Problem 43
Question
Solve the given differential equation. $$ \left(4+e^{2 x}\right) \frac{d y}{d x}=y e^{x} $$
Step-by-Step Solution
Verified Answer
The solution to the differential equation is \( y = C \sqrt{4 + e^{2x}} \).
1Step 1: Separate variables
The given differential equation is \( (4+e^{2x}) \frac{dy}{dx} = y e^x \). First, separate the variables \( y \) and \( x \) by rewriting it as \( \frac{dy}{y} = \frac{e^x}{4+e^{2x}} \, dx \).
2Step 2: Integrate both sides
Integrate both sides of the equation separately. This gives \( \int \frac{dy}{y} = \int \frac{e^x}{4+e^{2x}} \, dx \). The left side integrates to \( \ln |y| \).
3Step 3: Simplify the right side integral
To integrate the right side, use substitution. Let \( u = 4+e^{2x} \), then \( du = 2e^{2x} \, dx \) or \( e^x \, dx = \frac{du}{2e^x} \). Rewrite \( e^x \) as \( \sqrt{u-4} \), making the integral \( \frac{1}{2} \int \frac{1}{u} \, du \).
4Step 4: Complete the integration
The integral \( \frac{1}{2} \int \frac{1}{u} \, du \) yields \( \frac{1}{2} \ln |u| + C \). Substituting back for \( u \), we get \( \frac{1}{2} \ln |4 + e^{2x}| + C \).
5Step 5: Solve for \( y \)
Equating both integrals gives \( \ln |y| = \frac{1}{2} \ln |4 + e^{2x}| + C \). Solve for \( y \) by exponentiating both sides to get \( |y| = e^C \sqrt{4 + e^{2x}} \). Thus, \( y = Ce^{1}\sqrt{4 + e^{2x}} \) where \( C = e^C \) is a constant.
Key Concepts
Variable SeparationIntegration TechniquesSubstitution Method
Variable Separation
Variable separation is a common technique used to solve differential equations. It involves rearranging the equation to isolate variables on opposite sides, enabling easier integration. In our problem, this technique allows us to rewrite the equation so the variables are neatly separated:
Remember, the core goal is isolating derivatives and corresponding variables on either side wherever possible, leading to functions that you can handle individually.
- The original equation is: \[ \left(4+e^{2x}\right) \frac{d y}{d x} = y e^{x} \]
- By separating variables, we get: \[ \frac{dy}{y} = \frac{e^x}{4+e^{2x}} \, dx \]
Remember, the core goal is isolating derivatives and corresponding variables on either side wherever possible, leading to functions that you can handle individually.
Integration Techniques
Integration plays a fundamental role in solving differential equations after variable separation. Here, we must integrate both sides of the separated equation:
These techniques expand our toolkit, making it easier to solve a wider range of problems, especially in cases where simple integration formulations don’t work. By working through each component carefully, you ensure a correct and elegant solution.
- The left side becomes:\[ \int \frac{dy}{y} = \ln |y| + C \]
- For the right side, it involves more complex handling, resulting in:\[ \int \frac{e^x}{4+e^{2x}} \, dx \]
These techniques expand our toolkit, making it easier to solve a wider range of problems, especially in cases where simple integration formulations don’t work. By working through each component carefully, you ensure a correct and elegant solution.
Substitution Method
The substitution method is vital in solving integrals that are complex or involve non-standard functions. In our problem, the integral \( \int \frac{e^x}{4+e^{2x}} \, dx \) is not straightforward and needs substitution to simplify. Here's how substitution is applied:
The substitution method is a critical strategy, especially in complex integrals where standard techniques would be difficult or impossible to use directly. It transforms the problem into one that is manageable, demonstrating how mathematical insight can simplify complicated expressions.
- First, we choose a substitution: let \( u = 4 + e^{2x} \)
- This means, \( du = 2e^{2x} \, dx \), rearranging gives \( e^x \, dx = \frac{du}{2e^x} \)
- Rewriting the integral, it becomes:\[ \frac{1}{2} \int \frac{1}{u} \, du \]
The substitution method is a critical strategy, especially in complex integrals where standard techniques would be difficult or impossible to use directly. It transforms the problem into one that is manageable, demonstrating how mathematical insight can simplify complicated expressions.
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