Problem 44
Question
Find (a) the reference number for each value of t, and (b) the terminal point determined by t. $$ t=\frac{13 \pi}{6} $$
Step-by-Step Solution
Verified Answer
Reference number: \( \frac{\pi}{6} \), Terminal point: \( \left( \frac{\sqrt{3}}{2}, \frac{1}{2} \right) \).
1Step 1: Understand Reference Number
In trigonometry, the reference number is the acute angle that the given angle makes with the nearest x-axis. It is within the interval \( (0, \frac{\pi}{2}) \). To find this, first determine where the angle falls on the unit circle.
2Step 2: Find Equivalent Angle
Convert \( t = \frac{13\pi}{6} \) to an equivalent angle within \( [0, 2\pi) \) by subtracting \( 2\pi \), since \( \frac{13\pi}{6} > 2\pi \).\( \frac{13\pi}{6} - 2\pi = \frac{13\pi}{6} - \frac{12\pi}{6} = \frac{\pi}{6} \).
3Step 3: Determine the Reference Number
The given \( t = \frac{13\pi}{6} \) converts to \( \frac{\pi}{6} \), which itself is the reference number because it is already in the first quadrant and less than \( \frac{\pi}{2} \).
4Step 4: Identify Quadrant and Terminal Point
Since the angle \( \frac{\pi}{6} \) falls in the first quadrant, it does not need to be adjusted further. The terminal point for this angle corresponds to where it intersects the unit circle.
5Step 5: Calculate Terminal Point Coordinates
For an angle \( \frac{\pi}{6} \), the terminal point on the unit circle is calculated using the sine and cosine functions: \( \cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2} \) and \( \sin(\frac{\pi}{6}) = \frac{1}{2} \). Therefore, the terminal point is \( \left( \frac{\sqrt{3}}{2}, \frac{1}{2} \right) \).
Key Concepts
Reference NumberUnit CircleTerminal Point
Reference Number
When working with trigonometry, the concept of a reference number is crucial. A reference number is essentially an acute angle that your specific angle forms with the closest x-axis.
Since \( \frac{\pi}{6} \) already falls within the first quadrant, and is less than \( \frac{\pi}{2} \), it itself becomes the reference number. Understanding reference numbers can help in learning how angles behave and are analyzed within trigonometry.
- This angle is always between 0 and \( \frac{\pi}{2} \) (in radians).
- It helps to simplify problems by allowing the analysis of an angle as if it were smaller and less complex.
Since \( \frac{\pi}{6} \) already falls within the first quadrant, and is less than \( \frac{\pi}{2} \), it itself becomes the reference number. Understanding reference numbers can help in learning how angles behave and are analyzed within trigonometry.
Unit Circle
The unit circle is a fundamental concept in trigonometry.
On the unit circle, important trigonometric values are derived from angles corresponding to common fractions of degrees, such as \( \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3} \), etc. A significant advantage of using the unit circle is that, due to its radius of 1, the calculations become straightforward and systematic.
- It is a circle with a radius of 1, centered at the origin (0,0) of a coordinate plane.
- It is used to define trigonometric functions for all real numbers.
On the unit circle, important trigonometric values are derived from angles corresponding to common fractions of degrees, such as \( \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3} \), etc. A significant advantage of using the unit circle is that, due to its radius of 1, the calculations become straightforward and systematic.
Terminal Point
The terminal point is where the terminal side of an angle intersects the unit circle. To find this point,
This point gives us practical insight into the angle's position on the circle. It also allows us to determine the trigonometric values directly, facilitating the application of trigonometry in various problems.
- Determine the coordinates using trigonometric functions, specifically cosine for the x-coordinate and sine for the y-coordinate.
- For example, the terminal point of \( \frac{\pi}{6} \) on the unit circle involves the calculation: \( \cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2} \) and \( \sin(\frac{\pi}{6}) = \frac{1}{2} \).
This point gives us practical insight into the angle's position on the circle. It also allows us to determine the trigonometric values directly, facilitating the application of trigonometry in various problems.
Other exercises in this chapter
Problem 43
Find (a) the reference number for each value of t, and (b) the terminal point determined by t. $$ t=\frac{13 \pi}{4} $$
View solution Problem 43
7–52 Find the period and graph the function. $$y=2 \csc \left(\pi x-\frac{\pi}{3}\right)$$
View solution Problem 44
7–52 Find the period and graph the function. $$y=2 \sec \left(\frac{1}{2} x-\frac{\pi}{3}\right)$$
View solution Problem 45
Find the sign of the expression if the terminal point determined by \(t\) is in the given quadrant. \(\sin t \cos t, \quad\) quadrant II
View solution