutes, you can calculate how many miles it covers per hour. Let's break this down:
- You start with the formula \( D = kT \).
- Given \( D = 10 \text{ miles} \) and \( T = 0.25 \text{ hours} \).
- To find \( k \), solve \( 10 = k \times 0.25 \).
- Dividing both sides by 0.25 gives \( k = 40 \).
Unit Conversion
Unit Conversion plays an essential role in solving many mathematical problems, including our exercise. For consistency, it's crucial to use compatible units across all parts of your calculations. Here, the exercise provides a conversion task:The car travels 10 miles in 15 minutes. However, to find the rate as a constant of proportionality, you need time expressed in hours, not minutes. Thus:
- Convert minutes to hours by dividing: \( 15 \text{ minutes} / 60 = 0.25 \text{ hours} \).
Other exercises in this chapter
Problem 44
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