Problem 43
Question
Solve each equation. Let \(f(x)=\sqrt[4]{3 x+1}\). For what value(s) of \(x\) is \(f(x)=4 ?\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 85\).
1Step 1: Set up the equation
We start by setting up the equation given in the problem: \(f(x) = \sqrt[4]{3x + 1} = 4\). We need to solve for \(x\).
2Step 2: Remove the fourth root
To eliminate the fourth root, raise both sides of the equation to the fourth power: \((\sqrt[4]{3x + 1})^4 = 4^4\), which simplifies to \(3x + 1 = 256\).
3Step 3: Solve for x
Subtract 1 from both sides to isolate the term with \(x\): \(3x = 256 - 1\), which simplifies to \(3x = 255\).
4Step 4: Divide to find x
Divide both sides by 3 to solve for \(x\): \(x = \frac{255}{3}\), which simplifies to \(x = 85\).
Key Concepts
Fourth RootsAlgebraic FunctionsIsolation of Variables
Fourth Roots
When we talk about a fourth root, we refer to a mathematical operation in which you want to determine what number, when raised to the fourth power, would give you a certain value. Mathematically, the fourth root of a number \( a \) is the number \( b \) such that \( b^4 = a \). This is similar to finding a square root, but instead of dividing the exponent into pairs, you divide it into fours. Fourth roots are a form of radical expression. They provide a way to reverse the process of raising a number to the power of 4. Just like square roots allow us to find the base \( b \) when we know \( b^2 \), fourth roots help us find the base when we know \( b^4 \).
- Common notation for fourth root is \( \sqrt[4]{a} \).
- Finding the fourth root can be crucial in solving equations that contain power terms.
Algebraic Functions
An algebraic function is a function that involves only algebraic operations such as addition, subtraction, multiplication, division, and taking roots. In our exercise, the function \( f(x) = \sqrt[4]{3x + 1} \) is an algebraic function, since it involves taking the fourth root of a linear expression.Algebraic functions can often be manipulated and solved through basic algebraic procedures:
- The function's form allows us to apply operations that help with finding unknown variables.
- These functions are central to a wide variety of mathematical solutions.
Isolation of Variables
Isolation of variables is a fundamental concept in solving equations. It involves rearranging an equation so that the unknown variable is by itself on one side of the equation. This tends to make finding the value of the variable much simpler.In our specific example of solving the equation for \( x \), we began with \( (3x + 1) \), a part of the expression within the fourth root. By eliminating the root and systematically using algebraic operations, we were able to isolate \( x \):
- Subtract 1 from both sides to simplify the equation.
- Divide both sides by the coefficient of \( x \) to completely isolate \( x \).
Other exercises in this chapter
Problem 43
Simplify each expression. Assume that all variables are unrestricted and use absolute value symbols when necessary. See Example 2. $$ \sqrt{36 s^{6}} $$
View solution Problem 43
Simplify each radical expression. All variables represent positive real numbers. $$ \sqrt{\frac{z^{2}}{16 x^{2}}} $$
View solution Problem 44
Square or cube each quantity and simplify the result. $$ (\sqrt{11})^{2} $$
View solution Problem 44
Find the exact distance between each pair of points. \((0,0),(-12,16)\)
View solution