Problem 43
Question
Match the real-life problem with an equation. Then solve the problem. A. \(x+15=7\) B. \(15-x=7\) C. \(15+7=x\) D. \(x+15=-7\) There are 15 members of a high school band brass section. After graduation there are only 7 members. How many members graduated?
Step-by-Step Solution
Verified Answer
8 members graduated from the high school band.
1Step 1: Match the situation with an equation
The situation describes the number of members decreasing from 15 to 7 due to graduation. This reflects a subtraction operation, so the equation should involve subtraction. Out of the presented options, B. \(15-x=7\) matches the real-life problem.
2Step 2: Solve the matching equation
To find the number of members graduated, solve equation B. \(15-x=7\) for \(x.\) The solution is obtained by subtracting 7 from both sides of the equation. In other words, \(x\) equals \(15 - 7\).
3Step 3: Calculate the value of x
By performing the subtraction operation, it is found that \(x = 15 - 7 = 8\). So, 8 members graduated from the high school band.
Key Concepts
subtractionreal-life problemhigh school mathematics
subtraction
Subtraction is one of the fundamental operations in mathematics. It involves taking one number away from another. In our equation solving example, the number of members in the band decreased from 15 to 7, signifying a subtraction process. This can be thought of as asking, "How many need to be removed to reach a certain amount?"Subtraction in equations:
- Typically presented as: "A - B = C," where you need to find one of the numbers.
- It is an essential skill for high school math, aiding in solving many real-life problems.
real-life problem
Solving real-life problems using equations is a powerful application of mathematics. In real-life settings, chemistry, finance, and even music can present situations where math is needed. Our high school band scenario is a perfect example.In this situation:
- We had a starting count of 15 band members.
- After graduation, only 7 remained.
- We wanted to determine how many members graduated.
high school mathematics
High school mathematics lays the foundation for solving both theoretical and practical problems. Understanding equations like the one in the exercise bridges academic concepts with real-world applications. This exercise serves as a typical high school-level problem requiring students to engage critically with mathematical concepts.
Educational importance of this exercise:
- It teaches students to translate word problems into mathematical equations.
- Involves logic and deduction to correctly select the form of the equation.
- Reinforces basic concepts such as subtraction within an algebraic context.
Other exercises in this chapter
Problem 42
Solve the equation. $$-\frac{2}{3} t=-16$$
View solution Problem 43
Describe the errors. $$ \begin{aligned} 2(4 b-3) &=8 b-6 \\ 8 b-6 &=8 b-6 \\ -6 &=-6 \\ b &=-6 \end{aligned} $$
View solution Problem 43
Multiply the equation by a power of 10 to write an equivalent equation with integer coefficients. $$ 4.5 n-0.375=0.75 n+2.0 $$
View solution Problem 43
Solve the equation. $$\frac{3}{4} z=-5 \frac{1}{2}$$
View solution