Problem 43
Question
Simplify each radical expression. All variables represent positive real numbers. $$ \sqrt{\frac{z^{2}}{16 x^{2}}} $$
Step-by-Step Solution
Verified Answer
\( \frac{z}{4x} \)
1Step 1: Apply the Radical to the Fraction
We start by applying the radical (square root) to both the numerator and the denominator of the expression separately: \[ \sqrt{\frac{z^2}{16x^2}} = \frac{\sqrt{z^2}}{\sqrt{16x^2}}. \]
2Step 2: Simplify the Square Root in the Numerator
Simplify \( \sqrt{z^2} \). Since \( z \) is positive, \( \sqrt{z^2} = z \). So, the expression now looks like: \[ \frac{z}{\sqrt{16x^2}}. \]
3Step 3: Simplify the Square Root in the Denominator
Now, simplify \( \sqrt{16x^2} \). Since \( x \) is positive, \( \sqrt{16x^2} \) becomes \( 4x \) because \( \sqrt{16} = 4 \) and \( \sqrt{x^2} = x \). Thus, the expression is now \[ \frac{z}{4x}. \]
4Step 4: Verify the Simplification
Check the simplified expression to ensure it is accurate: \[ \frac{z}{4x}. \] Both square roots have been correctly simplified, validating the expression.
Key Concepts
Simplifying RadicalsSquare RootAlgebraic Fractions
Simplifying Radicals
Understanding how to simplify radicals can make complex mathematical expressions more manageable. When you're simplifying radical expressions, you're essentially finding the simplest form of the root. This process often involves separating the numbers under the root sign and simplifying them step by step.
For instance, when you see a radical like \( \sqrt{\frac{z^2}{16x^2}} \), you're tasked with making this as straightforward as possible. You apply the square root to the numerator and the denominator separately. This turns the expression into \( \frac{\sqrt{z^2}}{\sqrt{16x^2}} \). From there, it's a matter of simplifying each part.
For instance, when you see a radical like \( \sqrt{\frac{z^2}{16x^2}} \), you're tasked with making this as straightforward as possible. You apply the square root to the numerator and the denominator separately. This turns the expression into \( \frac{\sqrt{z^2}}{\sqrt{16x^2}} \). From there, it's a matter of simplifying each part.
- Look for perfect squares: If a part under the square root is a perfect square, simplify it to its root.
- Apply root properties: For variables, use the properties of exponents. \( \sqrt{z^2} \) becomes \( z \) because squaring and square rooting are opposite operations.
- Maintain positivity: Remember that variables represent positive real numbers, ensuring that each simplification remains valid.
Square Root
The square root of a number (\( \sqrt{x} \)) is a value that, when multiplied by itself, gives the original number \( x \). This is fundamental when dealing with expressions like the one in our example.
Let's zoom into how we handle square roots in different scenarios:
Let's zoom into how we handle square roots in different scenarios:
- Perfect Square: If the number is a perfect square, the square root is an integer. For example, \( \sqrt{16} = 4 \), as seen in simplifying \( \sqrt{16x^2} \).
- Variables with even exponents: When dealing with algebraic expressions like \( \sqrt{z^2} \), try to transform these to the variable itself. Here, \( \sqrt{z^2} = z \), assuming \( z \) is positive.
- Multiple terms: When square rooting an expression that includes variables, apply the square root to each part separately. \( \sqrt{16x^2} \) becomes \( 4x \), deconstructing into \( \sqrt{16} \times \sqrt{x^2} \).
Algebraic Fractions
An algebraic fraction is essentially a fraction where the numerator, the denominator, or both, contain algebraic expressions. Simplifying them involves understanding both the arithmetic and algebra involved.
When confronted with fractions under a square root, as in \( \sqrt{\frac{z^2}{16x^2}} \), treat the numerator and denominator separately. It simplifies the process of applying the square root.
When confronted with fractions under a square root, as in \( \sqrt{\frac{z^2}{16x^2}} \), treat the numerator and denominator separately. It simplifies the process of applying the square root.
- Separate the components: Write the fraction as the square roots of the numerator and the denominator independently, \( \frac{\sqrt{z^2}}{\sqrt{16x^2}} \).
- Simplify each part: Discover where you can reduce complexity. \( \sqrt{z^2} \) simplifies to \( z \), and \( \sqrt{16x^2} \) simplifies to \( 4x \).
- Check your work: Always make sure that the resulting fraction is in its simplest form. For this problem, it reduced neatly to \( \frac{z}{4x} \).
Other exercises in this chapter
Problem 43
Perform the operations. Write all answers in the form \(a+b i .\) See Example 3 $$ (8+\sqrt{-25})-(7+\sqrt{-4}) $$
View solution Problem 43
Simplify each expression. Assume that all variables are unrestricted and use absolute value symbols when necessary. See Example 2. $$ \sqrt{36 s^{6}} $$
View solution Problem 43
Solve each equation. Let \(f(x)=\sqrt[4]{3 x+1}\). For what value(s) of \(x\) is \(f(x)=4 ?\)
View solution Problem 44
Square or cube each quantity and simplify the result. $$ (\sqrt{11})^{2} $$
View solution